\( = \Delta {{\text{S}}^\circ }_{X{Y_3}} - [\frac{1}{2}\Delta {S^\circ }_{{X_2}} + \frac{3}{2}\Delta {S^\circ }_{{Y_2}} = 50 - [\frac{1}{2} \times 60 + \frac{3}{2} \times 40]{\mkern 1mu} \)
\( = 50 - [30 + 60]{\mkern 1mu} \)
\( = - 40{\mkern 1mu} {\mkern 1mu} sq/{\mkern 1mu} {{\text{K}}^{{\text{ - 1}}}}{\mkern 1mu} \)
\(\Delta {\text{G}} = \Delta H - T\Delta S\) સંતુલને \(\Delta {\text{G}} = {\text{0}}\,\,\,\,\,\therefore \,\,\Delta {\text{H}} = {\text{T}}\Delta {\text{S}}\,\,\,\,\,\,{\text{T}} = \frac{{\Delta {\text{H}}}}{{\Delta {\text{S}}}} = \frac{{ - 30000}}{{ - 40}} = 750\,K\)
(તટસ્થીકરણ એન્થાલ્પી $=57\, kJ \,mol ^{-1}$ અને પાણીની વિશિષ્ટ ઉષ્મા= $4.2 \,J\,K ^{-1} \,g ^{-1}$ )