b
(b) $V{P^3}$= constant = $k$ ==> $P = \frac{k}{{{V^{1/3}}}}$
Also$PV = \mu RT$==>$\frac{k}{{{V^{1/3}}}}.V = \mu RT$==> ${V^{2/3}} = \frac{{\mu RT}}{k}$
Hence ${\left( {\frac{{{V_1}}}{{{V_2}}}} \right)^{2/3}} = \frac{{{T_1}}}{{{T_2}}}$==> ${\left( {\frac{V}{{27V}}} \right)^{2/3}} = \frac{T}{{{T_2}}}$==> ${T_2} = 9\,T$