In 10s, a charge of 25C leaves a battery, and 200j of energy are delivered to an outside circuit as a result.
- What is the p.d. across the battery?
- What current flows from the battery?
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t = 10s
Q = 25C,
Energy deliverd = work done = 200J
$\text{p}.\text{d}.=\frac{\text{Work done}}{\text{Charge moved}}=\frac{200}{25}=8\text{V}$
$\text{I}=\frac{\text{Q}}{\text{t}}=\frac{25}{10}=2.5\text{A}$
Q = 25C,
Energy deliverd = work done = 200J
$\text{p}.\text{d}.=\frac{\text{Work done}}{\text{Charge moved}}=\frac{200}{25}=8\text{V}$
$\text{I}=\frac{\text{Q}}{\text{t}}=\frac{25}{10}=2.5\text{A}$
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