For the circuit shown in the diagram below:
What is the value of :
Current through $6 Ω$ resistor?
Potential difference across $12 Ω$ resistor?
Download our app for free and get started
As per the circuit
$V = 4V$
Total resistance in line $1 = R_1 = 6 + 3 = 3$ ohm
Total resistance in line $2 = R_2 = 12 + 3 = 15$ ohm
Current through $6\Omega$ resistor = current through line $1=\frac{\text{=V}}{\text{R}_1}=\frac{4}{9}=0.44\Omega$
p.d. across line $2$ is $4V$
current through line $2=\frac{\text{V}}{\text{R}_2}=\frac{4}{15}\Omega$
p.d. across $12\Omega$ resistor $=\frac{4}{15}\times12=3.2\text{V}$
Download our app
and get started for free
Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*
The electrical resistivities of five substances A, B, C, D and E are given below:
$\begin{matrix}\text{B}&110\times10^{-8}\Omega\text{ m}\\\text{C}&2.60\times10^{-8}\Omega\text{ m}\\\text{D}&10.0\times10^{-8}\Omega\text{ m}\\\text{E}&1.70\times10^{-8}\Omega\text{ m}\end{matrix}$
Calculate the area of cross-section of a wire if its length is 1.0m, its resistance is $23 Ω$ and the resistivity of the material of the wire is $1.84\times10 Ω\ \text{m}.$
The electrical resistivities of four materials P, Q, R and S are given below:
$\begin{matrix}\text{P}&6.84\times10^{-8}\Omega\text{m}\\\text{Q}&1.70\times10^{-8}\Omega\text{m}\\\text{R}&1.0\times10^{15}\Omega\text{m}\\\text{S}&11.0\times10^{-7}\Omega\text{m}\end{matrix}$
Which material will you use for making:
If the charge on an electron is $1.6 \times 10$ coulombs, how many electrons should pass through a conductor in $1$ second to constitute $1$ ampere current?