\(\therefore \,\,\frac{{{k}_{2}}}{{{k}_{1}}}=\frac{{{e}^{-Ea/R{{T}_{1}}}}}{{{e}^{-Ea/R{{T}_{2}}}}}\)
\(={{e}^{Ea/R{{T}_{2}}-Ea/R{{T}_{1}}}}\)
\(={{e}^{\frac{{{E}_{a}}}{R}\left( \frac{1}{{{t}_{2}}}-\frac{1}{{{t}_{1}}} \right)}}\)
\(={{e}^{\frac{{{E}_{a}}}{R}\left( \frac{{{T}_{2}}-{{T}_{1}}}{{{T}_{1}}{{T}_{2}}} \right)}}\)
\(\,\therefore \,\,\,\log \,\,\frac{{{E_a}}}{{2.303\,R}}\,\,\left( {\frac{{{T_2} - {T_1}}}{{{T_1}{T_2}}}} \right)\)
$[$આપેલ છે :${R}=8.31\, {~J} \,{~K}^{-1} \,{~mol}^{-1} ; \log 6.36 \times 10^{-3}=-2.19$ $\left.10^{-4.79}=1.62 \times 10^{-5}\right]$
$A\,\xrightarrow{{{K_1}}}\,B,$ સક્રિયકરણ ઊર્જા ; $Ea_1$
$A\,\xrightarrow{{{K_2}}}\,C,$ સક્રિયકરણ ઊર્જા $Ea_2$