Three capacitors of capacitance $3\,\mu \,F$ are connected in a circuit. Then their maximum and minimum capacitances will be
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(a) ${C_{\max }} = nC = 3 \times 3 = 9\,\mu F$, ${C_{\min }} = \frac{C}{n} = \frac{3}{3} = 1\,\mu F$
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