The following arrangement consists of five identical metal plates parallel to each other. Area of each plate is $A$ and separation between the successive plates is $d$. The capacitance between $P$ and $Q$ is
A$\frac{5 \varepsilon_0 A}{d}$
B$\frac{7}{3} \varepsilon_0 \frac{A}{d}$
C$\frac{4}{3} \frac{\varepsilon_0 A}{d}$
D$\frac{5}{3} \frac{\varepsilon_0 A}{d}$
Medium
Download our app for free and get started
D$\frac{5}{3} \frac{\varepsilon_0 A}{d}$
d (d)
$C_{\text {net }}=\frac{5 C}{3}$
Download our app
and get started for free
Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*
A parallel plate capacitor is connected to a battery. The plates are pulled apart with a uniform speed. If $x$ is the separation between the plates, the time rate of change of electrostatic energy of capacitor is proportional to
$125$ identical drops each charged to the same potential of $50\;volts$ are combined to form a single drop. The potential of the new drop will be......$V$
Three capacitors are connected to $D.C.$ source of $100\;volts$ shown in the adjoining figure. If the charge accumulated on plates of ${C_1},\;{C_2}$ and ${C_3}$ are ${q_a},\;{q_b},\;{q_c},{q_d}.{q_e}$ and ${q_f}$ respectively, then
An electric field of $1000\,V/m$ is applied to an electric dipole at angle of $45^o$. The value of electric dipole moment is $10^{-29}\, C.m.$ What is the potential energy of the electric dipole?