For a straight \(P-V\) graph line \(P \propto V\)

If pressure increases, volume increases then \(T\) also increases \([P V \propto T]\)

So \(\Delta T \neq 0\)

Volume increasing so work is positive, \(W > 0\)

and temperature also increasing so \(\Delta Q > 0\)

\(\because \Delta Q=\Delta U+\Delta W\)

So \(\Delta U > 0\)