The distance between the centres of carbon and oxygen atoms in carbon monoxide gas molecules is $=1.13\mathring{\text{A}}.$ Locate the centre of mass of the molecules relative to carbon atom.
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Here, distance between carbon and oxygen atoms $=1.13\mathring{\text{A}}$ Mass of carbon atom $m_1 = 14$ Mass of oxygen atom $m_2 = 16$ Let COM of molecule be at a distance x from carbon atom.
$\therefore \text{r}_1 = \times \mathring{\text{A}}, \text{ r}_2 = (1.13 - \times)\mathring{\text{A}}$ As $m_1r_1 = m_2r_2$
$\therefore14\text{x}=16(1.13-\text{x})$ $\text{ or }30\text{x}=16\times1.13$ $\text{x}=\frac{16\times1.13}{30}=0.602\mathring{\text{A}}.$
$\therefore \text{r}_1 = \times \mathring{\text{A}}, \text{ r}_2 = (1.13 - \times)\mathring{\text{A}}$ As $m_1r_1 = m_2r_2$
$\therefore14\text{x}=16(1.13-\text{x})$ $\text{ or }30\text{x}=16\times1.13$ $\text{x}=\frac{16\times1.13}{30}=0.602\mathring{\text{A}}.$
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