\(\because\) Volume \(=\) constant

i.e., \(\frac{4}{3} \pi R^3=n \times \frac{4}{3} \pi r^3\)

Radius of each new droplet \(=\frac{R}{n^{1 / 3}}\)

Work done to break into ' \(n\) ' drops \(=S\left[n \times 4 \pi r^2-4 \pi R^3\right]\)

\(=S \times 4 \pi R^2\left[n^{1 / 3}-1\right]\)