\(\therefore \mathrm{V}_{\mathrm{I} / \mathrm{m}}=-\mathrm{m}^{2} \mathrm{~V}_{\mathrm{O} / \mathrm{m}}\)
Given,
\(\mathrm{V}_{\mathrm{O} / \mathrm{m}}=40 \mathrm{~m} / \mathrm{s}\)
\(\mathrm{m}=\frac{\mathrm{f}}{\mathrm{f}-\mathrm{u}}=\frac{10}{10+190}=\frac{10}{200}\)
\(\therefore \mathrm{V}_{\mathrm{L} / \mathrm{m}}=-\frac{1}{400} \times 40=-0.1 \mathrm{~m} / \mathrm{s}\)
\(\therefore\) Car will appear to move with speed \(0.1 \mathrm{~m} / \mathrm{s}\).