c $C_{Isothermal} = \infty $ and $C_{adibatic} =0$
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Under an adiabatic process, the volume of an ideal gas gets doubled. Consequently the mean collision time between the gas molecule changes from $\tau_{1}$ to $\tau_{2} .$ If $\frac{C_{p}}{C_{v}}=\gamma$ for this gas then a good estimate for $\frac{\tau_{2}}{\tau_{1}}$ is given by :
A flask contains Hydrogen and Argon in the ratio $2: 1$ by mass. The temperature of the mixture is $30^{\circ} C$. The ratio of average kinetic energy per molecule of the two gases ( $K$ argon/ $K$ hydrogen) is: (Given: Atomic Weight of $Ar = 39.9$)
An object is placed in a medium of refractive index $3$. An electromagnetic wave of intensity $6 \times 10^8 \mathrm{~W} / \mathrm{m}^2$ falls normally on the object and it is absorbed completely. The radiation pressure on the object would be (speed of light in free space $=3 \times 10^8 \mathrm{~m} / \mathrm{s}$ ):
For two different gases $X$ and $Y,$ having degrees of freedom $f_1$ and $f_2$ and molar heat capacities at constant volume $C_{v_1}$ and $C_{v_2}$ respectively, for adiabatic process , the $\ln P$ versus $\ln V$ graph is plotted as shown :-
A mole of an ideal diatomic gas undergoes a transition from $A$ to $B$ along a path $AB$ as shown in the figure, The change in internal energy of the gas during the transition is ...... $kJ$