a
In triangle shape \({N}_{{t}}=\frac{24 {a}}{3 {a}}=8\)

In square \({N}_{{s}}=\frac{24 {a}}{4 {a}}=6\)

\(\frac{{M}_{{t}}}{{M}_{3}}=\frac{{N}_{{t}} {IA}_{{t}}}{{N}_{{s}} {I}_{{s}}}[{I}\) will be same in both \(]\)

\(=\frac{8 \times \frac{\sqrt{3}}{4} \times a^{2}}{6 \times a^{2}}\)

\(\frac{{M}_{{t}}}{{M}_{{s}}}=\frac{1}{\sqrt{3}}\)

\({y}=3\)