In the following P-V diagram two adiabatics cut two isothermals at temperatures T_1 and T_2 (fig.). The value of frac{{{V_a}}}{{{V

Q: In the following $P-V$ diagram two adiabatics cut two isothermals at temperatures $T_1$ and $T_2$ (fig.). The value of $\frac{{{V_a}}}{{{V_d}}}$ will be

a (a) For adiabatic process ${T_1}V_b^{\gamma - 1}$= Constant For $bc$ curve ${T_1}V_b^{\gamma - 1} = {T_2}V_c^{\gamma - 1}$ or $\frac{{{T_2}}}{{{T_1}}} = {\left( {\frac{{{V_b}}}{{{V_c}}}} \right)^{\gamma - 1}}$…..$(i)$ For $ad$ curve ${T_1}V_a^{\gamma - 1} = {T_2}V_d^{\gamma - 1}$ or $\frac{{{T_2}}}{{{T_1}}} = {\left( {\frac{{{V_a}}}{{{V_d}}}} \right)^{\gamma - 1}}$…..$(ii)$ From equation $(i)$ and $(ii)$ $\frac{{{V_b}}}{{{V_c}}} = \frac{{{V_a}}}{{{V_d}}}$

SECTION - A [PHYSICS - MCQ]

GSEB - English Medium

In the following $P-V$ diagram two adiabatics cut two isothermals at temperatures $T_1$ and $T_2$ (fig.). The value of $\frac{{{V_a}}}{{{V_d}}}$ will be

A$\frac{{{V_b}}}{{{V_c}}}$
B$\frac{{{V_c}}}{{{V_b}}}$
C$\frac{{{V_d}}}{{{V_a}}}$
D${V_b}{V_c}$

Medium

STD 11 Science
NEET
STD 11 - 11. thermodynamics
Physics

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