For isothermal process: $T_2=T_0$
For adibatic process: $T_0\left(V_0\right)^{\gamma-1}=T(V)^{\gamma-1}$
As $V > V _0 \Rightarrow T < T _0$
Thus final temp. is greater for isothermal process.
For isothermal process: $P_0 V_0=P_i V \Rightarrow P_1=P_0 \frac{V_0}{V}$
For adibatic process: $P_0\left( V _0\right)^\gamma= P _2( V )^y$
$\Rightarrow P _2= P _0\left(\frac{ V _0}{ V }\right)^\gamma$
As $\gamma > 1$ (always) $\Rightarrow P_1 > P_2$
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$B=\frac{4}{\pi} \times 10^{-3}\, {T}\left(1-\frac{{t}}{100}\right)$
The energy dissipated by the coil before the magnetic field is switched off completely is $E=.....\,{m} J.$

$(i)$ acceleration of the centre of mass of ring is $\frac{g}{3}$
$(ii)$ acceleration of the hanging particle is $\frac{2g}{3}$
$(iii)$ frictional force (on the ring) acts along forward direction
$(iv)$ frictional force (on the ring) acts along backward direction
