Pressure versus temperature graph of an ideal gas is as shown in figure. Density of the gas at point $A$ is ${\rho _0}$. Density at point $B$ will be
Medium
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$\rho=\frac{P M}{R T}$ or $\rho \propto \frac{P}{T}$
$\left(\frac{P}{T}\right)_{A}=\frac{P_{0}}{T_{0}}$ and $\left(\frac{P}{T}\right)_{B}$
$=\frac{3}{2}\left(\frac{P_{0}}{T_{0}}\right)\left(\frac{P}{T}\right)_{B}=\frac{3}{2}\left(\frac{P}{T}\right)_{A}$
$\therefore \quad \rho_{B}=\frac{3}{2} \rho_{A}=\frac{3}{2} \rho_{0}$
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