$a=100$, $x=90$, $t=10$
તો ${{K}_{1}}=\frac{2.303}{10}\log \frac{100}{10}$ $K=2.303\times {{10}^{-1}}\,hou{{r}^{-1}}$
હવે, $ 99.9\%$ પૂર્ણ થવા માટે
$a= 100$ અને $x =99.9$
$t=\frac{2.303}{{{K}_{1}}}\log \frac{100}{0.1}$ $=\frac{2.303}{2.303\times {{10}^{-1}}}\times 3=30$ કલાક
${\log _{10}}\,\left[ { - \frac{{d\left[ A \right]}}{{dt}}} \right] = {\log _{10}}\,\left[ {\frac{{d\left[ B \right]}}{{dt}}} \right] + 0.3010$