\( = \,\,\frac{{164}}{{65.6}}\,\, = \,\,2.5\)
\(\because \,\,i\,\, = \,\,1\,\, + \,\,(n\,\, - \,\,1)\,\,\alpha .\,[Ca{(N{O_3})_2} \to \,\,C{a^{ + 2}}\, + \,\,2NO_3^ - ]\)
\(2.5\,\, = \,\,1\,\, + \,\,(3\,\, - \,\,1)\,\,\alpha \,\,\, \Rightarrow \,\,\,2\alpha \,\, = \,\,1.5\,\,\)
\( \Rightarrow \,\,\alpha \,\, = \,\,0.75\)
\(\,\alpha (in\,\% )\,\, = \,\,75\% \)
$(R = 0.083 \,L\, bar \,mol^{-1}\, K{-1})$