(Image)
\((B)\) magnetic field due to a current carrying wire for \(\mathrm{x}<\mathrm{a}\) :
\(\mathrm{B}=\frac{\mu_0 \mathrm{ir}}{2 \pi \mathrm{a}^2}\)
(Image)
\((C)\) magnetic field due to a current carrying wire for \(x>a\) :
\(B=\frac{\mu_0 i}{2 \pi a}\)
(Image)
\((D)\) magnetic field inside solenoid varies as: