Questions · Page 3 of 5

M.C.Q (1 Marks)

MCQ 1011 Mark
Which of the following change the activity of radioisotope?
  • A
    Temperature
  • B
    Pressure
  • C
    Chemical environment
  • D
    None of the above
Answer
  1. None of the above

Explanation:

The activity of radioisotope is not affected by any external condition of temperature, pressure or chemical change.

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MCQ 1021 Mark
The source of stellar energy is:
  • A
    Nuclear fission
  • B
    Nuclear fusion
  • C
    Nuclear fission & fusion
  • D
    Nuclear decay
Answer
  1. Nuclear fusion

Explanation:

Stellar and solar energy is due to fusion reactions. So, source of stellar energy is Nuclear fusion.

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MCQ 1031 Mark
92​U238 absorbs a neutron. The product emits an electron. This product further emits an electron. The result is
  • A
    94​Pu239
  • B
    90​Pu239
  • C
    93​Pu237
  • D
    94​Pu237
Answer
  1. 94​Pu239

Explanation:

92​V238 + n → 92​A239

92​A239 93​B239+e

92​B239 94​C239+e

Finding the element C from periodic table

94​Pu239

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MCQ 1041 Mark
For a nuclear fusion process, suitable nuclei are:
  • A
    Any nuclei.
  • B
    Heavy nuclei.
  • C
    Lighter nuclei.
  • D
    Nuclei lying in the middle of periodic table.
Answer
  1. Lighter nuclei.
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MCQ 1051 Mark
A chlorine atom whose nucleus contains 17 protons and 20 neutrons. Find out the composition of the nucleus of an isotope of chlorine?
  • A
    20 protons, 17 neutrons
  • B
    19 protons, 18 neutrons
  • C
    18 protons, 18 neutrons
  • D
    17 protons, 19 neutrons
Answer
  1. 17 protons, 19 neutrons

Explanation:

Isotope nucleus means that those nucleus has same protons number but different neutrons and mass number. Since chlorine has 17 protons so its isotope also will have 17 protons.

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MCQ 1061 Mark
An $\alpha$-particle is bombarded on 14N. As a result, a 17O nucleus is formed and a particle is emitted. This particle is a:
  • A
    Neutron.
  • B
    Proton.
  • C
    Electron.
  • D
    Positron.
Answer
  1. Proton.

Explanation:

If an alpha particle is bombarded on a nitrogen (N-14) nucleus, an oxygen (O-17) nucleus and a proton are released.

According to the conservation of mass and charge,

$^4_2\text{He}+\text{ }^{14}_7\text{N}\rightarrow\text{ }^{17}_6\text{O}+\text{ }^1_1\text{p}$

So, the emitted particle is a proton.

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MCQ 1071 Mark
The value of 1 amu is equal to:
  • A
    1.66×10−8g
  • B
    1.66×10−4g
  • C
    1.66×10−16g
  • D
    1.66×10−24g
Answer
  1. 1.66×10−24g

Explanation:

One an amu is $\frac{1}{10}$​ of the mass of one carbon-12 atom.

It is equal to $\frac{1}{\text{NA}}$

$\frac{1}{6.022\times10^{23}}$

= 1.66×10−24g.

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MCQ 1081 Mark
As the mass number A increases, the binding energy per nucleon in a nucleus:
  • A
    Increases.
  • B
    Decreases.
  • C
    Remains the same.
  • D
    Varies in a way that depends on the actual value of A.
Answer
  1.  Varies in a way that depends on the actual value of A.

Explanation:

Binding energy per nucleon in a nucleus first increases with increasing mass number (A) and reaches a maximum of 8.7MeV for A (50 - 80). Then, again it slowly starts decreasing with the increase in A and drops to the value of 7.5MeV.

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MCQ 1091 Mark
What describe the Einsteins equation for the relativity of mass and energy?
  • A
    A small amount of mass contains a lot of energy.
  • B
    A small amount of energy can be converted into a large amount of mass.
  • C
    Mass can be converted into energy, but energy cannot be converted mass.
  • D
    Energy can be converted into mass, but mass cannot be converted into energy.
Answer
  1. A small amount of mass contains a lot of energy.

Explanation:

Sir Einstein's mass-energy equation states that mass and energy can be converted into each other by the following relation.

E = mc2, (c = speed of light)

This implies that a small amount of mass contains a lot of energy, which can be proved with an example.

Let we have a mass of 1g = 10−3kg , therefore energy produced by it will be:

E = 10−3 × ( 3 × 10) 2 = 9 × 1013J

which is a vast amount energy produced by only one gram (small mass) of mass.

Whereas a small amount of energy doesn't give a large amount of mass because for that we have to divide the energy by c2, which gives a small mass.

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MCQ 1101 Mark
In a nuclear reactor, moderators slow down the neutrons which come out in a fission process. The moderator used have light nuclei. Heavy nuclei will not serve the purpose because:
  • A
    They will break up.
  • B
    Elastic collision of neutrons with heavy nuclei will not slow them down.
  • C
    The net weight of the reactor would be unbearably high.
  • D
    Substances with heavy nuclei do not occur in liquid or gaseous state at room temperature.
Answer
  1. Elastic collision of neutrons with heavy nuclei will not slow them down.

Solution:

The moderator used have light nuclei like proton. When protons undergo perfectly elastic collision with the neutron emitted their velocities are exchanged, it means, neutrons come to rest and protons move with the velocity of neutrons.

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MCQ 1111 Mark
Free 238U nuclei kept in a train emit alpha particles. When the train is stationary and a uranium nucleus decays, a passenger measures that the separation between the alpha particle and the recoiling nucleus becomes x in time t after the decay. If a decay takes place when the train is moving at a uniform speed v, the distance between the alpha particle and the recoiling nucleus at a time t after the decay, as measured by the passenger will be:
  • A
    x + vt
  • B
    x - vt
  • C
    x
  • D
    depends on the direction of the train.
Answer
  1. x

Explanation:

When the train is stationary, the separation between the alpha particle and recoiling uranium nucleus is x in time t after the decay. Even if the decay is taking place in a moving train and the separation is measured by the passenger sitting in it, the separation between the alpha particle and nucleus will be x. This is because the observer is also moving with the same speed with which the alpha particle and recoiling nucleus are moving, i.e. they all are in the same frame that is moving at a uniform speed.

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MCQ 1121 Mark
If a radioactive element is placed in an evacuated chamber, then the rate of radioactive decay will:
  • A
    Decrease.
  • B
    Remains unchanged.
  • C
    Increase.
  • D
    None of these.
Answer
  1. Remains unchanged.
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MCQ 1131 Mark
The heavier nuclei tend to have larger $\frac{\text{N}}{\text{Z}}$ ratio because:
  • A
    A neutron is heavier than a proton.
  • B
    A neutron is an unstable particle.
  • C
    A neutron does not exert electric repulsion.
  • D
    Coulomb forces have longer range compared to the nuclear forces.
Answer
  1. A neutron does not exert electric repulsion.
  2. Coulomb forces have longer range compared to the nuclear forces.

Explanation:

This is because in heavy nuclei, the $\frac{\text{N}}{\text{Z}}$ ratio becomes larger in order to maintain their stability and reduce instability caused due to the repulsion among the protons. The neutrons exert only attractive short-range nuclear forces on each other as well as on the neighbouring protons, whereas the protons exert attractive short-range nuclear forces on each other as well as the electrostatic repulsive force. Thus, the nuclei with high mass number, in order to be stable, have large neutron to proton ratio $\frac{\text{N}}{\text{Z}}.$

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MCQ 1141 Mark
As the mass number A increases, which of the following quantities related to a nucleus do not change?
  • A
    Mass.
  • B
    Volume.
  • C
    Density.
  • D
    Binding energy.
Answer
  1. Density.

Explanation:

Radius of a nucleus with mass number A is given as

$\text{R}=\text{R}_{\text{0}}\text{A}^{\frac{1}{3}}$

Here, $\text{R}_0=1.2\text{fm}$

$\therefore$ Volume of the nucleus $=\frac{4\pi\text{R}^3}{3}=\frac{4\pi\text{R}^3\text{A}}{3}$

This depends on A. With an increase in A, V increases proportionally.

Mass of the nucleus $\simeq\text{Am}_{\text{N}}$

Here, mis the mass of a nucleon.

Therefore, mass of the nucleus also increases with the increasing mass number. Binding energy also depends on mass number (number of nucleons) as it is the difference between the total mass of the constituent nucleons and the nucleus. Therefore, it also varies with the changing mass number.

On the other hand,

$\text{Density}=\frac{\text{Mass}}{\text{Volume}}$

$=\frac{\text{Am}_{\text{N}}}{\frac{4\pi\text{R}3}{3}}=\frac{\text{Am}_{\text{N}}}{\frac{4\pi\text{R}_0^3\text{A}}{3}}=\frac{\text{m}_{\text{N}}}{\frac{4\pi\text{R}_0^3}{3}}=\frac{3\text{m}_{\text{N}}}{4\pi\text{R}_{0}^3}$

This is independent of A and hence does not change as mass number increases.

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MCQ 1151 Mark
Which of the following is not a mode of radioactive decay?
  • A
    Positron emission.
  • B
    Electron capture.
  • C
    Fusion.
  • D
    Alpha decay.
Answer
  1. Fusion.
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MCQ 1161 Mark
For a fast chain reaction, the size of U235 block, as compared to its critical size, must be:
  • A
    greater
  • B
    smaller
  • C
    same
  • D
    anything
Answer
  1. greater

Explanation:

In fast chain reaction neutron released in previous fission again strikes 235U, So size of 235U block should be greater than it's critical size.

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MCQ 1171 Mark
Which of the following is used as standard for determination of atomic mass unit?
  • A
    O16
  • B
    C12
  • C
    H1
  • D
    O17
Answer
  1. C12

Explanation:

Atomic mass of a compound is measured in atomic mass units abbreviated as amu or u. One atomic mass unit is defined as $\frac{1}{12}$​th of mass of a single carbon-12 atom.

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MCQ 1181 Mark
In which of the following decays the atomic number decreases?
  • A
    $\alpha-\text{decay}$
  • B
    $\beta^+-\text{decay}$
  • C
    $\beta^--\text{decay}$
  • D
    $\gamma-\text{decay}$
Answer
  1. $\alpha-\text{decay}$

  2. $\beta^+-\text{decay}$

Explanation:

In alpha particle decay, the unstable nucleus emits an alpha particle reducing its proton number (atomic number) Z as well as neutron number N by 2.

$\text{ }^{\text{A}}_{\text{Z}}\text{X}\rightarrow\text{ }^{\text{A}-4}_{\text{Z}-2}\text{Y}+\text{ }^4_2\text{He}$

During $\beta^--\text{decay},$ a neutron is converted to a proton​, an electron and an antineutrino. Thus, there is an increase in the atomic number.

$\text{ }^{\text{A}}_{\text{Z}}\text{X}\rightarrow\text{ }^{\text{A}}_{\text{Z}+1}\text{Y}+\text{e}^-+\bar{\text{v}}$

During $\beta^+-\text{decay},$ a proton in the nucleus is converted to a neutron​, a positron and a neutrino in order to maintain the stability of the nucleus. Thus, there is a decrease in the atomic number. ​

$\text{ }^{\text{A}}_{\text{Z}}\text{X}\rightarrow\text{ }^{\text{A}}_{\text{Z}-1}\text{Y}+\beta^++\text{v}$

When a nucleus is in higher excited state or has excess of energy, it comes to the lower state in order to become stable and release energy in the form of electromagnetic radiation called gamma ray. The element in the gamma decay doesn't change.

Therefore, alpha and beta plus decay suffer decrease in atomic number.

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MCQ 1191 Mark
Radioactive substance emits:
  • A
    $\alpha - \text{rays} $
  • B
    $\beta - \text{rays}$
  • C
    $\gamma - \text{rays}$ 
  • D
    All of the above.
Answer
  1. All of the above.
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MCQ 1201 Mark
Joining of light nuclei of elements to form a heavy nucleus with the release of energy is called:
  • A
    Nuclear fission
  • B
    Nuclear fusion
  • C
    Nuclear combustion
  • D
    Nuclear combination
Answer
  1. Nuclear fusion

Explanation:

In nuclear physics, nuclear fusion is a nuclear reaction in which two or more atomic nuclei collide at a very high speed and join to form a new type of atomic nucleus. During this process, matter is not conserved because some of the matter of the fusing nuclei is converted to photons (energy).

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MCQ 1211 Mark
Nucleus of an atom whose atomic mass is 24 consists of:
  • A
    11 Electrons, 11 protons and 13 neutrons.
  • B
    11 Electrons, 13 protons and 11 neutrons.
  • C
    11 Protons and 13 neutrons.
  • D
    11 Protons and 13 electrons.
Answer
  1. 11 Protons and 13 neutrons.
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MCQ 1221 Mark
Which of the following is the radio isotope in this pair?$30\text{​P}\\ \ 15$,$32\text{​P}\\ \ 15$
  • A
    $32\text{​P}\\ \ 15$
  • B
    $30\text{​P}\\ \ 15$
  • C
    Both of them.
  • D
    None of them
Answer
  1. $32\text{​P}\\ \ 15$

Explanation:

$32\text{​P}\\ \ 15$ is the radioactive isotope of phosphorous element.

As it has more number of neutrons than number of protons.

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MCQ 1231 Mark
Consider a sample of a pure beta-active material:
  • A
    All the beta particles emitted have the same energy.
  • B
    The beta particles originally exist inside the nucleus and are ejected at the time of beta decay.
  • C
    The antineutrino emitted in a beta decay has zero mass and hence zero momentum.
  • D
    The active nucleus changes to one of its isobars after the beta decay.
Answer
  1. The active nucleus changes to one of its isobars after the beta decay.

Explanation:

In a beta decay, either a neutron is converted to a proton or a proton is converted to a neutron such that the mass number does not change. Also, the number of the nucleons present in the nucleus remains the same. Thus, the active nucleus gets converted to one of its isobars after beta decay.

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MCQ 1241 Mark
For the nuclie with mass number > 100:
  • A
    Binding energy of the nucleus decreases on an average as A increases.
  • B
    Binding energy of the nucleus increases on an average as A increases.
  • C
    The two nuclei fuse to form a bigger nuclide releasing energy.
  • D
    The nucleus essentially breaks up into two nuclides of equal mass releasing energy.
Answer
  1. Binding energy of the nucleus decreases on an average as A increases.

Explanation:

From the above figure it is clearly visible that the binding energy of the nucleus decreases on an average as A increases

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MCQ 1251 Mark
Q value for neutron decay is:
  • A
    0.782 MeV
  • B
    0.782 eV
  • C
    78.2 MeV
  • D
    0
Answer
  1. 0.782 MeV

Explanation:

For neutron decay, some mass disappears as neutrons convert to a proton, electron and antineutrino.

Q = (mn​−mp​−mνˉ​−me​)c= 0.782MeV

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MCQ 1261 Mark
In an endothermic reaction the binding energies of reactants and products are e1​, e2​ respectively, then:
  • A
    e1​< e2
  • B
    e1​= e2​
  • C
    e1​> e2​
  • D
    e1​ ≥ e2
     
Answer
  1. e1​> e2​

Explanation:

In endothermic reaction the binding energy of reactants is more than the binding energy of products.

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MCQ 1271 Mark
Which is the lightest element in the universe?
  • A
    Helium
  • B
    Hydrogen
  • C
    Nitrogen
  • D
    Silicon
Answer
  1. Hydrogen

Explanation:

Hydrogen is the lightest element in the universe with atomic number 1 and so, it has the simplest atomic structure.

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MCQ 1281 Mark
Sun maintains its shining because of:
  • A
    The fission of helium
  • B
    Chemical reactoin
  • C
    Fusion of hydrogen nuclei
  • D
    Burning of carbon
Answer
  1. Fusion of hydrogen nuclei

Explanation:

The Sun produces energy by the nuclear fusion of hydrogen into helium in its core.

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MCQ 1291 Mark
Which of the following are electromagnetic waves?
  • A
    $\alpha-\text{decay}$
  • B
    $\beta^+-\text{decay}$
  • C
    $\beta^--\text{decay}$
  • D
    $\gamma-\text{decay}$
Answer
  1. $\gamma-\text{decay}$

Explanation:

Alpha rays, beta-plus and beta-minus rays carry charged particles that show particle behaviour. On the other hand, gamma rays carry photons that show particle as well as wave behaviour. Hence, only gamma rays are electromagnetic waves.

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MCQ 1301 Mark
A free neutron decays to a proton but a free proton does not decay to a neutron. This is because:
  • A
    Neutron is a composite particle made of a proton and an electron whereas proton is a fundamental particle.
  • B
    Neutron is an uncharged particle whereas proton is a charged particle.
  • C
    Neutron has large rest mass than the proton.
  • D
    Weak forces can operate in a neutron but not in a proton.
Answer
  1. Neutron has large rest mass than the proton.

Explanation:

A nucleus is made up of two fundamental particles-neutrons and protons. If a nucleus has more number of neutrons than what is needed to have stability, then neutrons decay into protons and if there's an excess of protons, then they decay to form neutrons. Since a neutron has larger rest mass than a proton, the Q-value of its decay reaction is positive and a free neutron decays to a proton, while an isolated proton cannot decay to a neutron as the Q-value of its decay reaction is negative. Hence, it is physically not possible.

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MCQ 1311 Mark
The neutron was discovered by:
  • A
    Marie Curie
  • B
    Pierree Curie
  • C
    James Chadwick
  • D
    Rutherford
Answer
  1. James Chadwick

Explanation:

James Chadwick discovered the neutron.

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MCQ 1321 Mark
Nuclear forces exists between:
  • A
    Neutron - neutron.
  • B
    Proton - proton.
  • C
    Neutron - proton.
  • D
    All of these.
Answer
  1. All of these.
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MCQ 1331 Mark
The 'rad' is the correct unit used to report the measurement of:
  • A
    The ability of a beam of gamma ray photons to produce ions in a target.
  • B
    The energy delivered by radiation to a target.
  • C
    The biological effect of radiation.
  • D
    The rate of decay of a radioactive source.
Answer
  1. The biological effect of radiation.
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MCQ 1341 Mark
Half life of radioactive element depends upon:
  • A
    Amount of element present.
  • B
    Temperature.
  • C
    Pressure.
  • D
    Nature of element.
Answer
  1. Nature of element.
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MCQ 1351 Mark
What is the atomic mass (u) of sodium?
  • A
    22
  • B
    23
  • C
    23.5
  • D
    24
Answer
  1. 23

Explanation:

Sodium is a chemical element with the symbol Na and atomic number 11. 

Atomic mass (u) of sodium = 23u.

It is a soft, silvery-white, highly reactive metal.

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MCQ 1361 Mark
Complete the reaction: 
86​Rn22084​Po216+ __________:
  • A
    $\beta$
  • B
    $\gamma$
  • C
    $\alpha$
  • D
    $\text{H}^1_1$
Answer
  1. $\alpha$

Explanation:

86​Rn220 → 84​Po216 Z​XA

Z + 84 = 86 and 220 = 216 + A

So, Z = 2 and A = 4

$2​​\alpha^4$

So, it is $\alpha$ particle.

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MCQ 1371 Mark
Two lithium nuclei in a lithium vapour at room temperature do not combine to form a carbon nucleus because:
  • A
    A lithium nucleus is more tightly bound than a carbon nucleus.
  • B
    Carbon nucleus is an unstable particle.
  • C
    It is not energetically favourable.
  • D
    Coulomb repulsion does not allow the nuclei to come very close.
Answer
  1. Coulomb repulsion does not allow the nuclei to come very close.

Explanation:

Lithium atom contains 3 protons and 3 neutrons in the nucleus and 3 valence electrons. When two lithium nuclei are brought together, they repel each other. The attractive nuclear forces being short-range are insignificant as compared to the electrostatic repulsion. Thus, the nuclei do not combine to form carbon atom because of coulomb repulsion.

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MCQ 1381 Mark
Radioactive samples are stored in lead boxes because it is:
  • A
    Heavy.
  • B
    Strong.
  • C
    Good absorber.
  • D
    Bad conductor.
Answer
  1. Good absorber.
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MCQ 1391 Mark
Identify the similarity between isotopes of the same element.
  • A
    They have the same particles in the nucleus.
  • B
    They are equally abundant in nature.
  • C
    They have the same number of protons
  • D
    They have the same mass.
Answer
  1. They have the same number of protons

Explanation:

Isotopes of the same element must have same number of protons but different number of neutrons and hence they have different mass.

Also the isotopes of same element are not equally abundant in nature. 

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MCQ 1401 Mark
What is the average binding energy per nucleon over a wide range?
  • A
    8MeV
  • B
    8.8MeV
  • C
    7.6MeV
  • D
    1.1MeV
Answer
  1. 8MeV

Explanation:

The average binding energy per nucleon is just the total binding energy divided by the number of nucleons. If we consider Na atom, its binding energy is 194MeV. 

Its binding energy per nucleon is given by $\frac{194\text{MeV​}}{24}$

= 8.08MeV

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MCQ 1411 Mark
When a nucleus in an atom undergoes a radioactive decay, the electronic energy levels of the atom:
  • A
    Do not change for any type of radioactivity.
  • B
    Change for α and β radioactivity but not for γ-radioactivity.
  • C
    Change for α-radioactivity but not for others.
  • D
    Change for β-radioactivity but not for others.
Answer
  1. Change for α and β radioactivity but not for γ-radioactivity.

Solution:

Key Concept:

Features
α- particles
β- particles
γ-rays
1.
Identity
Helium nucleus or doubly ionised helium atom (2He4)
Fast moving electron $(-\beta^0\text{ or }\beta^-)$
Photons (E.M. waves)
2.
Charge
+2e
-e
Zero
3.
Mass
4 mp (mp = mass of proton) = 1.87 × 10-27
me
Massless
4.
Equation of decay
$_\text{Z}\text{X}^\text{A} \xrightarrow{\alpha-\text{decay}}\ _{\text{z}-2}\text{Y}^{\text{A}-4}+_2\text{He}^4$
$\text{n}_\alpha=\frac{\text{A}-\text{A}'}{4}$
$_\text{Z}\text{X}^\text{A}\rightarrow_{\text{z}-2}\text{Y}^{\text{A}}+_{-1}\text{e}^0+\overline{\text{v}}$
$_\text{Z}\text{Y}^\text{A}\xrightarrow{^\text{n}\beta}\ _{\text{z}'}\text{Y}^{\text{A}}$
$\Rightarrow\ \text{n}_\beta=(2\text{n}_\alpha-\text{Z}+\text{Z}')$
$_\text{Z}\text{X}^\text{A}\rightarrow\ _\text{Z}\text{X}^\text{a}+\gamma$

A/3-particle carries one unit of negative charge (-e), an α-particle carries 2 units of positive charge (+2e ) and γ (particle) carries no charge. Hence electronic energy levels of the atom charges for α and β decay, but not for γ-decay.

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MCQ 1421 Mark
The binding energies of a deutron and an $\alpha$-particle are 1.125, 7.2MeV/nucleon respectively. Which is more stable of the two?
  • A
    Deuteron
  • B
    $\alpha$-practicle
  • C
    Both
  • D
    Sometimes deutron and sometimes $\alpha$-particle
Answer
  1. $\alpha$-practicle

Explanation:

The binding energy is a energy that holds the nucleus together. 

Thus, more binding energy will give more stable nuclei. Here alpha particle has more binding energy so it will be more stable than deutron.

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MCQ 1431 Mark
The critical mass of a fissionable material is:
  • A
    0.1kg
  • B
    The minimum mass needed for chain reaction.
  • C
    The rest mass equivalent to 1020 joules.
  • D
    0.5kg
Answer
  1. The minimum mass needed for chain reaction.

Explanation:

If the mass of fissionable material exceeds a critical value, chain reaction or self propagating fission reaction or self propagating fission reaction takes place.

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MCQ 1441 Mark
The difference between the mass of a nucleus and the combined mass of its nucleons is:
  • A
    Zero
  • B
    Positive
  • C
    Negative
  • D
    Zero, positive or negative
Answer
  1. Negative

Explanation:

We know that mass defect = combined mass of nucleons − mass of the nucleus.

Since mass defect is always positive quantity so the difference of nucleus and the combined mass of its nucleons will be negative. The combined mass is greater than the mass of nucleus.

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MCQ 1451 Mark
Particles which can be added to the nucleus of an atom without changing its chemical properties are called:
  • A
    Neutrons.
  • B
    Electrons.
  • C
    Protons.
  • D
    Alpha particles.
Answer
  1. Neutrons.
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MCQ 1461 Mark
The curve of binding energy per nucleon as a function of atomic mass number has a sharp peak for helium nucleus. This implies that helium?
  • A
    Can easily be broken up.
  • B
    Is very stable.
  • C
    Can be used as fissionable meterial.
  • D
    Is radioactive.
Answer
  1. Is very stable.
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MCQ 1471 Mark
Which of the following is the radio-isotope? 
$^{39}_{19}{\text{K}}$​, $^{40}_{19}{\text{K}}$
  • A
    $^{39}_{19}{\text{K}}$
  • B
    $^{40}_{19}{\text{K}}$
  • C
    $^{39}_{19}{\text{K}}$​, $^{40}_{19}{\text{K}}$
  • D
    none of them
Answer
  1. $^{40}_{19}{\text{K}}$

Explanation:

$^{40}_{19}{\text{K}}$ is the radioactive isotope of Potassium element.

As it has more number of neutrons than number of protons.

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MCQ 1481 Mark
Let Fpp' Fpn and Fnn fill denote the magnitudes of the nuclear force by a proton on a proton, by a proton on a neutron and by a neutron on a neutron respectively. When the separation is 1fm:
  • A
    Fpp > Fpn = Fnn
  • B
    Fpp = Fpn = Fnn
  • C
    Fpp > Fpn > Fnn
  • D
    Fpp < Fpn = Fnn
Answer
  1. Fpp < Fpn = Fnn

Explanation:

Protons and neutrons are present inside the nucleus and they exert strong attractive nuclear forces on each other, which are equal in magnitude. Due to their positive charge, protons repel each other. Hence the net attractive force between two protons gets reduced, but the nuclear force is stronger than the electrostatic force at a separation of 1fm.

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MCQ 1491 Mark
The same radioactive nucleus may emit?
  • A
    All the three $\alpha,\ \beta$ and $\gamma$ one after another.
  • B
    All the three $\alpha,\ \beta$ and $\gamma$ radiations simultaneously.
  • C
    Only $\alpha$ and $\beta$ simultaneously.
  • D
    Only one $\alpha,\ \beta$ and $\gamma$ at a time.
Answer
  1. Only one $\alpha,\ \beta$ and $\gamma$ at a time.
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MCQ 1501 Mark
Isotopes of an element contain:
  • A
    The same number of protons but different number of neutrons.
  • B
    The same number of neutrons but different number of protons.
  • C
    Equal number of protons and electrons.
  • D
    Equal number of nucleons.
Answer
  1. The same number of protons but different number of neutrons.

Explanation:

Isotopes of an element must have same atomic number (Z) but different mass number A.

Number of protons is equal to the atomic number.

So, isotopes of an element have same number of protons.

Mass number is equal to the sum of number of protons and neutrons i.e. A = p + n

As isotopes of an element have different mass number but same number of protons, thus they must have different number of neutrons.

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