b
Work done in adiabatic process $=\frac{-n R}{\gamma-1}\left(T_{f}-T_{i}\right)$
$\therefore W _{ AD }=\frac{- nR }{\gamma-1}\left( T _{2}- T _{1}\right)$
$\text { and } W _{ BC }=\frac{- nR }{\gamma-1}\left( T _{2}- T _{1}\right)$
$\therefore W _{ AD }= W _{ BC }$