The average dipole moment of $Fe$ atoms is $1.8 × 10^{-23}\ A-m^2$ . The magnetic moment of an iron rod of length $10\ cm$ and diameter $1\,cm$ is........$A-m^2$ : (density and at. wt. of $Fe$ are $7.87\ g/cm^3$ and   $55.87$ )
  • A$3$
  • B$4$
  • C$6$
  • D$12$
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