Rajasthan Boardहिन्दी माध्यमकक्षा 12 साइन्सगणितसमाकलन2 Marks
Question
हल कीजिए : $\int \cos ^{-1}(\sin x) d x$
✓
Answer
$I =\int \cos ^{-1}(\sin x) d x$ $\quad$$=\int \cos ^{-1}\left[\cos \left(\frac{\pi}{2}-x\right)\right] d x$ $\quad$$=\int\left(\frac{\pi}{2}-x\right) d x=\frac{\pi}{2} \int d x-\int x d x$ $\quad$$=\frac{\pi}{2} x-\frac{x^2}{2}+ C$
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