A p.d. of 6V is applied to two resistors of $3 Ω$ and $6 Ω$ connected in parallel. Calculate:
The combined resistance.
The current flowing in the main circuit.
The current flowing in the $3 Ω$ resistor.
The combined resistance.
The current flowing in the main circuit.
The current flowing in the $3 Ω$ resistor.
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$V = 6V,$
$R_1 = 3 ohm$, $R_2 = 6\ ohm$ (in parallel)
Combined resistance, $\frac{1}{\text{R}}=\frac{1}{\text{R}_1}+\frac{1}{\text{R}_2}$
$\frac{1}{\text{R}}=\frac{1}{3}+\frac{1}{6}=\frac{3}{6}=\frac{1}{2}$
R = 2 ohm
Current flowing in the main circuit, $\text{I}=\frac{\text{V}}{\text{R}}=\frac{6}{2}=3\text{A}$
Current flowing in 3 ohm resistor $=\frac{\text{V}}{\text{R}_1}=\frac{6}{3}=2\text{A}$
$R_1 = 3 ohm$, $R_2 = 6\ ohm$ (in parallel)
Combined resistance, $\frac{1}{\text{R}}=\frac{1}{\text{R}_1}+\frac{1}{\text{R}_2}$
$\frac{1}{\text{R}}=\frac{1}{3}+\frac{1}{6}=\frac{3}{6}=\frac{1}{2}$
R = 2 ohm
Current flowing in the main circuit, $\text{I}=\frac{\text{V}}{\text{R}}=\frac{6}{2}=3\text{A}$
Current flowing in 3 ohm resistor $=\frac{\text{V}}{\text{R}_1}=\frac{6}{3}=2\text{A}$
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