Show how you would connect two 4 ohm resistors to produce a combined resistance of:
- 2 ohms.
- 8 ohms.
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By connecting in parallel: Since equivalent resistance will be
$\frac{1}{\text{R}}=\frac{1}{4}+\frac{1}{4}=\frac{2}{4}=\frac{1}{2}$
Therefore. R = 2 ohm
By connecting in series: since equilaent resistance will be R = 4 ohm + 4 ohm = 8 ohm.
$\frac{1}{\text{R}}=\frac{1}{4}+\frac{1}{4}=\frac{2}{4}=\frac{1}{2}$
Therefore. R = 2 ohm
By connecting in series: since equilaent resistance will be R = 4 ohm + 4 ohm = 8 ohm.
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