\(\frac{1240\, \mathrm{eV}}{\lambda}=\frac{15}{16} \times 9 \times 13.6\, \mathrm{eV}\)
\(\lambda=\frac{1240 \times 16}{15 \times 9 \times 13.6}=10.8\, \mathrm{nm}\)
[Rhc=13.6 eV, $\mathrm{hc}=1242 \mathrm{eV} \mathrm{nm}, \mathrm{h}=6.6 \times 10^{-34} \mathrm{J-s}$ અને હાઈડ્રોજન પરમાણુનું દળ $\sim 1.6 \times 10^{-27} \mathrm{~kg}$ લો.]