If the charge on an electron is $1.6 \times 10$ coulombs, how many electrons should pass through a conductor in $1$ second to constitute $1$ ampere current?
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We know that
$\text{I}=\frac{\text{Q}}{\text{T}}$
$\Rightarrow1\text{A}=\frac{\text{Q}}{1\text{s}}$
$\Rightarrow\text{Q}=1\text{C}$
Now, when charge is $1.6 \times 10^{-19}$ Coulamb, number of electrone $= 1$
When charge is $1$ Coulamb, number of electrone $=\frac{1}{1.6\times10^{-19}}=0.625\times10^{19}=625\times10^{18}$
$\text{I}=\frac{\text{Q}}{\text{T}}$
$\Rightarrow1\text{A}=\frac{\text{Q}}{1\text{s}}$
$\Rightarrow\text{Q}=1\text{C}$
Now, when charge is $1.6 \times 10^{-19}$ Coulamb, number of electrone $= 1$
When charge is $1$ Coulamb, number of electrone $=\frac{1}{1.6\times10^{-19}}=0.625\times10^{19}=625\times10^{18}$
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