If a potential difference of 10V causes a current of 2A to flow for 1 minute, how much energy is transferred?
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Given: p.d. = 10V, I = 2amp, t = 1 min = 60s.
We know that:
$\text{I} = \frac{\text{Q}}{\text{T}}$
Thus, Q = I × t.
Q = × 60.
Q = 120C.
Work done = p.d. × charge moved
Work done = 120 × 10J
Work done = 1200J.
We know that:
$\text{I} = \frac{\text{Q}}{\text{T}}$
Thus, Q = I × t.
Q = × 60.
Q = 120C.
Work done = p.d. × charge moved
Work done = 120 × 10J
Work done = 1200J.
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