\(\mathrm{B}=\left(\frac{2}{3} \pi \mathrm{R}^{3}\right) \rho \mathrm{g}\)
\(\mathrm{F}=\mathrm{T}(2 \pi \mathrm{R})\)
\(\mathrm{m}=\mathrm{d}\left(\frac{4}{3} \pi \mathrm{R}^{3}\right)\)
\(\left(\frac{2}{3} \pi \mathrm{R}^{3}\right) \rho \mathrm{g}+\mathrm{T}(2 \pi \mathrm{R})=\mathrm{d}\left(\frac{4}{3} \pi \mathrm{R}^{3}\right) \mathrm{g}\)
\(\mathrm{T}(2 \pi \mathrm{R})=\left(\frac{2}{3} \pi \mathrm{R}^{3}\right) \mathrm{g}[2 \mathrm{d}-\rho]\)
\(\mathrm{R}=\sqrt{\frac{3 \mathrm{T}}{(2 \mathrm{d}-\rho) \mathrm{g}}}\)
[પ્રવાહીની ઘનતા $\left.\rho_{\text {(liquid) }}=900\; kg\,m ^{-3}, g =10\, ms ^{-2}\right]$ (નજીકના પૂર્ણાંકમાં જવાબ આપો)