Temperature of ice cold water \({T_1} = 0^\circ C = 273\,K\)

Final volume of \({V_2} = 67\) units

Applying Charle’s law, we have \(\frac{{{V_1}}}{{{T_1}}} = \frac{{{V_2}}}{{{T_2}}}\)

(where temperature \({T_2}\) is the boiling point)

or \({T_2} = \frac{{{V_2}}}{{{V_1}}} \times {T_1} = \frac{{67 \times 273}}{{47.5}} = 385\,K = 112^\circ C\)