d
Work done is equal to area under the P-V graph, thus work done by gas is greater for isothermal process.
For isothermal process: $T_2=T_0$
For adibatic process: $T_0\left(V_0\right)^{\gamma-1}=T(V)^{\gamma-1}$
As $V > V _0 \Rightarrow T < T _0$
Thus final temp. is greater for isothermal process.
For isothermal process: $P_0 V_0=P_i V \Rightarrow P_1=P_0 \frac{V_0}{V}$
For adibatic process: $P_0\left( V _0\right)^\gamma= P _2( V )^y$
$\Rightarrow P _2= P _0\left(\frac{ V _0}{ V }\right)^\gamma$
As $\gamma > 1$ (always) $\Rightarrow P_1 > P_2$