The coefficient of performance of a refrigerator is $5$ . If the temperature inside freezer is $-20\,^oC$ , the temperature of the surroundings to which it rejects heat is ....... $^oC$
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Coefficient of performance of refrigerator
$\mathrm{COP}=\frac{\mathrm{T}_{\mathrm{L}}}{\mathrm{T}_{\mathrm{H}}-\mathrm{T}_{\mathrm{L}}}$
Where $\mathrm{T}_{\mathrm{L}} \rightarrow$ lower Temperature
$\mathrm{\&} \quad \mathrm{T}_{\mathrm{H}} \rightarrow$ Higher Temperature
So, $5=\frac{T_{L}}{T_{H}-T_{L}}$
$\Rightarrow \mathrm{T}_{\mathrm{H}}=\frac{6}{5} \mathrm{T}_{\mathrm{L}}=\frac{6}{5}(253)=303.6 \mathrm{K}$
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