Questions · Page 2 of 6

M.C.Q (1 Marks)

MCQ 511 Mark
 Find equivalent capacitance between A and B

  • A
    $4\mu\text{F}$
  • B
    $6\mu\text{F}$
  • C
    $8\mu\text{F}$
  • D
    $10\mu\text{F}$ 
Answer
  1. $8\mu\text{F}$

Explanation:

In the given figure,

Equivalent capcitance between A and B.

Ceg ​= C​+ C2​

$=4μ\text{F}+4μ\text{F}$

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MCQ 521 Mark
The equivalent capacitance of the combination shown in figure is:

  • A
    C
  • B
    2C
  • C
    $\frac{\text{C}}{2}$
  • D
    None of these.
Answer
  1. 2C

Explanation:

Since the potential at point A is equal to the potential at point B, no current will flow along arm AB. Hence, the capacitor on arm AB will not contribute to the circuit. Also, because the remaining two capacitors are connected in parallel, the net capacitance of the circuit is given by

Ceq = C + C = 2C

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MCQ 531 Mark
Two capacitors each having capacitance C and breakdown voltage V are joined in series. The capacitance and the breakdown voltage of the combination will be:
  • A
    $\text{2C}\ \text{and}\ \text{2V}$
  • B
    $\frac{\text{C}}{2}\ \text{and}\ \frac{\text{V}}{2}$
  • C
    $\text{2C}\ \text{and}\ \frac{\text{V}}{2}$
  • D
    $\frac{\text{C}}{2}\ \text{and}\ \text{2V}$
Answer
  1. $\frac{\text{C}}{2}\ \text{and}\ \text{2V}$

Explanation:

Since the voltage gets added up when the capacitors are connected in series, the voltage of the combination is 2V.

Also, the capacitance of a series combination is given by

$\frac{1}{\text{C}_{\text{net}}}=\frac{1}{\text{C}_1}+\frac{1}{\text{C}_2}$

Here,

C​net​ = Net capacitance of the combination

$\text{C}_1=\text{C}_2=\text{C}$

$\therefore\text{C}_{\text{net}}=\frac{\text{C}}{2}$

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MCQ 541 Mark
The electrostatic potential due to an electric dipole is inversely proportional to:
  • A
    $\frac{1}{\text{r}}$
  • B
    $\frac{1}{\text{r}^2}$
  • C
    $\text{r}$
  • D
    $\text{r}^2$
Answer
  1. $\text{r}^2$
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MCQ 551 Mark
The electrostatic potential due to a point charge is directly proportional to:
  • A
    $\frac{1}{\text{r}}$
  • B
    $\frac{1}{\text{r}^2}$
  • C
    $\text{r}$
  • D
    $\text{r}^2$
Answer
  1. $\frac{1}{\text{r}}$
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MCQ 561 Mark
The energy stored per unit volume of a space is called as:
  • A
    Energy efficiency.
  • B
    Energy density.
  • C
    Electric field.
  • D
    Polarisation.
Answer
  1. Energy density.
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MCQ 571 Mark
  • A
    It will remain stationary
  • B
    It will move from B to A
  • C
    It will move from A to B
  • D
    It will rotate in a circular path
Answer
  1. It will move from A to B

Explanation:

A charge always tries to move from a point of higher potential to a point of lower potential. The potential at A is greater than the potential at B because of electric potential decreases with distance from the charge. It can also be explained by the fact that a positive charge is always repelled by another positive charge.

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MCQ 591 Mark
The electric field and the electric potential at a point are E and V respectively.
  • A
    If E = 0, V must be zero.
  • B
    If V = 0, E must be zero.
  • C
    If $\text{E}\neq0,$ V cannot be zero.
  • D
    If $\text{V}\neq0,$ E cannot be zero.
Answer
  1. If V = 0, E must be zero.

Explantion:

Electric field is negative gradient of electric potential.

$\text{E}=-\text{grad}(\text{V})$

$\text{E}=-\frac{\text{dV}}{\text{dr}}$

If $\text{E}=0$

$-\frac{\text{dV}}{\text{dr}}=0$

This implies

V = constant.

A constant can be zero or a quantifiable number.

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MCQ 601 Mark
At the surface of a charged conductor electrostatic field must be _____ to the surface at every point.
  • A
    Normal.
  • B
    Perpendicular.
  • C
    Parallel.
  • D
    Both a and b.
Answer
  1. Both a and b.
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MCQ 611 Mark
According to the diagram, the equipotential points are _____. The arrows are the direction of the electric field.
Image
  • A
    P and Q
  • B
    S and Q
  • C
    S and R
  • D
    P and R
Answer
  1. S and R

Explanation:

The equipotential surface is always perpendicular to the electric field lines. In the diagram, the electric field lines are horizontal and parallel to each other. Therefore, the equipotential lines must be vertical and the points that have equal potential should be on the vertical line. Therefore, R and S have equal potential.

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MCQ 621 Mark
The forces in which sum of kinetic energy and potential energy is conserved are called as:
  • A
    Electrostatic forces.
  • B
    Nuclear forces.
  • C
    Conservative forces.
  • D
    Both a and c.
Answer
  1. Conservative forces.
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MCQ 631 Mark
An electric dipole is placed in a uniform electric field. The net electric force on the dipole.
  • A
    Is always zero.
  • B
    Depends on the orientation of the dipole.
  • C
    Can never be zero.
  • D
    Depends on the strength of the dipole.
Answer
  1. Is always zero.

Explanation:

Net Electric force = FA + FB

= -qE + qE

= 0

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MCQ 641 Mark
What will be the nature of equipotential surfaces due to a point charge, situated at infinity?
  • A
    Plane surface
  • B
    Spherical
  • C
    Elliptical
  • D
    Cylindrical
Answer
  1. Plane surface

Explanation:

If a point charge is situated at infinity, the electric field lines coming out of it will be in the form of parallel straight lines. As we know that field lines cut the equipotential surfaces orthogonally, therefore the equipotential surfaces must be plane surfaces. They can be considered the surface of a sphere of infinite radius.

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MCQ 651 Mark
A capacitor becomes a perfect insulator for:
  • A
    Alternating current
  • B
    Direct current
  • C
    Both (a) and (b)
  • D
    None of these
Answer
  1. Direct current

Explanation:

A capacitor becomes a perfect insulator for direct current as the regular supply of current charges capacitor and the it behaves as open circuit, where as in A.C. the current being variable in sign and magnitude does not charge capacitor ever it goes through a repetitive process of charging and discharging and hence it never behaves as open circuit.

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MCQ 661 Mark
Name the unit of electrical potential:
  • A
    Coulomb
  • B
    Watt
  • C
    Joule
  • D
    Volt
Answer
  1. Volt

Explanation:

Electrical potential is a type of potential energy, and refers to the energy that could be released if electric current is allowed to flow.

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MCQ 671 Mark
What is the net electrostatic field in the interior of a conductor?
  • A
    Positive
  • B
    Negative
  • C
    Zero
  • D
    Depends on the nature of the conductor
Answer
  1. Zero

Explanation:

Net electrostatic field is zero in the interior of a conductor. When a conductor is placed in an electric field, its free electrons begin to move in the opposite direction. Negative charges are induced on the left end and positive charges on the right end of the conductor. The process continues until the electric field set up by induced charges becomes equal and opposite the external field.

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MCQ 681 Mark
Identify the simplest and the most widely used capacitor among the following.
  • A
    Electrolytic capacitor.
  • B
    Spherical Capacitor.
  • C
    Parallel plate capacitor.
  • D
    Cylindrical capacitor.
Answer
  1. Parallel plate capacitor.

Explanation:

The simplest and the most widely used capacitor is the parallel plate capacitor. It consists of two large plane parallel conducting plates, separated by a small distance.

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MCQ 691 Mark
Earth’s potential is _______?
  • A
    Zero.
  • B
    Highly positive.
  • C
    Highly negative.
  • D
    Varies from place to place.
Answer
  1. Zero.

Explanation:

We consider earth as the storage of infinite positive as well as a negative charge. Therefore, the potential of the earth is always considered to be zero and the potential of every body is measured with respect to earth. That’s why if we connect any charged body to the earth, its potential instantaneously becomes zero.

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MCQ 701 Mark
The molecules in which centres of positive and negative charges are separated are called as:
  • A
    Non polar molecules.
  • B
    Polar molecules.
  • C
    Both a and b.
  • D
    None.
Answer
  1. Polar molecules.
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MCQ 711 Mark
Identify the factor on which the capacitance of a parallel plate capacitor does not depend.
  • A
    Permeability of the medium between the plates.
  • B
    Area of the plates.
  • C
    Distance between the plates.
  • D
    The permittivity of the medium between the plates.
Answer
  1. Permeability of the medium between the plates.

Explanation:

The capacitance of a parallel plate capacitor is directly proportional to the area of the plates and permittivity of the medium between the plates. It is indirectly proportional to the distance between the plates.

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MCQ 721 Mark
...X... is a machine that can build up high voltages of the order of a few million volts. Here, A refers to:
  • A
    Dynamo.
  • B
    Van De Graaff generator.
  • C
    DC generator.
  • D
    AC generator.
Answer
  1. Van De Graaff generator.
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MCQ 731 Mark
A conductor carries a certain charge. When it is connected to another uncharged conductor of finite capacity, then the energy of the combined system is.
  • A
    More than that of the first conductor.
  • B
    Less than that of the first conductor.
  • C
    Equal to that of the first conductor.
  • D
    Uncertain.
Answer
  1. Less than that of the first conductor.
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MCQ 741 Mark
What is the order of potential difference built up by the Van de Graff generator?
  • A
    Potential difference of the order of hundreds.
  • B
    Potential difference of the order of several million volts.
  • C
    Potential difference of the order of thousands.
  • D
    Potential difference of the order of tens.
Answer
  1. Potential difference of the order of several million volts.

Explanation:

A Van de Graff generator, by means of a moving belt and suitable brushes, transfers charge continuously to a large spherical conducting shell. As a result, a potential difference of the order of several million volts is built up and this can be used for accelerating charged particles.

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MCQ 751 Mark
A foil of aluminium of negligible thickness is inserted in between the space of a parallel plate condenser. If the foil is electrically insulated, the capacity of the condenser will:

  • A
    increase
  • B
    decrease
  • C
    remain unchanged
  • D
    become zero
Answer
  1. remain unchanged

Explanation:

The capacity of condenser before inserting foil is $\text{C}=\frac{\text{A}\in0}{\text{d}}$​​ where A be the area of plate and d be the separation between plates.

After inserting foil the there will be two capacitors in series with capacitance 2C as distance is halved and the series combination of the two will give equivalent capacitance of C, hence, capacity will remain same.

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MCQ 761 Mark
Two metal pieces having a potential difference of 800V are 0.02m apart horizontally. A particle of mass 1.96 × 10-15kg is suspended in equilibrium between the plates. If e is the elementary charge, then charge on the particle is:
  • A
    8
  • B
    6
  • C
    0.1
  • D
    3
Answer
  1. 3
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MCQ 771 Mark
In a charged capacitor, the energy is stored in:
  • A
    The negative charges.
  • B
    The positive charges.
  • C
    The field between the plates.
  • D
    Both (a) and (b).
Answer
  1. The field between the plates.
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MCQ 781 Mark
A capacitor is charged by a battery. The battery is removed, and another identical uncharged capacitor is connected in parallel. The total electrostatic energy of resulting system.
  • A
    Decreases by a factor of 2.
  • B
    Remains the same.
  • C
    Increases by a factor of 2.
  • D
    Increases by a factor of 4.
Answer
  1. Decreases by a factor of 2.
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MCQ 791 Mark
On moving a charge of Q coulomb by X cm, W J of work is done, then the potential difference between the points is:
  • A
    W/Q *V.
  • B
    QW V.
  • C
    Q/W V.
  • D
    Q2 /W V.
Answer
  1. W/Q *V.
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MCQ 801 Mark
The electrostatic force between the metal plates of an isolated parallel plate capacitor C having a charge Q and area A, is:
  • A
    Independent of the distance between the plates.
  • B
    Linearly proportional to the distance between the plates.
  • C
    Inversely proportional to the distance between theplates.
  • D
    Proportional to the square root of the distance betweenthe plates.
Answer
  1. Independent of the distance between the plates.
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MCQ 811 Mark
Which material sheet should be placed between the plates of a parallel plate condenser in order to increase its capacitance ?
  • A
    Mica
  • B
    Copper
  • C
    Tin
  • D
    Iron
Answer
  1. Mica

Explanation:

Here copper, tin, iron all are conductor so they will decrease the capacitance. The mica sheet is a dielectric or insulator so it will increase the capacitance k times. Where k is the dielectric constant.

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MCQ 821 Mark
To obtain $3\ \mu\text{F}$ capacity from three capacitors of $2\ \mu\text{F}$ each, they will be arranged.
  • A
    All the three in series.
  • B
    All the three in parallel.
  • C
    Two capacitors in series and the third in parallel with the combinatioin of first two.
  • D
    Two capacitors in parallel and the third in series with the combinatioin of first two.
Answer
  1. Two capacitors in series and the third in parallel with the combinatioin of first two.
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MCQ 831 Mark
A parallel plate capacitor is charged to a certain voltage. Now, if the dielectric material (with dielectric constant k) is removed then the
  • A
    Capacitance increases by a factor of k
  • B
    Electric field reduces by a factor k
  • C
    Voltage across the capacitor decreases by a factor k
  • D
    None of these
Answer
  1. None of these

Explanation:

As the capacitor is charged by using cell so potential as well as filed between the plates become constant.

For removing dielectric the capacitance becomes C/ k. Thus capacitance decreases by a factor of k.

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MCQ 841 Mark
What is not true of equipotential surface?
  • A
    The PD between any two points on the surface is zero.
  • B
    The electric field is always perpendicular to the surface.
  • C
    Equipotential surfaces are always spherical.
  • D
    No work is done in moving a charge along the surface.
Answer
  1. Equipotential surfaces are always spherical.

Explanation:

Equipotential surface

→ P.D difference between two points on the surface is zero always since potential is same everywhere in equipotential surface.

→ The EF is always perpendicular to the surface because there is no potential gradient along any direction parallel to the surface P so no EF parallel to the surface

→ Equipotential surface can have any shape not just sphere.

→ No work is done in moving a charge along the surface, because potential difference is zero.

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MCQ 851 Mark
Each capacitor in the circuit shown is a 1F capacitor. What would be the equivalent capacitance between A and B?

  • A
    0.5F
  • B
    F
  • C
    2F
  • D
    4F
Answer
  1. F

Explanation:

Equivalent capacitance of each pair of capacitance in series$=\frac{1\times1}{1+1}\text{F}=0.5\text{F}$

The two series combination are connected in parallel. Hence the net capacitance becomes 0.5F + 0.5F = 1F

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MCQ 861 Mark
How is the potential within and on the surface of a conductor?
  • A
    Indirectly proportional
  • B
    Directly proportional
  • C
    Zero
  • D
    Constant
Answer
  1. Constant

Explanation:

Electric field at any point is equal to the negative of the potential gradient. But inside a conductor, the electric field is zero. Hence, the electric potential is constant throughout the volume of a conductor and has the same value on its surface.

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MCQ 871 Mark
An electric dipole is kept in non-uniform elecric field. it experiences?
  • A
    A force and a torque.
  • B
    A force but not a torque.
  • C
    A torque but not a force.
  • D
    Neither a force nor a torque.
Answer
  1. A force and a torque.
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MCQ 881 Mark
A smaller sphere has potential 50V and a larger sphere has potential 100V. How should they be placed so that if they are connected with the help of a wire, the charge will flow from the smaller sphere to the larger sphere? Both the spheres are conducting and hollow.
  • A
    Concentrically
  • B
    Touching each other
  • C
    It is never possible
  • D
    The smaller sphere should be grounded
Answer
  1. Concentrically

Explanation:

We know that for a conducting sphere, the charge is always distributed on its outer surface. We also know that charge flows from higher potential to lower potential. But if we put the smaller sphere inside the larger sphere and connect them with a conductor, they will act as a single conductor and charge will be distributed to its outer surface, i.e. charge will flow to the larger sphere.

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MCQ 891 Mark
What is the dimension of the dipole moment?
  • A
    [I L T]
  • B
    [I L T-1]
  • C
    [I L2 T]
  • D
    [I T]
Answer
  1. [I L T]

Explanation:

Dipole moment = charge × length of the dipole. The electric charge has dimensions [I T] and length has dimensions [L]. Therefore, the dipole moment has the dimension [I T L] and has unit C × m of C × m.

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MCQ 901 Mark
Which one of the following gives the resultant capacitor when capacitors are joined in series?
  • A
    The sum of the individual capacitors.
  • B
    The reciprocal of the sum of the reciprocals of the individual capacitors.
  • C
    The reciprocal of the sum of the capacitors.
  • D
    The sum of the reciprocals of the individual capacitors.
Answer
  1. The reciprocal of the sum of the reciprocals of the individual capacitors.

Explanation:

The resultant capacitor when capacitors are joined in series is the reciprocal of the sum of the reciprocals of the indivisual capacitors.

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MCQ 911 Mark
In which type of molecule positive and negative charges does not coincide with each other?
  • A
    Isentropic
  • B
    Equipotential
  • C
    Polar
  • D
    Non-polar
Answer
  1. Polar

Explanation:

A molecule in which the centre of mass of positive and negative charges does not collide with each other is called a polar molecule. They have a permanent dipole moment. They have unsymmetrical shapes.

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MCQ 921 Mark
. A surface that has the same electrostatic potential at every point on it is known as _____________.
  • A
    Equal-potential surface
  • B
    Same potential surface
  • C
    Equi-magnitude surface
  • D
    Equipotential surface
Answer
  1. Equipotential surface

Explanation:

Equipotential surface is a surface formed by the locus of all the points which are at the same potential. Equipotential surfaces do not intersect with each other and are closely spaced in the region of strong electric fields and vice-versa.

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MCQ 931 Mark
The direction of electric field is from:
  • A
    Negative to positive plate.
  • B
    Positive to negative plate.
  • C
    Both a and b.
  • D
    None.
Answer
  1. Positive to negative plate.
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MCQ 941 Mark
Each plate of a parallel plate capacitor has a charge q on it. The capacitor is now connected to a batter. Now:
  • A
    The facing surfaces of the capacitor have equal and opposite charges.
  • B
    The two plates of the capacitor have equal and opposite charges.
  • C
    The battery supplies equal and opposite charges to the two plates.
  • D
    The outer surfaces of the plates have equal charges.
Answer
  1. The facing surfaces of the capacitor have equal and opposite charges.

  2. The two plates of the capacitor have equal and opposite charges.

  1. The outer surfaces of the plates have equal charges.

Explanation:

In H.C Verma the answer is (a), (c), (d). But according to us the answer should be (a), (b), (d) all these options are the properties of a capacitor and the option (c) is incorrect because the battery is a source of energy not charge. Moreover if a capacitor plates have equal charge on outside and equal charge on inside then one can think that the charge on the plates must be also equal so option (b) cant be incorrect.

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MCQ 951 Mark
The potential energy of a system of two charges is negative when:
  • A
    Both the charges are positive.
  • B
    Both the charges are negative.
  • C
    One charge is positive and other is negative.
  • D
    Both the charges are separated by infinite distance.
Answer
  1. One charge is positive and other is negative.
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MCQ 961 Mark
When a dielectric is introduced between the plates of a condenser, the capacity of condenser:
  • A
    increases
  • B
    decreases
  • C
    remains same
  • D
    none of these
Answer
  1. increases

Explanation:

If the empty Condensor has capacity C, then its capacity with dielectric is given by C′ = kC, where k is the dielectric constant of the dielectric material. k can never be less than 1.

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MCQ 971 Mark
A diode, a resistor and a 50Hz AC source are connected in series. The number of current pulses per second through the resistor is:
  • A
    25
  • B
    50
  • C
    100
  • D
    200
Answer
  1. 50

Explanation:

The number of current pulses is equal to the frequency of the AC source because one current pulse passes through the diode for one oscillation of the AC source.

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MCQ 981 Mark
is equal to the work done by an external agent in carrying a unit of positive charge from the arbitrarily chosen reference point (usually infinity) to that point without any acceleration.
  • A
    Electric potential energy.
  • B
    Electric field.
  • C
    Electric potential.
  • D
    Electric potential difference.
Answer
  1. Electric potential.

Explanation:

Electric potential is equal to work done by an external agent in carrying a unit positive charge from the arbitrary chosen reference point to that point without any acceleration.

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MCQ 1001 Mark
An electric dipole is placed at the centre of a sphere, choose the correct options:
  • A
    Electric field is zero at every point on the surface.
  • B
    Flux is zero across the surface.
  • C
    No circle is present in the sphere which is equipotential.
  • D
    None of the above.
Answer
  1. Flux is zero across the surface.

Explanation:

A dipole contains two equal and opposite charge. So total charge inside the sphere will be zero.

By Gauss's law, the flux across a surface is depends on the charge inside the surface. As total charge is zero inside the sphere so the flux through the sphere will be zero.

As the electric field is resultant effect due to all charges so there will be field exists on the surface.

As the sphere contains two equal and opposite charges so there may be exists equipotential surface in the sphere.

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