where $K_1 = 2K and K_2 = 3K$ $\left( {\because \,\frac{{{K_1}}}{{{K_2}}} = \frac{2}{3}} \right)$
==> $\theta = $$\frac{{2K \times 100 + 3K \times 0}}{{2K + 3K}}$$ = \frac{{200K}}{{5K}} = 40^\circ C$
($A$) The temperature distribution over the filament is uniform
($B$) The resistance over small sections of the filament decreases with time
($C$) The filament emits more light at higher band of frequencies before it breaks up
($D$) The filament consumes less electrical power towards the end of the life of the bulb
