It means it is a first order reaction (because unit of rate constant is $\sec^{-1}$)
For first order reaction $K = \frac{1}{t}\ln \frac{a}{{a - x}}$
$Kt = \ln \frac{a}{{a - x}} = \ln \frac{{{{[{N_2}{O_5}]}_0}}}{{{{[{N_2}{O_5}]}_t}}}$
$\mathrm{R}=8.314\; \mathrm{JK}^{-1} \mathrm{mol}^{-1}$
| $[A] (mol\,L^{-1})$ | $[B] (mol\,L^{-1})$ | પ્રક્રિયાનો પ્રારંભિક વેગ $(mol\, L^{-1}\,s^{-1} )$ |
| $0.05$ | $0.05$ | $0.045$ |
| $0.10$ | $0.05$ | $0.090$ |
| $0.20$ | $0.10$ | $0.72$ |