If $\gamma = 2.5$ and volume is equal to $\frac{1}{8}$ times to the initial volume then pressure $P' $ is equal to (Initial pressure $= P$)
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(c)$\frac{{{P_2}}}{{{P_1}}} = {\left( {\frac{{{V_1}}}{{{V_2}}}} \right)^\gamma } \Rightarrow \frac{{P'}}{P} = {(8)^{5/2}} \Rightarrow P' = P \times {(2)^{15/2}}$
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