Show how you would connect two 4 ohm resistors to produce a combined resistance of:
2 ohms.
8 ohms.
Download our app for free and get started
By connecting in parallel: Since equivalent resistance will be
$\frac{1}{\text{R}}=\frac{1}{4}+\frac{1}{4}=\frac{2}{4}=\frac{1}{2}$
Therefore. R = 2 ohm
By connecting in series: since equilaent resistance will be R = 4 ohm + 4 ohm = 8 ohm.
Download our app
and get started for free
Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*
A resistor of 8 ohms is connected in parallel with another resistor X. The resultant resistance of the combination is 4.8 ohms. What is the value of the resistor X?
With the help of a circuit diagram, obtain the relation for the equivalent resistance of two resistances connected in parallel. In the circuit diagram shown below, find:
The resistors $R_1 , R_2 , R_3$ and $R_4$ in the figure given below are all equal in value.
What would you expect the voltmeters $A, B$ and $C$ to read assuming that the connecting wires in the circuit have negligible resistance?
Calculate the area of cross-section of a wire if its length is 1.0m, its resistance is $23 Ω$ and the resistivity of the material of the wire is $1.84\times10 Ω\ \text{m}.$
Two resistances when connected in parallel give resultant value of $2$ ohm; when connected in series the value becomes $9$ ohm. Calculate the value of each resistance.