What will be the resistance of a metal wire of length $2$ metres and area of cross-section $1.55 \times 10m $, if the resistivity of the metal be $2.8 \times 10 m?$
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$I = 2m$
$A = 1.55 \times 10^{-6} m^2$
$P = 2.8 \times 10^{-8}m$
$\text{R}=\text{P}\frac{\text{I}}{\text{A}}$
$=2.8\times10^{-8}\times\frac{2}{1.55\times10^{-6}}$
$0.036\Omega$
$A = 1.55 \times 10^{-6} m^2$
$P = 2.8 \times 10^{-8}m$
$\text{R}=\text{P}\frac{\text{I}}{\text{A}}$
$=2.8\times10^{-8}\times\frac{2}{1.55\times10^{-6}}$
$0.036\Omega$
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