The Maxwell's distribution curve heats at the most probable speed, which depends on temperature.
\(V_{\text {probable }} \propto \sqrt{T}\)
Hence \(T_1 > T_2\) is correctly shown in option \((1)\) as it shows with peaks of the curve at higher temperature, furthers along the \(x\)-axis.
કારણ : $\frac{{{C_P}}}{{{C_V}}} = \gamma $