\(A \rightarrow\) Product ;
given \(t_{1 / 2}=1\,hr\)
for a zero order reaction
\(t_{\text {completion}}=\frac{\left[A_{0}\right]}{k}=\frac{\text {initial} \,\operatorname{conc}}{rate\, {\text{on}}\,{\text{ stant}}}\)
\(\therefore \) \(t_{1 / 2}=\frac{\left[A_{0}\right]}{2 K}\)
or \( k=\frac{\left|A_{0}\right|}{2 t_{1 / 2}}=\frac{2}{2 \times 1}=1\,mol\,lit\) \(^{-1}\, h r^{-1}\)
Further for a zero order reaction
\(k=\frac{d x}{d t}=\frac{\text { change in concentration }}{\text {time}}\)
\(I=\frac{0.50-0.25}{time}\)
\(\therefore \) time \(=0.25\, h r\)
(આપેલ : $\ln 10=2.303\,\log 2=0.3010$ )
$1$. $[A]$ $0.012$, $[B]$ $0.0351\rightarrow $ પ્રારંભિક દર $ = 0.10$
$2$. $[A]$ $0.024$, $[B]$ $0.070\rightarrow $ પ્રારંભિક દર $= 1.6$
$3$. $[A]$ $0.024$, $[B]$ $0.035\rightarrow $ પ્રારંભિક દર $ = 0.20$
$4$. $[A]$ $0.012$ , $[B]$ $0.070\rightarrow $ પ્રારંભિક દર $ = 0.80$
(આપેલ છે: $\left. R =8.314\, J\, mol ^{-1} K ^{-1}\right)$