Three capacitors each of capacitance $C$ and of breakdown voltage $V$ are joined in series. The capacitance and breakdown voltage of the combination will be
AIPMT 2009, Easy
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Three capacitors of capacitance $C$ each are in series
$\therefore$ Total capacitance, $C_{\text {total }}=C / 3$
The charge is the same, $Q,$ when capacitors are in series.
$V_{\text {total }}=\frac{Q}{C}=\frac{Q}{C / 3}=3 V$
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