A resistor has a resistance of 176 ohms. How many of these resistors should be connected in parallel so that their combination draws a current of 5 amperes from a 220 volt supply line?
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I = 5A
V = 220V
$\text{R}=\frac{\text{V}}{\text{I}}=\frac{220}{5}=44\Omega$
Required resistance is less that $176\Omega,$ so the resistor should be connected in parallel.
Let the required no. be n.
$\text{R}_\text{eq}=\frac{176}{\text{n}}=44$
$\text{n}=\frac{176}{44}=4$
V = 220V
$\text{R}=\frac{\text{V}}{\text{I}}=\frac{220}{5}=44\Omega$
Required resistance is less that $176\Omega,$ so the resistor should be connected in parallel.
Let the required no. be n.
$\text{R}_\text{eq}=\frac{176}{\text{n}}=44$
$\text{n}=\frac{176}{44}=4$
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