Question
समीकरण $a({x^2} + 1) - ({a^2} + 1)x = 0$ के मूल हैं
==>$a{x^2} - ({a^2} + 1)x + a = 0$
==>$(ax - 1)(x - a) = 0$
==> $x = a,\frac{1}{a}$.
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