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M.C.Q (1 Marks)

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153 questions · auto-graded multiple-choice test.

MCQ 11 Mark
Electronegativity of inert gases is :
  • A
    low
  • B
    high
  • zero
  • D
    abnormally high
Answer
Correct option: C.
zero
Electronegativity of inert gases is zero as they have no tendency to attract the shared e$^-$.
Since the noble gases already have eight electrons in their outer shells, they don't want to attract any more.
Since electronegativity measures the amount of attraction between an atom and an electron, noble gases do not have electronegativity.
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MCQ 21 Mark
The anomalous behaviour of nitrogen is due to:
  • A
    Small size and high electronegativity.
  • B
    Non availability of $d-$orbitals in valency shell.
  • C
    Ease of multiple bond formation.
  • All are correct.
Answer
Correct option: D.
All are correct.
Nitrogen differs from other members of the group due to its smaller size, high electronegativity, high $IE$ and non availability of $d-$orbitals. Nitrogen has unique ability to form $\text{p}\pi-\text{p}\pi$ multiple bonds with itself and with other elements having small size and high electronegativity.
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MCQ 31 Mark
Compounds formed when the noble gases get entrapped in the cavities of crystal lattices of certain organic and inorganic compounds are known as:
  • A
    Interstitial compounds.
  • Clathrates.
  • C
    Hydrates.
  • D
    Picrates.
Answer
Correct option: B.
Clathrates.
Clathrates $($also known as cage compounds$)$ are compounds of noble gases in which they are trapped within cavities of crystal lattices of certain organic and inorganic substances.
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MCQ 41 Mark
In the preparation of $\mathrm{HNO}_3,$ we get $NO$ gas by catalytic oxidation of ammonia. The moles of $NO$ produced by the oxidation of two moles of $\mathrm{NH}_3$ will be $......$
  • $2$
  • B
    $3$
  • C
    $4$
  • D
    $6$
Answer
Correct option: A.
$2$
Two moles of $\mathrm{NH}_3$ will produce $2$ moles of $NO$ on catalytic oxidation of ammonia in preparation of nitric acid.
$4\text{NH}_3+5\text{O}_2\xrightarrow[\text{Pt(Rh gauge catalyst)}]{\Delta} 4\text{NO}(\text{g})+6\text{H}_2\text{O}(\text{l})$
Hence$, 2$ moles of ammonia will produce $2$ moles of $NO.$
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MCQ 51 Mark
The inert gas present in the second long period is:
  • A
    $Kr$
  • $Xe$
  • C
    $Ar$
  • D
    $Rn$
Answer
Correct option: B.
$Xe$
Periods $4$ and $5$ are called long periods as they contain $18$ elements each.
$4^{th}$ period is called the first long period and the inert gas in this period is $Kr.$
$5^{th}$ period is the second long period where $Xe$ is the inert gas element.
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MCQ 61 Mark
Bond dissociation enthalpy of $E-H (E =$ element$)$ bonds is given below. Which of the compounds will act as strongest reducing agent?
Compound $\ce{NH_3}$ $\ce{PH_3}$ $\ce{AsH_3}$ $\ce{SbH_3}$
$\Delta_{\text{diss}}(\text{E}-\text{H})/\text{kJ mol}^{-1}$ $389$ $322$ $297$ $255$
  • A
    $\ce{NH_3}$
  • B
    $\ce{PH_3}$
  • C
    $\ce{AsH_3}$
  • $\ce{SbH_3}$
Answer
Correct option: D.
$\ce{SbH_3}$
On moving down the group size of the central atom increases i.e. bond length increases and bond dissociation enthalpy decreases.
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MCQ 71 Mark
$\text{VA}$ group elements are known as:
  • A
    Halogens.
  • B
    Normal elements.
  • C
    Chalcogens.
  • Pnicogens.
Answer
Correct option: D.
Pnicogens.
Halogens$:\ \text{VIIA}$
Chalcogens$:\ \text{VIA}$
Pnicogens$:\ \text{VA}$
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MCQ 81 Mark
Hydrates of helium and neon have not been prepared because of:
  • A
    Low polarisability.
  • B
    Small size.
  • C
    Low boiling point.
  • All of the above.
Answer
Correct option: D.
All of the above.
When water is allowed to freeze in the presence of $\text{Ar, Kr}$ or $Xe$ under pressure, atoms of noble gas get trapped in the crystal lattice of ice giving clathrates corresponding to the composition, $8 \mathrm{G} .46 \mathrm{H}_2 \mathrm{O} (G =$ noble gas$).$ These clathrates are also known as the noble gas hydrates. But due to small size, low boiling point and low polarisability, He and Ne are unable to trap so they do not form.
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MCQ 91 Mark
Fluorine shows anomalous behavior in $\text{VIIA}$ group due to:
  • A
    Its small size.
  • B
    High electronegativity.
  • C
    Absence of $d-$orbitals.
  • All the above.
Answer
Correct option: D.
All the above.
Second period elements show anomalous behavior due to small size, high electronegativity and absence of $d-$orbitals and fluorine is a second period element
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MCQ 101 Mark
What is found in silver deposits?
  • A
    Phosphorous
  • B
    Bismuth
  • C
    Copper
  • Antimony
Answer
Correct option: D.
Antimony
Silver is found in a native form very rarely as nuggets, but more usually combined with sulfur, arsenic, antimony, or chlorine and in various ores such as argentite $\mathrm{Ag}_2 \mathrm{S},$ chlorargyrite $''$horn silver$,'' \text{AgCl}),$ and galena $($a lead ore often containing significant amounts of silver$).$
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MCQ 111 Mark
Which of the following statements are true?
$a.$ Only type of interactions between particles of noble gases are due to weak dispersion forces.
$b.$ Ionisation enthalpy of molecular oxygen is very close to that of xenon.
$c.$ Hydrolysis of $\ce{XeF_6}$ is a redox reaction.
$d.$ Xenon fluorides are not reactive.
  • $a$ and $b$
  • B
    $a$ and $c$
  • C
    $b$ and $c$
  • D
    $a$ and $d$
Answer
Correct option: A.
$a$ and $b$
Weak dispersion forces are present between particles of noble gases. Ionization enthalpy of molecular oxygen is very close to that of xenon.
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MCQ 121 Mark
Calcium cyanamide on treatment with steam under pressure gives ammonia and:
  • Calcium carbonate.
  • B
    Calcium hydroxide.
  • C
    Calcium oxide.
  • D
    Calcium bicarbonate.
Answer
Correct option: A.
Calcium carbonate.
$\mathrm{CaCN}_2+3 \mathrm{H}_2 \mathrm{O} \rightarrow \mathrm{CaCO}_3+2 \mathrm{NH}_3$​
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MCQ 131 Mark
On heating with concentrated $\text{NaOH}$ solution in an inert atmosphere of $\ce{CO_2}$, white phosphorus gives a gas. Which of the following statement is incorrect about the gas?
  • A
    It is highly poisonous and has smell like rotten fish.
  • B
    It’s solution in water decomposes in the presence of light.
  • It is more basic than $\ce{NH_3}$
  • D
    It is less basic than $\ce{NH_3}$.
Answer
Correct option: C.
It is more basic than $\ce{NH_3}$
White phosphorous is poisonous, insoluble in water but soluble in carbon disulphide and glows in dark $($chemiluminescence$).$ It dissolves in boiling $\text{NaOH}$ solution in an inert atmosphere giving $\ce{PH_3}$.
$\text{P}_4+3\text{NaOH}+3\text{H}_2\text{O}\xrightarrow{\ \ \ \ \ \ \ \ }\text{PH}_3+3\text{NaH}_2\text{PO}_2$
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MCQ 141 Mark
Which one of these group off elements is also called the halogen family?
  • A
    Group $16$
  • B
    Group $18$
  • C
    Group $10$
  • Group $17$
Answer
Correct option: D.
Group $17$
Group $17$ is also called halogen family.
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MCQ 151 Mark
Which is the most thermodynamically stable allotropic form of phosphorus?
  • A
    Red
  • B
    White
  • Black
  • D
    Yellow
Answer
Correct option: C.
Black
Black phosphorus is the most thermodynamically stable allotropic form of phosphorus.
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MCQ 161 Mark
With reference to Haber's process, the required catalyst used is:
  • A
    Iron oxide.
  • B
    Aluminium oxide.
  • C
    Magnesium oxide.
  • All of the above.
Answer
Correct option: D.
All of the above.
$\mathrm{N}_2+3 \mathrm{H}_2 \rightarrow 2 \mathrm{NH}_3$
Haber$-$Bosch process involves the direct reaction of hydrogen and nitrogen. This reaction requires the use of a catalyst high pressure$(100−1000\ atm)$ and elevated temperature$(400−550^\circ C).$ The catalyst can be iron oxide, magnesium oxide, aluminium oxide.
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MCQ 171 Mark
Anomalous behaviour of oxygen, compared to other $\text{VI A}$ group elements is due to:
  • A
    Its high electronegativity.
  • B
    Its small atomic size.
  • C
    Non availability of $d-$orbitals.
  • All.
Answer
Correct option: D.
All.
Oxygen is the first element of $\text{VI A}$ group and shows Anaomalous behaviour than other group elements because
  1. High Electronegativity
  2. small atomic size
  3. Non$-$avalability of $d-$orbits results in different compounds than their other group elements.
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MCQ 181 Mark
Which of the following elements does not show allotropy?
  • Nitrogen.
  • B
    Bismuth.
  • C
    Antimony.
  • D
    Arsenic.
Answer
Correct option: A.
Nitrogen.
The single $N-N$ bond is weak because of high inter$-$electronic repulsion of the non$-$bonding electrons, owing to the small bond length. As a result the catenation tendency is weaker in nitrogen that is why it does not show allotropy.
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MCQ 191 Mark
The percentage of $p-$character in the orbitals forming $P−PP−P$ is:
  • A
    $25$
  • B
    $33$
  • C
    $50$
  • $75$
Answer
Correct option: D.
$75$
In $P_4​,$ all $P$ atoms are in $sp^3$ hybridization so $p-$character in the orbitals forming $PP$ bonds $100\times\frac{3}{4}=75\%$
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MCQ 201 Mark
Viscosity is very low for?
  • A
    $Ar$
  • B
    $Xe$
  • $He$
  • D
    $Kr$
Answer
Correct option: C.
$He$
Noble gases have low melting and boiling point and lowest boiling point among them is of $He\ (4.2K).$ This is because they have only type of inter$-$atomic interaction that is weak dispersion forces.
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MCQ 211 Mark
he colour and state of phosphorus pentoxide is:
  • White crystalline solid.
  • B
    White amorphous liquid.
  • C
    Blue crystalline.
  • D
    Blue colour liquid.
Answer
Correct option: A.
White crystalline solid.
The colour and state of phosphorus pentoxide is white crystalline solid.
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MCQ 221 Mark
Magnesium on heating to redness in an atmosphere of $N_2$ and then on treating with $H_2​O$ gives?
  • $NH_3$
  • B
    $H_2$
  • C
    $N_2$​
  • D
    $O_2$
Answer
Correct option: A.
$NH_3$
Megnesium when heated with $N_2$ in atmosphere it forms magnesium nitride$(\left(\mathrm{Mg}_3 \mathrm{N}_2)\right.$ which on hydrolysis$($reaction with water$)$ gives ammonia.
$3 \mathrm{Mg}+\mathrm{N}_2 \rightarrow \mathrm{Mg}_3 \mathrm{\sim N}_2$
$\mathrm{Mg}_3 \mathrm{\sim N}_2+6 \mathrm{H}_2 \mathrm{O} \rightarrow 3 \mathrm{Mg}(\mathrm{OH})_2+2 \mathrm{NH}_3$
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MCQ 231 Mark
Rhombic, monoclinic and plastic sulphur are?
  • A
    Isomers.
  • B
    Isotopes.
  • Allotropes.
  • D
    Hydrides of sulphur.
Answer
Correct option: C.
Allotropes.
Sulfur is heated to just above the melting point,which is allowed to cool and crystallise slowly as monoclinic sulfur. Remaining sulfur is heated to boiling point, and the liquid is rapidly cooled in cold water to form plastic sulfur.Another sample of sulfur is dissolved in a hot solvent, and the solution allowed to cool and evaporate, leaving crystals of rhombic sulfur.All the observed changes in properties can be related to the different structural forms of the three solid sulfur samples $($allotropes$).$
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MCQ 241 Mark
Among these ores the highest phosphorus content is in:
  • A
    Chlorapatite.
  • Phosphorite.
  • C
    Fluorspar.
  • D
    All have equal content.
Answer
Correct option: B.
Phosphorite.
Phosphorite ore is the ore that has the highest phosphorus content.
Percentage of $P$ in phosphorite
$=\frac{69}{279}\times100=22.22\%$
In flourapatite and chlorapatite the percentage content of phosphorus is $20.32\%$ and $19.62\%$ respectively.
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MCQ 251 Mark
The oxidation state of central atom in the anion of compound $\mathrm{NaH}_2 \mathrm{PO}_2$ will be $......$
  • A
    $+3$
  • B
    $+5$
  • $+1$
  • D
    $-3$
Answer
Correct option: C.
$+1$
Oxidation state of $\mathrm{NaH}_2 \mathrm{PO}_2$
$\stackrel{{+1}}{\hbox{Na}}\stackrel{{+1}}{\hbox{ H}_2}\stackrel{{\text{n}}}{\hbox{ P}}\stackrel{{-2}}{\hbox{O}_2}$
$+1+2\times+1+\text{x}+2\times-2=0$
$+3+\text{x}-4=0$
$\text{x}-1=0$
$\text{x}=+1$
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MCQ 261 Mark
The word Argon represents the term $.......?$
  • A
    Sun
  • B
    Hidden
  • Lazy
  • D
    Stranger
Answer
Correct option: C.
Lazy
The word Argon represents the term Lazy.
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MCQ 271 Mark
Which of the following are formed by xenon?
  • A
    $\ce{XeF_7}$
  • $\ce{XeF_4}$
  • C
    $\ce{XeF_5}$​
  • D
    $\ce{XeF_3}$
Answer
Correct option: B.
$\ce{XeF_4}$
$\ce{XeF_{4^-}}$ This compound is formed by xenon.
$Xe$ compounds can contain only even no. of fluorine atoms.
$Xe$ has a complete filled $5p$ configuration.
As a result when it undergoes bonding with an odd number $(3$ or $5)$ of $F$ atoms it leaves behind one unpaired electron.
This causes the molecule to become unstable.
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MCQ 281 Mark
The outer most electronic configuration of the most electronegative element is:
  • A
    $\ce{ns^2 np^3}$
  • B
    $\ce{ns^2 np^4}$
  • $\ce{ns^2 np^5}$
  • D
    $\ce{ns^2 np^6}$
Answer
Correct option: C.
$\ce{ns^2 np^5}$
Halogens are most electronegative.
Therefore outer electronic configuration is $\ce{ns^2 np^5}.$
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MCQ 291 Mark
Inter $-$ halogen compounds can be:
  • A
    $\mathrm{ICl}_3$
  • B
    $\mathrm{BrF}_5$
  • C
    $\mathrm{IF}_7$
  • All of these
Answer
Correct option: D.
All of these
Halogens can combine and to form inter$-$halogen compounds which are highly reactive in nature.
Interhalogen Compounds as the subordinates of halogens. These are the compounds having two unique sorts of halogens. For example, the common interhalogen compounds include Chlorine monofluoride, bromine trifluoride, iodine pentafluoride, iodine heptafluoride, etc.
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MCQ 301 Mark
Which of the following noble gas is the least polarizable?
  • A
    Radon
  • B
    Krypton
  • C
    Xenon
  • Helium
Answer
Correct option: D.
Helium
Helium is the least polarizable noble gas due to presence of weakest Van der Waal's forces.
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MCQ 311 Mark
In the third excited state, the number of unpaired electrons in chlorine atom is:
  • A
    $5$
  • $7$
  • C
    $3$
  • D
    $1$
Answer
Correct option: B.
$7$
The general electronic configuration of chlorine is $[\mathrm{Ne}] 3 \mathrm{s}^2 3 \mathrm{p}^5$.
When electrons are excited in chlorine, the electrons enter into $3d$ subshell then the electronic configuration of chlorine is given as $[\mathrm{Ne}] 3s^1 3 p^3 3 d^3$
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MCQ 321 Mark
If a new noble gas is discovered then, what will be its atomic number?
  • A
    $87$
  • B
    $104$
  • $118$
  • D
    $132$
Answer
Correct option: C.
$118$
$Rn + 32 = 86 + 32 = 118$
The atomic number of next inert gas to be discovered will be $118.$
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MCQ 331 Mark
The set up shown in the diagram is for the laboratory preparation of a pungent alkaline gas. What is the name of drying agent used in the process?
  • Quick lime.
  • B
    Magnesium oxide.
  • C
    Calcium carbonate.
  • D
    None of these.
Answer
Correct option: A.
Quick lime.
Drying Agent is $\text{CaO}\ ($Quick lime$).$ It is used to dry ammonia gas.
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MCQ 341 Mark
Inversion temperature of helium is very low. So when helium is allowed to expand into vacuum it gets:
  • A
    Cooled.
  • Heated.
  • C
    Neither cooled, nor heated $X.$
  • D
    Liquified.
Answer
Correct option: B.
Heated.
He gets heated at their inversion temperature on expansion into vacuum.
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MCQ 351 Mark
In clathrate atoms or molecules the bond formed is:
  • A
    Metallic
  • B
    Covalent
  • C
    Ionic
  • They do not form bond
Answer
Correct option: D.
They do not form bond
In clathrate bond is not formed. There is only dipole- induced dipole interaction which is not a bond.
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MCQ 361 Mark
In the manufacture of ammonia, the catalyst used is:
  • Magnesium oxide.
  • B
    Silver.
  • C
    Gold.
  • D
    Nickel.
Answer
Correct option: A.
Magnesium oxide.
Several catalysts are being utilized. The catalyst is iron containing iron oxide, magnesium oxide, aluminium oxide and ruthenium on carbon.
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MCQ 371 Mark
Which is the strongest oxidising agent out of the following?
  • A
    $\mathrm{I}_2$
  • B
    $\mathrm{Cl}_2$
  • C
    $\mathrm{Br}_2$
  • $\mathrm F_2$
Answer
Correct option: D.
$\mathrm F_2$
Fluorine is such a powerful oxidising agent that you can't reasonably do solution reactions with it.
Standard Reduction Potential for fluorine is $2.87 V.$
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MCQ 381 Mark
The element which can displace three other halogens from their compound is:
  • A
    $Cl$
  • B
    $Br$
  • C
    $I$
  • $F$
Answer
Correct option: D.
$F$
$F$ can displace other halogens from their compounds due to its oxidising nature $($Reaction will be feasible$).$
Reactivity decreases from $F$ to $I.$
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MCQ 391 Mark
Nitrogen is liberated by the thermal decomposition of only:
  • A
    $\mathrm{NH}_4 \mathrm{NO}_2$
  • B
    $\mathrm{NaN}_3$
  • C
    $\left(\mathrm{NH}_4\right)_2 \mathrm{Cr}_2 \mathrm{O}_7$
  • All of these
Answer
Correct option: D.
All of these
Nitrogen is liberated by the thermal decomposition of ammonium nitrite.
$\left(\mathrm{NH}_4 \mathrm{NO}_2\right), \mathrm{NaN}_3,\left(\mathrm{NH}_4\right)_2 \mathrm{Cr}_2 \mathrm{O}_7$
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MCQ 401 Mark
Which of the following statements are correct?
$a.$ All the three $N—O$ bond lengths in $\mathrm{HNO}_3$ are equal.
$b.$ All $P—Cl$ bond lengths in $\ce{PCl_5}$ molecule in gaseous state are equal.
$c. P_4$ molecule in white phohsphorus have angular strain therefore white phosphorus is very reactive.
$d. \text{PCl}$ is ionic in solid state in which cation is tetrahedral and anion is octahedral.
  • A
    $a$ and $b$
  • B
    $b$ and $c$
  • C
    $a$ and $c$
  • $c$ and $d$
Answer
Correct option: D.
$c$ and $d$
  1. All the three $N – O$ bond lengths in $\mathrm{HNO}_3$ are not equal.
  2. All $\text{P – Cl}$ bond lengths in $\mathrm{PCl}_5$ molecule in gaseous state are not equal. Axial bond is longer than equatorial bond.
  3. $P_4$ molecule in white phosphorus have angular strain therefore white phosphorus is very reactive.
  4. $\mathrm{PCl}_5$ is ionic in solid state in which cation is tetrahedral and anion is octahedral.
Cation $- \left[\mathrm{PCl}_4\right]^{+}$
Anion $- \left[\mathrm{PCl}_6\right]^{-}$
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MCQ 411 Mark
Which of the following are peroxoacids of sulphur?
  • $\mathrm{H}_2 \mathrm{SO}_5$ and $\mathrm{H}_2 \mathrm{\sim S}_2 \mathrm{O}_8$
  • B
    $\mathrm{H}_2 \mathrm{SO}_5$ and $\mathrm{H}_2 \mathrm{S}_2 \mathrm{O}_7$
  • C
    $\mathrm{H}_2 \mathrm{S}_2 \mathrm{O}_7$ and $\mathrm{H}_2 \mathrm{S}_2 \mathrm{O}_8$
  • D
    $\mathrm{H}_2 \mathrm{S}_2 \mathrm{O}_6$ and $\mathrm{H}_2 \mathrm{S}_2 \mathrm{O}_7$
Answer
Correct option: A.
$\mathrm{H}_2 \mathrm{SO}_5$ and $\mathrm{H}_2 \mathrm{\sim S}_2 \mathrm{O}_8$
Peroxoacids of sulphur must contain one $-O – O –$ bond as shown below.
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MCQ 421 Mark
The most abundant element in the earth's crust among the following is $.......$
  • $P$
  • B
    $As$
  • C
    $Sb$
  • D
    $Bi$
Answer
Correct option: A.
$P$
The most abundant element among the given elements in the earth's crust is phosphorus.
It occurs in the minerals of the apatite family. An example is a fluorapatite $\mathrm{Ca}_9\left[\mathrm{PO}_4\right]_6 \cdot \mathrm{CaF}_2$
Phosphorus is the most abundant element of $15^{th}$ group, accounting for $0.10\%$ of the mass of the earth's crust.
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MCQ 431 Mark
A black compound of manganese reacts with a halogen acid to give greenish yellow gas. When excess of this gas reacts with $\mathrm{NH}_3$ an unstable trihalide is formed. In this process the oxidation state of nitrogen changes from $........$
  • A
    $-3$ to $+3$
  • B
    $-3$ to $0$
  • $-3$ to $+5$
  • D
    $0$ to $-3$
Answer
Correct option: C.
$-3$ to $+5$
$\text{Mn0}_2+4\text{HCl}\xrightarrow{\ \ \ \ \ \ \ \ \ \ }\text{MnCl}_2+2\text{H}_2\text{O}+\text{Cl}$
$($greenish yellow gas$)$
When excess of $\mathrm{Cl}_2$ reacts with $\mathrm{NH}_3$ the products are $\mathrm{NCl}_3$ and $\text{HCl}.$
$\text{NH}_3+3\text{Cl}_2\xrightarrow{\ \ \ \ \ \ \ \ \ }\text{NCl}_3+3\text{HCl}\\\text{O.S.}(-3)\text{O.S.}(+3)$
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MCQ 441 Mark
Which of the following is a tetratomic element?
  • Phosphorus.
  • B
    Iron.
  • C
    Calcium.
  • D
    None of the above.
Answer
Correct option: A.
Phosphorus.
Tetra atomic elements are those which are made up of four atoms.
A common and biologically important element that consists as molecules of four atoms chemically bonded together is the element phosphorus.
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MCQ 451 Mark
On heating ammonium dichromate and barium azide separately we get
  • $\mathrm{N}_2$ in both cases.
  • B
    $\mathrm{N}_2$ with ammonium dichromate and $NO$ with barium azide.
  • C
    $\mathrm{N}_2 \mathrm{O}$ with ammonium dichromate and $\mathrm{N}_2$ with barium azide.
  • D
    $\mathrm{N}_2 \mathrm{O}$ with ammonium dichromate and $\mathrm{NO}_2$ with barium azide.
Answer
Correct option: A.
$\mathrm{N}_2$ in both cases.
$(\text{NH}_4)_2\text{Cr}_2\text{O}_7\xrightarrow{\ \ \ \ \ \ \ \ \ }\text{N}_2+\text{Cr}_2\text{O}_3+4\text{H}_2\text{O}$
$\text{Ba}(\text{N}_3)_2\xrightarrow{\ \ \ \ \ \ \ \ \ }3\text{N}_2+\text{Ba}$
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MCQ 461 Mark
The molecular formula of phosphorous is:
  • A
    $P_1$
  • $P_4$
  • C
    $P_2$
  • D
    $P_5$
Answer
Correct option: B.
$P_4$
The molecular formula of phosphorous is $P_4$.
White phosphorus, in gaseous state and as waxy solid consists of $P_4$​ tetrahedra.
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MCQ 471 Mark
At low temperatures, nitrogen:
  • A
    Is poisonous.
  • B
    Is highly soluble in water.
  • Can be liquefied on compression.
  • D
    Dissociates to form nascent nitrogen.
Answer
Correct option: C.
Can be liquefied on compression.
At low temperatures nitrogen can be liquefied on compression.
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MCQ 481 Mark
In the manufacture of ammonia, what is the ratio of the reactants taken, i.e. $N_2: H_2​?$
  • A
    $1 : 1$
  • B
    $1 : 3$
  • $3 : 1$
  • D
    $2 : 3$
Answer
Correct option: C.
$3 : 1$
Reactants taken for commercial production of ammonia is nitrogen and hydrogen in the presence of catalyst, high temperature and high pressure.
$\mathrm{N}_2+3 \mathrm{H}_2 \rightarrow 2 \mathrm{NH}_3$​
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MCQ 491 Mark
In the preparation of ammonia gas from ammonium chloride and calcium hydroxide, the reactants are ground thoroughly $......?$
  • To provide maximum surface area.
  • B
    To provide maximum surface area.
  • C
    To increase the number of particle.
  • D
    None of these.
Answer
Correct option: A.
To provide maximum surface area.
In the preparation of ammonia gas from ammonium chloride and calcium hydroxide, the reactants are ground thoroughly to provide a maximum surface area of the reactants which helps in speeding up the reaction.
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MCQ 501 Mark
Argon was discovered by:
  • A
    Rayleigh
  • B
    Ramsay
  • Both $(A)$ and $(B)$
  • D
    Frankland and Lockeyer
Answer
Correct option: C.
Both $(A)$ and $(B)$
Argon was discovered by Lord Rayleigh and Sir William Ramsay in $1894.$
It was isolated by examination of the residue obtained by removing nitrogen, oxygen, carbon dioxide, and water from clean air.
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MCQ 511 Mark
Which of the following is isoelectronic pair?
  • A
    $\text{ICl}_2,\ \text{ClO}_2$
  • $\text{BrO}_2^-,\ \text{BrF}_2^+$
  • C
    $\text{ClO}_2,\ \text{BrF}$
  • D
    $\text{CN}^-,\ \text{O}_3$
Answer
Correct option: B.
$\text{BrO}_2^-,\ \text{BrF}_2^+$
Isoelectronic pair have same number of electrons.
  1. $\begin{cases}\text{ICl}_2=53+2\times17=87\\\text{ClO}_2=17+16=33\end{cases}$
  2. $\begin{cases}\text{BrO}_2^-=35+2\times8+1=52\\\text{BrF}_2^+=35+9\times2-1=52\end{cases}$
  3. $\begin{cases}\text{ClO}_2=17+16=33\\\text{BrF}=35+9=44\end{cases}$
  4. $\begin{cases}\text{CN}^-=6+7+1=14\\\text{O}_3=8\times3=24\end{cases}$
Hence, only $(b)$ is the correct choice.
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MCQ 521 Mark
Fluorine is highly reactive because:
  • A
    $F-F$ bond energy is high.
  • $F-F$ bond energy is low.
  • C
    it is gaseous at room temperature.
  • D
    $F$ has a smaller size.
Answer
Correct option: B.
$F-F$ bond energy is low.
$F_2$​ is highly reactive because of its low bond energy. Also, it has the highest electronegativity.
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MCQ 531 Mark
Which is called lazy gas?
  • A
    $Kr$
  • $Ar$
  • C
    $He$
  • D
    $Ne$
Answer
Correct option: B.
$Ar$
Argon is lazy gas because during his experiments to remove all gases from air, Sir William Ramsay kept getting the same proportion of an inert gas left behind. He did a lot of experiments to make this gas react with most reactive substance like fluorine, potassium etc. but it did not react with anything. He named this gas argon from a Greek word 'Argos' which means lazy or inert or inactive.
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MCQ 541 Mark
The catalytic promoter used in Haber's process is:
  • $Mo$
  • B
    $Ni$
  • C
    $Pt$
  • D
    $\ce{V_2​O_5}$
Answer
Correct option: A.
$Mo$
$Mo$ is used as catalytic promoter in Haber's process.
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MCQ 551 Mark
The bond energy of $N ≡ N$ per mole is:
  • A
    $180$ kcal
  • $225$ kcal
  • C
    $350$ kcal
  • D
    $120$ kcal
Answer
Correct option: B.
$225$ kcal
The bond energy of $N_2$​ per mole is $225$ kcal or $945KJ/ mol.$
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MCQ 561 Mark
Maximum covalency of nitrogen is $.......$
  • A
    $3$
  • B
    $5$
  • $4$
  • D
    $6$
Answer
Correct option: C.
$4$
Maximum covalency of nitrogen is four as it cannot extend its valency beyond four $\left[\mathrm{NH}_4, \mathrm{R}_4 \mathrm{\sim N}\right]$ due to absence of vacant orbitals.
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MCQ 571 Mark
Which element is monoatomic gas at room temperature?
  • $Ne$
  • B
    $F$
  • C
    $\mathrm{O}_2$​
  • D
    $\mathrm{\sim N}_2$
Answer
Correct option: A.
$Ne$
$Ne$ is noble gas so it will exists as monoatomic gas at room temperature.
All other gases exists in dimer form as $\mathrm{F}_2, \mathrm{~N}_2$ and $\mathrm{O}_2$
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MCQ 581 Mark
Nitrogen can exhibit which of the following oxidation states:
  • A
    $+1$
  • B
    $+2$
  • C
    $+3$
  • all of the above
Answer
Correct option: D.
all of the above
Nitrogen forms oxides in which nitrogen exhibits each of its positive oxidation numbers from $+1$ to $+5.$
$\ce{N_2O}$ has nitrogen in the $+1$ oxidation state,$ NO$ has $+2$ and $\ce{NO_2}$​ has $+4$ oxidation state.
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MCQ 591 Mark
The noble gas which has abnormal behaviour in its liquid state is $.......$
  • $He$
  • B
    $Ar$
  • C
    $Xe$
  • D
    $Ne$
Answer
Correct option: A.
$He$
Helium has abnormal behavior in its liquid state due to its small size and nearly ideal behavior.
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MCQ 601 Mark
The inert gas which cannot be adsorbed over activated coconut charcoal?
  • A
    $Ne$
  • B
    $Ar$
  • $He$
  • D
    $Kr$
Answer
Correct option: C.
$He$
Due to small size of helium, it can not be absorbed over activated coconut charcoal.
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MCQ 611 Mark
Affinity for hydrogen decreases in the group from fluorine to iodine. Which of the halogen acids should have highest bond dissociation enthalpy?
  • $HF$
  • B
    $\text{HCl}$
  • C
    $\text{HBr}$
  • D
    $HI$
Answer
Correct option: A.
$HF$
$HF$ On moving top to bottom $\text{HCl}$ Size of halogen atom increases $\ce{HBr H-X}$ bond length increases $HI$ Bond dissociation enthalpy decreases.
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MCQ 621 Mark
Major minerals containing nitrogen are:
  • A
    $\text{DNA}$
  • B
    $\text{RNA}$
  • $\ce{KNO_3, NaNO_3}$
  • D
    All of these
Answer
Correct option: C.
$\ce{KNO_3, NaNO_3}$
Nitrogen gas makes up about $78%$ of the atmosphere by volume. There are relatively major minerals containing nitrogen as nitrates are 'saltpetre' $(\ce{NaNO_3})$ and $\ce{KNO_3}$.
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MCQ 631 Mark
Which of the following has the highest density?
  • A
    $Ne$
  • B
    $Ar$
  • C
    $He$
  • $Xe$
Answer
Correct option: D.
$Xe$
The density of elements increases down the group. So, the density of xenon is the highest. The density of $Xe$ is the highest.
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MCQ 641 Mark
$.......$ bacteria are microbes that work in the absence of oxygen.
  • Anaerobic.
  • B
    Aerobic.
  • C
    Gram$-$positive.
  • D
    Gram$-$negative.
Answer
Correct option: A.
Anaerobic.
Anaerobic bacteria works in the absence of oxygen.
Example is yeast.
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MCQ 651 Mark
Which of the following substance is stored under water:
  • White phosphorus.
  • B
    Red phosphorus.
  • C
    Sodium metal.
  • D
    Both white phosphorous and red phosphorus.
Answer
Correct option: A.
White phosphorus.
White phosphorous is very reactive therefore it is stored under water.
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MCQ 661 Mark
The inert gas atom in which the total number of $d-$electrons is equal to the difference in numbers of total $p−$ and $s−$electrons, is:
  • A
    $He$
  • B
    $Ne$
  • C
    $Ar$
  • $Kr$
Answer
Correct option: D.
$Kr$
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MCQ 671 Mark
Fluorine, chlorine, bromine, and iodine form a family of related elements, known as:
  • A
    Light gases.
  • Halogens.
  • C
    Purines.
  • D
    The aromatic ring.
Answer
Correct option: B.
Halogens.
Fluorine, chlorine, bromine, and iodine form a family of the related elements called “halogens” because they give salts when they react with metals.
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MCQ 681 Mark
To prepare $\ce{XeF_6}$​ at $573K, 50 - 60\ atm$ pressure, the ratio of xenon and fluorine used is:
  • A
    $1 : 2$
  • B
    $1 : 5$
  • $1 : 20$
  • D
    $10 : 1$
Answer
Correct option: C.
$1 : 20$
The ratio of xenon and fluorine is $1 : 20$ at $573K, 50 - 60\ atm$ pressure to prepare $\ce{XeF_6​}.$
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MCQ 691 Mark
According to Coulson the high reactivity of fluorine than other halogens is because of its:
  • A
    High electronegativity.
  • B
    Lesser internuclear repulsions.
  • Greater repulsions between non bonding electrons.
  • D
    All the above.
Answer
Correct option: C.
Greater repulsions between non bonding electrons.
According to Coulson, since fluorine atoms are small it's intermolecular repulsion is appreciable. The large electron$-$electron repulsion between the lone pairs of electrons on the fluorine atom weakens the bond.
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MCQ 701 Mark
Which of the following electronic configuration corresponds to an inert gas?
  • A
    $\ce{1 s^1 2 s^2 2 p^5}$
  • $\ce{1 s^2 2 s^2 2 p^6}$
  • C
    $\ce{1 s^2 2 s^1}$
  • D
    $\ce{1 s^2 2 s^2 2 p^6 3 s^1}$
Answer
Correct option: B.
$\ce{1 s^2 2 s^2 2 p^6}$
Noble gases have full$-$filled configuration i.e the subshell are completely filled.
They have the general electronic configuration as $\ce{ns^2np^6}$.
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MCQ 711 Mark
The valance electron present in group $17$ elements is:
  • A
    $1$
  • B
    $2$
  • C
    $6$
  • $7$
Answer
Correct option: D.
$7$
Group $17$ elements has outer configuration as $\ce{ns^2 np^5}$ so this group has $7$ valence electrons.
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MCQ 721 Mark
An alkaline gas, which produces dense white fumes when reacted with $\text{HCl}$ gas is $........$
  • Ammonia.
  • B
    Chlorine.
  • C
    Nitrogen.
  • D
    Oxygen.
Answer
Correct option: A.
Ammonia.
An alkaline gas which produces dense white fumes when reacted with $\text{HCl}$ gas is ammonia and fumes are of compound ammonium chloride.
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MCQ 731 Mark
$\ce{BrF_5}$​ is a:
  • Interhalogen compound.
  • B
    Pseudohalogen compound.
  • C
    Both the above.
  • D
    None of the above.
Answer
Correct option: A.
Interhalogen compound.
Inter halogen compounds are the compounds in which one halogen combines with other halogen.
$\ce{BrF_5}$ is an inter halogen compound. In this compound, bromine combines with fluorine.
Pseudohalogens on the other hand are covalent dimers and contains two or more electronegative atoms out of which at least one is nitrogen.
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MCQ 741 Mark
In the preparation of compounds of $Xe,$ Bartlett had taken $\text{O}_2^+\text{Pt}\text{ F}_6^-$ as a base compound. This is because
  • A
    both $O_2$ and $Xe$ have same size.
  • B
    both $O_2$ and $Xe$ have same electron gain enthalpy.
  • both $O_2$ and $Xe$ have almost same ionisation enthalpy.
  • D
    both $Xe$ and $O_2$ are gases.
Answer
Correct option: C.
both $O_2$ and $Xe$ have almost same ionisation enthalpy.
Neil Bartlett then observed the reaction of a noble gas. First, he prepared a red compound which is formulated as $\text{O}_2^+\text{Pt}\text{ F}_6^-$. He then realised that the first ionisation enthalpy of molecular oxygen $\ce{(1175 kJ mol^{-1})}$ was almost identical with that of xenon $\ce{(1170 kJ\ mol^{-1})}.$
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MCQ 751 Mark
For the inert gases, the value of coefficient of expansion is:
  • A
    $1.33$
  • B
    $1.40$
  • $1.66$
  • D
    can't be predicted
Answer
Correct option: C.
$1.66$
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MCQ 761 Mark
Which of the following is a noble gas?
  • $He$
  • B
    $N_2$
  • C
    $H_2$
  • D
    $O_2$
Answer
Correct option: A.
$He$
He is a noble gas with $2$ electrons in outer shell.
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MCQ 771 Mark
Industrially, ammonia is obtained by direct combination between nitrogen and hydrogen. The formation of ammonia is promoted at:
  • A
    $\text{1000 atm}$
  • $\text{200 atm}$
  • C
    $\text{25 atm}$
  • D
    $\text{1 atm}$
Answer
Correct option: B.
$\text{200 atm}$
Ammonia is prepared industrially by Haber's process.
In this process, dinitrogen directly reacts with Dihydrogen in $1 : 3$ in presence of iron catalyst with promoters as oxides of potassium or aluminium. The physical conditions required for this process are $\text{200−300 atm}$ pressure and $400−450^\circ C$ temperature.
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MCQ 781 Mark
Fluorine does not show variable oxidation states because $......?$
  • A
    It is a halogen.
  • Of absence of $d-$orbitals.
  • C
    Absence of $s-$orbital.
  • D
    Absence of $p-$orbitals.
Answer
Correct option: B.
Of absence of $d-$orbitals.
Fluorine cannot expand its octet due to absence of $d-$orbitals.
Therefore it cannot show variable oxidation states.
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MCQ 791 Mark
Halogens means:
  • A
    Ore forming elements.
  • Sea salt products.
  • C
    Inert gases.
  • D
    Rare gases.
Answer
Correct option: B.
Sea salt products.
Sea salt $\rightarrow $ like $\ce{Mgcl_2, MgBr_2}$ have halogens.
$\therefore$ Halogens are sea salt products.
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MCQ 801 Mark
Which is soluble in water:
  • A
    $\text{AgCl}$
  • B
    $\text{AgBr}$
  • C
    $\text{AgI}$
  • $\text{AgF}$
Answer
Correct option: D.
$\text{AgF}$
Ionic compounds are soluble in water
In $\ce{AgF F^-}$ is small onion with high charge density so less polarisation and less covalent character in the whole group of Ag holdies.
$\text{AgF}$ is most Ionic in nature.
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MCQ 811 Mark
Which of the following is not the allotropic form of sulphur?
  • Roll sulphur.
  • B
    Monoclinic sulphur.
  • C
    Plastic sulphur.
  • D
    Rhombic sulphur.
Answer
Correct option: A.
Roll sulphur.
Allotropes are defined as chemical elements which exist in two or more different forms, in the same physical state.
or allotropes are defined as different structural modifications of an element, the atoms of the element are bonded together in a different manner.
At present, about $30$ well$-$characterized sulphur allotropes are known.
Commonly known allotropes of sulphur are:
Rhombic sulphur.
Monoclinic sulphur.
Plastic sulphur $($also known as gamma$-$sulphur$).$
Roll sulphur is not the allotropic form of sulphur.
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MCQ 821 Mark
Which of the following is the Metallic element in group$-15?$
  • A
    $As$
  • B
    $Sb$
  • $Bi$
  • D
    $P$
Answer
Correct option: C.
$Bi$
Down the group metallic properties increases $Bi$ is the metallic element in group$-15$
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MCQ 831 Mark
Compounds formed when the noble gases get entrapped in the cavities of crystal lattices of certain organic and inorganic compounds are known as:
  • A
    Interstitial compounds
  • Clathrates
  • C
    Hydrates
  • D
    Picrates
Answer
Correct option: B.
Clathrates
Clathrates $($also known as cage compounds$)$ are compounds of noble gases in which they are trapped within cavities of crystal lattices of certain organic and inorganic substances.
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MCQ 841 Mark
During fractional evaporation of liquid air, nitrogen comes out as a fraction along with:
  • A
    $\text{Ar, Kr, Xe}$
  • B
    Only $Ar$
  • $He$ and $Ne$
  • D
    $\text{Kr, Xe}$
Answer
Correct option: C.
$He$ and $Ne$
$He$ and $Ne$ are obtained during fractional evaporation of liquid air as their boiling point is less. due to weak interaction between molecules.
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MCQ 851 Mark
Phosphorus normally exhibits a covalency of:
  • $+3$ and $+5$
  • B
    $+2$ and $+3$
  • C
    $+1$ and $+2$
  • D
    $+3$ and $+4$
Answer
Correct option: A.
$+3$ and $+5$
Phosphorous acid $\ce{H_3PO_3},$ metaphosphorous acid $\ce{HPO_2}$​ has $+3$ oxidation state.
Pyrophosphoric acid $\ce{H_4P_2O_7}$​, orthophosphoric acid $\ce{H_3PO_4}$​ has $+5$ oxidation state.
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MCQ 861 Mark
Mono atomic element among the following is:
  • A
    Phosphorus
  • B
    Oxygen
  • Krypton
  • D
    Sulphur
Answer
Correct option: C.
Krypton
Oxygen is diatomic gas.
Phosphorous is tetra atomic.
Sulphur is polyatomic.
Whereas being an inert gas, Krypton is monoatomic.
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MCQ 871 Mark
High reactivity of white phosphorus is due to:
  • Unusual bonding that produces considerable strain.
  • B
    High solubility in water.
  • C
    Oxide layer made on it.
  • D
    All of the above.
Answer
Correct option: A.
Unusual bonding that produces considerable strain.
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MCQ 881 Mark
Clathrates are $.......$
  • A
    Inert gases.
  • Inert gases $+$ organic or inorganic compounds.
  • C
    Halogen $+$ carbon black.
  • D
    Halogen $+$ transition elements.
Answer
Correct option: B.
Inert gases $+$ organic or inorganic compounds.
Clathrates compound are non$-$stoichiometric in nature.
They have a host molecule which could be a organic or inorganic compound while the guest molecule is inert gases.
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MCQ 891 Mark
Assuming that the seventh period is $32$ members long, what should be the atomic number of the noble gas following radon $(Rn)?$
  • A
    $120$
  • $118$
  • C
    $116$
  • D
    $122$
Answer
Correct option: B.
$118$
The atomic number of $Rn$ is $86.$
The atomic number of the noble gas following $Rn$ will be $86 + 32 = 118.$
The alkali metal following francium $(Fr)$ has $Z = 119,$
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MCQ 901 Mark
Which of the following statements is wrong?
  • Single $N–N$ bond is stronger than the single $P–P$ bond.
  • B
    $\ce{PH_3}$ can act as a ligand in the formation of coordination compound with transition elements.
  • C
    $\ce{NO_2}$ is paramagnetic in nature.
  • D
    Covalency of nitrogen in $\ce{N_2O_5}$ is four.
Answer
Correct option: A.
Single $N–N$ bond is stronger than the single $P–P$ bond.
$N-N$ bond is weaker than the single $P-P$ bond. because of high interelectronic repulsion of the non$-$bonding electrons, owing to the small bond length.
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MCQ 911 Mark
Hot conc. $\mathrm{H}_2 \mathrm{SO}_4$ acts as moderately strong oxidising agent. It oxidises both metals and nonmetals. Which of the following element is oxidised by conc. $\mathrm{H}_2 \mathrm{SO}_4$ into two gaseous products?
  • A
    $Cu$
  • B
    $S$
  • $C$
  • D
    $Zn$
Answer
Correct option: C.
$C$
Hot concentrated sulphuric acid is a moderately strong oxidising agent. In this respect, it is intermediate between phosphoric and nitric acids. Both metals and non$-$metals are oxidised by concentrated sulphuric acid, which is reduced to $SO_2. C$ is oxidised into two gaseous products.
$\text{C}+2\text{H}_2\text{SO}_4(\text{conc.})\xrightarrow{\ \ \ \ \ \ \ \ \ }\text{CO}_2+2\text{SO}_2+2\text{H}_2\text{O}$
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MCQ 921 Mark
Which of the following statements are correct?
$A.$ Among halogens, radius ratio between iodine and fluorine is maximum.
$B.$ Leaving $F—F$ bond, all halogens have weaker $X—X$ bond than $X—X\ '$ bond in interhalogens.
$C.$ Among interhalogen compounds maximum number of atoms are present in iodine fluoride.
$D.$ Interhalogen compounds are more reactive than halogen compounds.
  • A
    $A ,B$ and $C$
  • B
    $A$ and $b$
  • C
    $A ,C$ and $D$
  • $A ,B$ and $D$
Answer
Correct option: D.
$A ,B$ and $D$
  1. Among group $17$ elements radius ratio of iodine and fluorine is maximum because size of iodine is largest and fluorine is smallest in the group.
  2. The correct statement is inter halogen compounds are more reactive than halogens $($except fluorine$).$ This is because $X-X\ ’$ bond in interhalogens is weaker than $X-X$ bond in halogens except $F-F.$
  3. As the ratio between radii of $X$ and $X\ ’$ increase, the number of atoms per molecule also increases. Thus, iodine $(\text{VII})$ fluoride should have maximum number of atoms as the ratio of radii between $I$ and $F$ will be maximum.
  4. Interhalogen compounds are more reactive than halogens $($except fluorine$).$ This is because $X-X\ ’$ bond in interhalogens is weaker than $X-X\ ’$ bond in halogens.
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MCQ 931 Mark
An element $X$ of group $15$ exists as diatomic molecule and combines with hydrogen at $773K$ in presence of the catalyst to form a compound, ammonia which has a characteristic pungent smell. The element $X$ is:
  • Nitrogen.
  • B
    Oxygen.
  • C
    Phosphorous.
  • D
    Sulphur.
Answer
Correct option: A.
Nitrogen.
As it is is in group $15$ it will have $5$ electrons in outermost shell, i.e, nitrogen group family. As we know that nitrogen combines with hydrogen only in the presence of platinum catalyst. Hence the given element is nitrogen.
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MCQ 941 Mark
$\ce{PCl_5​}$ molecule has:
  • A
    Three fold axis of symmetry.
  • B
    Two fold axis of symmetry.
  • Both $A$ and $B.$
  • D
    None of these.
Answer
Correct option: C.
Both $A$ and $B.$
Considering the structure as shown in above image and hybridization of $\ce{PCl_5},$ we can say that it has both three fold axis of symmetry and two fold axis of symmetry.
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MCQ 951 Mark
Bond angle in $P_4$ molecule is:
  • $60^\circ $
  • B
    $90^\circ $
  • C
    $120^\circ $
  • D
    $109^\circ 28\ ′$
Answer
Correct option: A.
$60^\circ $
Each face of the tetrahedron are equilateral.
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MCQ 961 Mark
he greater reactivity of $F_2$ is due to:
  • A
    Lower electron affinity of $F.$
  • Lower bond energy of $F - F$ bond.
  • C
    Higher electronegativity of $F.$
  • D
    Gaseous state of $F_2$.
Answer
Correct option: B.
Lower bond energy of $F - F$ bond.
The greater reactivity of $F_2$ is due to lower bond energy of $F - F$ bond and bond energy is lower because of charge repulsion between two $F$ atoms $($due to lower size of $F$ atom charge density is high and repulsion is very high so bond energy is low$)$ making its bond enthalpy lower..
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MCQ 971 Mark
Fluorine does not show positive oxidation states because:
  • It is most electronegative element.
  • B
    It forms only anions in ionic compounds.
  • C
    It cannot form multiple bonds.
  • D
    It shows non$-$bonded electron pair repulsion due to small size.
Answer
Correct option: A.
It is most electronegative element.
Fluorine is the most electronegative element so it cannot show positive oxidation state.
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MCQ 981 Mark
On heating lead nitrate forms oxides of nitrogen and lead. The oxides formed are $......$
  • A
    $\ce{N_2O, PbO}$
  • $\ce{NO_2, PbO}$
  • C
    $\text{NO, PbO}$
  • D
    $\ce{NO, PbO_2}$
Answer
Correct option: B.
$\ce{NO_2, PbO}$
$2\text{Pb}(\text{NO}_3)_2\ \xrightarrow{\ \ \ \ \ \ \ \ }\ 2\text{PbO}+4\text{NO}_2+\text{O}_2$
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MCQ 991 Mark
Nitrogen reacts with a metal $M$ to produce a compound $X.$ This compound $X,$ when dissolved in water forms pungent gas $Y$ which can be identified easily by the formation of white fumes in the presence of $\text{HCl}.$ Identify the compound $X.$
  • A
    Iron nitride.
  • Calcium nitride.
  • C
    Nitrolim.
  • D
    Sodium nitride.
Answer
Correct option: B.
Calcium nitride.
Calcium nitride dissolves in water to give ammonia gas.
Compound $X$ is $\ce{Ca3​N_2}$.
$\mathrm{Ca}_3 \mathrm{\sim N}_2+6 \mathrm{H}_2 \mathrm{O} \rightarrow 3 \mathrm{Ca}(\mathrm{OH})_2+2 \mathrm{NH}_3$
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MCQ 1001 Mark
Which one of the following does not exist?
  • A
    XeOf$_4$
  • NFe$_2$
  • C
    XeF$_2$
  • D
    XeF$_6$
Answer
Correct option: B.
NFe$_2$
(B) NeF$_2$
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MCQ 1011 Mark
Most abundant uncombined element present in atmosphere is:
  • A
    $Ca$
  • B
    $Mg$
  • C
    $Al$
  • $N$
Answer
Correct option: D.
$N$
Nitrogen gas $N_2$​ makes up about $78\%$ of the atmosphere by volume.
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MCQ 1021 Mark
A degenerate gas is:
  • A
    $He$
  • B
    $O_2$
  • $\text{He(ll)}$
  • D
    $He_2$
Answer
Correct option: C.
$\text{He(ll)}$
$\text{He(II)}$ is a degenerate gas. A degenerate gas is one where quantum mechanical effects on the electrons dominate the behavior.A degenerate electron gas can permanently withstand the self$-$gravitation. its energy cannot be radiated away.
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MCQ 1031 Mark
How is ammonia collected?
  • Ammonia is less dense than air so it is collected by upward delivery.
  • B
    Ammonia is more dense than air so it is collected by upward delivery.
  • C
    Ammonia is more dense than air so it is collected by downward delivery.
  • D
    None of the above.
Answer
Correct option: A.
Ammonia is less dense than air so it is collected by upward delivery.
Ammonia is less dense than air so it is collected by upward delivery or gas syringe method.
In upward delivery method a gas jar is connected by a tube to flask that is giving off gas.
The gas that is less dense than air rises to the top of gas jar.
The air in the gas jar is displaced until the gas jar is filled with collected gas.
Ammonia is very soluble gas so the collection apparatus should be dry and not collected over water.
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MCQ 1041 Mark
Among $VA$ group elements, the element which has highest ionization energy?
  • $N$
  • B
    $P$
  • C
    $Sb$
  • D
    $Bi$
Answer
Correct option: A.
$N$
Among $VA$ group elements, the element which has highest ionization energy is nitrogen.
The ionization energy of $VA$ group elements decreases on moving down the group $($from $N$ to $Bi),$ due to gradual increase in atomic size.
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MCQ 1051 Mark
All noble gases are:
  • A
    Colourlful.
  • Colourless and odourless.
  • C
    Colourless and but have odour.
  • D
    None of these.
Answer
Correct option: B.
Colourless and odourless.
All the noble gases are colourless and odourless gases, in addition to being chemically inert and stable.
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MCQ 1061 Mark
On addition of conc. $\mathrm{H}_2 \mathrm{SO}_4$ to a chloride salt, colourless fumes are evolved but in case of iodide salt, violet fumes come out. This is because
  • A
    $\mathrm{H}_2 \mathrm{SO}_4$ reduces $HI$ to $I_2$.
  • B
    $HI$ is of violet colour.
  • $HI$ gets oxidised to $I_2$.
  • D
    $HI$ changes to $\ce{HIO_3}$.
Answer
Correct option: C.
$HI$ gets oxidised to $I_2$.
$HI$ formed during reaction is oxidized to $I_2$ which is violet in colour.
$2\text{NaCl}+\text{H}_2\text{SO}_4\rightarrow\text{Na}_2\text{SO}_4+2\text{HCl}$
In case of iodine, the halogen acid obtained $(HI)$ is oxidized to free iodine.
$2\text{NaI}+\text{H}_2\text{SO}_4\rightarrow\text{Na}_2\text{SO}_4+2\text{HI}\ \xrightarrow{{\text{H}_2\text{SO}_4}\ \ }\ 2\text{H}_2\text{O}+\text{SO}_2+\text{I}_2$
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MCQ 1071 Mark
The reaction of $Xe$ with an excess of $F-2$​ at high pressure and $573K$ yields:
  • A
    $\ce{XeF_2}$
  • B
    $\ce{XeF_4}$
  • $\ce{XeF_6}$
  • D
    $\ce{XeF_3}$
Answer
Correct option: C.
$\ce{XeF_6}$
The reaction of $Xe$ with on excess of $F_2$ at high pressure leads to the formation of $\ce{XeF_6}$
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MCQ 1081 Mark
Which of the following is not tetrahedral in shape?
  • A
    $\text{NH}_4^+$
  • B
    $\text{SiCl}_4$
  • $\text{SF}_4$
  • D
    $\ce{SO_4}^{2-}$
Answer
Correct option: C.
$\text{SF}_4$

It has trigonal bipyramidal geometry having $\ce{sp^3d}$ hydridisation.
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MCQ 1091 Mark
Which reaction of ammonia forms the first step of Ostwald's process?
  • The catalytic oxidation of ammonia by platinum catalyst.
  • B
    The catalytic oxidation of ammonia by cobalt catalyst.
  • C
    The catalytic reduction of ammonia by platinum catalyst.
  • D
    The oxidation of ammonia.
Answer
Correct option: A.
The catalytic oxidation of ammonia by platinum catalyst.
The first step of Ostwald's process is the catalytic oxidation of ammonia by platinum catalyst for the formation of nitric acid.
$\text{NH}_3\text{O}_2\xrightarrow{\text{Pt}}\text{NO}+\text{H}_2\text{O}$
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MCQ 1101 Mark
The heat of vaporization is very high for ?
  • A
    $He$
  • B
    $Ne$
  • C
    $Ar$
  • $Xe$
Answer
Correct option: D.
$Xe$
Heat of vapourisation $\times $ van der Waal's forces $\times $ malecular mass $Xe$ has high malecular mass Therefore heat of vapourisation is very high for $Xe$
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MCQ 1111 Mark
Which of the following belongs to the halogen family?
  • A
    Francium
  • B
    Polonium
  • C
    Radium
  • Astatine
Answer
Correct option: D.
Astatine
Astatine belongs to halogen family.
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MCQ 1121 Mark
The oxidation state of chlorine in bleaching powder is:
  • A
    $-2$
  • B
    $-1$
  • C
    $+1$
  • $-1$ and $+1$
Answer
Correct option: D.
$-1$ and $+1$
The chemical formula of bleaching powder is $\ce{CaOCl_2}$.
Here, calcium is bonded to $Cl^-$ ion and $\text{OCl}^-$ ion respectively.
In $Cl−$ the oxidation state of chlorine is $-1$ and in $\text{OCl}^-$ ion the oxidation state of chlorine is $+1.a\ 21$
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MCQ 1131 Mark
Which of the following elements can be involved in $\text{p}\pi-\text{d}\pi$ bonding?
  • A
    Carbon.
  • B
    Nitrogen.
  • Phosphorus.
  • D
    Boron.
Answer
Correct option: C.
Phosphorus.
Phosphorus can be involved in $\text{p}\pi-\text{d}\pi$ bonding due to presence of vacant $d$ orbitals $C, N,$ and $B$ do not have $o\ ’$ orbitals.
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MCQ 1141 Mark
Which of the following halogens does not form oxyacids at room temperature?
  • $F_2$​
  • B
    $Cl_2$​
  • C
    $Br_2$​
  • D
    $I_2$
Answer
Correct option: A.
$F_2$​
Fluorine does not hove $d-$sub shell so it can only have one oxidation state.
Therefore, it cann't form oxy acids. Fluorine is the most electronegative element and always show $−1$ oxiadation state. In oxyacids. reast of the halogens have positive oxidation state.
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MCQ 1151 Mark
Essential constituents of plants and animal tissues are:
  • $N$ and $P$
  • B
    $N$ and $As$
  • C
    $Cu$ and $Mg$
  • D
    $Ca$ and $Mg$
Answer
Correct option: A.
$N$ and $P$
Nitrogen $(N),$ phosphorus $(P)$ and potassium $(K)$ are present in plant tissue in quantities from $0.2\%$ to $4.0\%\ ($on a dry matter weight basis$).$
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MCQ 1161 Mark
In $P_4\ ($tetrahedral$):$
  • A
    Each $P$ is joined to four $P.$
  • Each $P$ is joined to three $P.$
  • C
    Each $P$ is joined to two $P.$
  • D
    $P_4$​ does not exist.
Answer
Correct option: B.
Each $P$ is joined to three $P.$
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MCQ 1171 Mark
If chlorine gas is passed through hot $\text{NaOH}$ solution, two changes are observed in the oxidation number of chlorine during the reaction. These are $......$ and $......$
$A. 0$ to $+5$
$B. 0$ to $+3$
$C. 0$ to $–1$
$D. 0$ to $+1$
  • A
    $A$ and $B$
  • $A$ and $c$
  • C
    $b$ and $c$
  • D
    $A$ and $d$
Answer
Correct option: B.
$A$ and $c$
$6\text{NaOH}+3\text{Cl}_2\xrightarrow{\ \ \ \ \ \ \ \ }5\text{NaCl}+\text{NaClO}_3+3\text{H}_2\text{O}$
When chlorine gas is passed through hot $\text{NaOH}$ solution it produces $\text{NaCl}$ and $\mathrm{NaClO}_3$. Thus oxidation state of chlorine changes from $0$ to $-1$ and $0$ to $+5$ respectively.
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MCQ 1181 Mark
One mole of magnesium nitride on the reaction with an excess of water gives:
  • A
    One mole of ammonia.
  • B
    One mole of nitric acid.
  • Two moles of ammonia.
  • D
    Two moles of nitric acid.
Answer
Correct option: C.
Two moles of ammonia.
Hint: Nitride on reaction with water gives ammonia
Step $1:\ $ Formula of magnesium nitride
The formula for magnesium nitride will be $\ce{Mg_3​N_2}​$
Step $2:\ $ Recation of magnesium nitrid
$\mathrm{Mg}_3 \mathrm{~N}_2+6 \mathrm{H}_2 \mathrm{O} \rightarrow 3 \mathrm{Mg}(\mathrm{OH})_2+2 \mathrm{NH}_3$
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MCQ 1191 Mark
Among the following the correct statement is:
  • A
    Phosphates have no biological significance in humans.
  • B
    Between nitrates and phosphates, phosphates are less abundant in earth's crust.
  • Between nitrates and phosphates, nitrates are less abundant in earth's crust.
  • D
    Oxidation of nitrates is possible in soil.
Answer
Correct option: C.
Between nitrates and phosphates, nitrates are less abundant in earth's crust.
Nitrates are less abundant than phosphates in the earth's crust because they are soluble in water. Moreover they can also be reduced by numerous microbes present in earth's crust.
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MCQ 1201 Mark
Which of the following acids forms three series of salts?
  • A
    $ \mathrm{H}_3 \mathrm{PO}_2 $
  • B
    $ \mathrm{H}_3 \mathrm{BO}_3 $
  • $ \mathrm{H}_3 \mathrm{PO}_4 $
  • D
    $ \mathrm{H}_3 \mathrm{PO}_3 $
Answer
Correct option: C.
$ \mathrm{H}_3 \mathrm{PO}_4 $
Structure of $ \mathrm{H}_3 \mathrm{PO}_4 $ is

$ \mathrm{H}_3 \mathrm{PO}_4 $​​​​​​​ has $3-OH$ groups i.e., has three ionisable $H-$atoms and hence forms three series of salts. These three possible series of salts of $ \mathrm{H}_3 \mathrm{PO}_4 $ are as follows:
$\mathrm{NaH}_2 \mathrm{PO}_4, \mathrm{NaHPO}_4$ and $\mathrm{Na}_3 \mathrm{PO}_4$
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MCQ 1211 Mark
The element that oxidizes water to $\mathrm {O_2}$ with a large evolution of heat is:
  • $ \mathrm{F}_2 $
  • B
    $ \mathrm{Cl}_2 $
  • C
    $ \mathrm{Br}_2 $
  • D
    $ \mathrm{I}_2 $
Answer
Correct option: A.
$ \mathrm{F}_2 $
$ \mathrm{F}_2 $ is the most powerful oxidizing agent and evolves large amount of heat due to the formation of $H -$ bond with $ \mathrm{H_2O} ($It is also the most electronegative element$)$
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MCQ 1221 Mark
Total number of covalent bonds in a white phosphorous molecule is:
  • A
    $1$
  • B
    $4$
  • C
    $3$
  • $6$
Answer
Correct option: D.
$6$
Number covalent bonds present in white phosphorous $P_4$​ is $6.$
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MCQ 1231 Mark
In a cyclotrimetaphosphoric acid molecule, how many single and double bonds are present?
  • A
    $3$ double bonds$; 9$ single bonds.
  • B
    $6$ double bonds$; 6$ single bonds.
  • $3$ double bonds$; 12$ single bonds.
  • D
    Zero double bonds$; 12$ single bonds.
Answer
Correct option: C.
$3$ double bonds$; 12$ single bonds.
Structure of Cyclotrimetaphosphoric acid.
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MCQ 1241 Mark
In solid state $\ce{PCl_5}$ is a _________.
  • A
    Covalent solid.
  • B
    Octahedral structure.
  • C
    Ionic solid with $\ce{[PCl_6]^+}$ octahedral and $\ce{[PCl_4]^-}$ tetrahedra.
  • Ionic solid with $\ce{[PCl_4]^+}$ tetrahedral and $\ce{[PCl_6]^-}$ octahedra.
Answer
Correct option: D.
Ionic solid with $\ce{[PCl_4]^+}$ tetrahedral and $\ce{[PCl_6]^-}$ octahedra.
Structure of $\ce{PCl_5}$ in solid state.
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MCQ 1251 Mark
Elements of group $-15$ form compounds in $+5$ oxidation state. However, bismuth forms only one well characterised compound in $+5$ oxidation state. The compound is
  • A
    $\ce{Bi_2O_5}$
  • $\ce{BiF_5}$
  • C
    $\ce{BiCl_5}$
  • D
    $\ce{Bi_2S_5}$
Answer
Correct option: B.
$\ce{BiF_5}$
Stability of $+5$ state decreases from top to bottom but because of high electronegativity and smaller size of fluorine bismuth can exist in this form.
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MCQ 1261 Mark
The characteristic of the last elements in the periods of a periodic table:
  • A
    Orbital completely.
  • B
    Zero electron affinity.
  • C
    Zero tendency in accepting electrons.
  • All of these.
Answer
Correct option: D.
All of these.
In a period the last element will have completely filled configuration by filling up that orbital completely. Hence they are called noble gases or inert elements as they do not participate in the bonding formation. They are also called zero group elements as they have zero electron affinity that is zero tendency in accepting electrons as they already have stability.
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MCQ 1271 Mark
The electronic configuration of halogens in their valence shell is:
  • A
    $\mathrm{ns}^2$
  • B
    $\ce{ns^2 np^6}$
  • C
    $ns^0$
  • $\ce{ns^2 np^5}$
Answer
Correct option: D.
$\ce{ns^2 np^5}$
Electronic configuration of halogens in their valence shells $\ce{= ns^2 np^5}$
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MCQ 1281 Mark
Strong reducing behaviour of $\mathrm{H}_3 \mathrm{PO}_2$ is due to
  • A
    Low oxidation state of phosphorus.
  • B
    Presence of two$-OH$ groups and one $P-H$ bond.
  • Presence of one$-OH$ group and two $P-H$ bonds.
  • D
    High electron gain enthalpy of phosphorus.
Answer
Correct option: C.
Presence of one$-OH$ group and two $P-H$ bonds.
In $\mathrm{H}_3 \mathrm{PO}_2,$ two H atoms are bonded directly to $P$ atom which imparts reducing character to the acid.
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MCQ 1291 Mark
Calcium cyanamide on treatment with steam produces:
  • A
    $\mathrm{NH}_3+\mathrm{CaO}$
  • B
    $\mathrm{NH}_3+\mathrm{CaHCO}$
  • $\mathrm{NH}_3+\mathrm{CaCO}_3$
  • D
    $\mathrm{NH}_3+\mathrm{Ca}(\mathrm{OH})_2$
Answer
Correct option: C.
$\mathrm{NH}_3+\mathrm{CaCO}_3$
Reaction:
$\mathrm{CaCN}_2+3 \mathrm{H}_2 \mathrm{O} \rightarrow \mathrm{CaCO}_3+\mathrm{NH}_3$
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MCQ 1301 Mark
The halogen which can form both cations and anions is:
  • A
    $F$
  • B
    $Cl$
  • C
    $Br$
  • $I$
Answer
Correct option: D.
$I$
Iodine can form both cations, as well as anions. Iodine can form cations due to the poor shielding effect of $d$ orbitals where electrons can be removed from the valence shell and the cation is formed. The cations and anions of Iodine is represented as follow:
$I^{-}$and $I^{+}$
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MCQ 1311 Mark
Which of the following is correct for $P_4$ molecule of white phosphorus?
It has $6$ lone pairs of electrons.
It has six $P–P$ single bonds.
It has three $P–P$ single bonds.
It has four lone pairs of electrons.
  • A
    $a$ and $b$
  • B
    $a$ and $c$
  • C
    $b$ and $c$
  • $b$ and $d$
Answer
Correct option: D.
$b$ and $d$

It has four lone pairs of electrons at each $p-$atom.
It has six $p-p$ single bond.
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MCQ 1321 Mark
Hydride of nitrogen is called:
  • A
    Hydrogen sulphide.
  • B
    Water.
  • Ammonia.
  • D
    Nitrous oxide.
Answer
Correct option: C.
Ammonia.
Hydride of nitrogen is the binary compound formed by the combination of hydrogen and nitrogen.
The hydride formed with nitrogen is ammonia $(\ce{NH_3}).$
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MCQ 1331 Mark
The word Argon means $.......$
  • A
    Noble
  • B
    Now
  • C
    Strange
  • Lazy
Answer
Correct option: D.
Lazy
The name "argon" is derived from the Greek word , meaning "lazy" or "inactive", as a reference to the fact that the element undergoes almost no chemical reactions.
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MCQ 1341 Mark
In Haber's process for the manufacture of ammonia, the catalyst used is:
  • A
    Finely divided nickel.
  • B
    Finely divided molybdenum.
  • Finely divided iron.
  • D
    Finely divided platinum.
Answer
Correct option: C.
Finely divided iron.
Finely divided iron is used as catalyst in the manufacture of ammonia by Haber's process.
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MCQ 1351 Mark
Nitrogen differs from $\text{P, As, Sb}$ and $Bi$ in the following properties:
  • A
    It forms diatomic molecule.
  • B
    It is not able to extent its coordination number beyond four.
  • C
    Nitrogen does not function as a Lewis acid whereas $\text{P, As, Sb}$ and $Bi$ do so.
  • In all the properties given above.
Answer
Correct option: D.
In all the properties given above.
As vacant $d-$orbital are present in $P$ and other elements of this group except $N$ so they can expand their valency and forms stable pentavalence product but due to absence of $d-$orbitals nitrogen cannot form pentavalence products. It forms diatomic molecule $N_2$
Nitrogen does not function as a Lewis acid due to absence of $d-$orbitals and it is a Lewis base due to presence of lone pair.
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MCQ 1361 Mark
Which of the following non$-$metals belongs to the halogen family?
  • A
    Flourine
  • B
    Chlorine
  • C
    Bromine
  • All of the above
Answer
Correct option: D.
All of the above
Elements of $17^{th}$ group are called halogens. It contains fluorine$(F),$ Chlorine$(Cl),$ Bromine$(Br),$ Iodine$(I)$ and Astatine$(At).$
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MCQ 1371 Mark
Which of the following pairs of ions are isoelectronic and isostructural?
  • $\text{CO}_3^{2-},\text{NO}_3^-$
  • B
    $\text{ClO}_3^-,\text{CO}_3^{2-}$
  • C
    $\text{SO}_3^{2-},\text{NO}_3^-$
  • D
    $\text{ClO}_3^-,\text{SO}_3^{2-}$
Answer
Correct option: A.
$\text{CO}_3^{2-},\text{NO}_3^-$
No. of electron in both the molecule is $= 32,$
Both has similar structure that is triangular planar.
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MCQ 1381 Mark
Which of the following statements are correct?
$a. S-S$ bond is present in $\mathrm{H}_2 \mathrm{S}_2 \mathrm{O}_6$.
$b.$ In peroxosulphuric acid $\left(\mathrm{H}_2 \mathrm{SO}_5\right)$ sulphur is in $+6$ oxidation state.
$c.$ Iron powder along with $\mathrm{Al}_2 \mathrm{O}_3$ and $\mathrm{K}_2 \mathrm{O}$ is used as a catalyst in the preparation of $\mathrm{NH}_3$ by Haber's process.
$d.$ Change in enthalpy is positive for the preparation of $\mathrm{SO}_3$ by catalytic oxidation of $\mathrm{SO}_2$.
  • $a$ and $b$
  • B
    $a$ and $c$
  • C
    $b$ and $c$
  • D
    $a$ and $d$
Answer
Correct option: A.
$a$ and $b$

In $\mathrm{H}_2 \mathrm{SO}_5$, there is a peroxo$-$linkage.

$(O$ in peroxide linkage has oxidation state$-1)$
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MCQ 1391 Mark
An element with variable $($more than one$)$ valency stored under water is:
  • A
    Silicon.
  • B
    Iron.
  • Phosphorus.
  • D
    Gold.
Answer
Correct option: C.
Phosphorus.
Phosphorous can accept either $3$ electrons or donate $5$ electrons depending on the neighborhood element. Hence, it has variable valency. The allotropic form of phosphorus $($white phosphorus$)$ is less stable and therefore highly reactive because of angular strain in $P_4$​ molecule where the angles are only $60^\circ .$
It readily catches fire in air to give dense white fumes of $\ce{P_4O_{10}}$. Therefore, it is kept in water to avoid oxidation by the oxygen present in the air. It is kept in water because it is insoluble in water.
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MCQ 1401 Mark
Which of the following statements is not correct?
  • A
    All halogens except flourine from $\text{OXO}-$acids.
  • B
    Hypohalous acids $\text{HOCI, HOBr}$ and $\text{HOI}$ are all strong acids.
  • C
    Hypochlorous acid is the most stable among hypohalous acids.
  • Chlorous acid is the only halous acid known.
Answer
Correct option: D.
Chlorous acid is the only halous acid known.
There are also other halous acids like:
$\mathrm{HOBr}_2$ which is Hydrobromous acid.
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MCQ 1411 Mark
The lightest gas which is non$-$inflammable is:
  • A
    $H_2$
  • $He$
  • C
    $N_2$
  • D
    $Ar$
Answer
Correct option: B.
$He$
$H_2$​ is the lightest gas but it is inflammable.
$He$ is the next lightest gas and it is non$-$inflammable.
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MCQ 1421 Mark
Warming ammonium sulphate with sodium hydroxide solution gives:
  • Ammonia.
  • B
    Chlorine.
  • C
    Nitrogen.
  • D
    None of these.
Answer
Correct option: A.
Ammonia.
$\left(\mathrm{NH}_4\right) 2 \mathrm{SO}_4+2 \mathrm{NaOH} \rightarrow \mathrm{Na}_2 \mathrm{SO}_4+2 \mathrm{H}_2 \mathrm{O}+2 \mathrm{NH}_3$
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MCQ 1431 Mark
Zero group elements are known as $.......$
  • A
    Alkali metals.
  • B
    Alkaline earth metals.
  • C
    Transition metals.
  • Inert gases.
Answer
Correct option: D.
Inert gases.
The elements of group $0$ have stable complete octate configuration. As a result, they do not react with other elements easily, i.e., they have inert behavior.
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MCQ 1441 Mark
A brown ring is formed in the ring test for $\text{NO}_3^-$ ion. It is due to the formation of
  • $[\text{Fe}(\text{H}_2\text{O})_5(\text{NO})]^{2+}$
  • B
    $\text{FeSO}_4.\text{NO}_2$
  • C
    $[\text{Fe}(\text{H}_2\text{O})_4(\text{NO})_2]^{2+}$
  • D
    $\text{FeSO}_4.\text{HNO}_3$
Answer
Correct option: A.
$[\text{Fe}(\text{H}_2\text{O})_5(\text{NO})]^{2+}$
When freshly prepared solution of $\mathrm{FeSO}_4$ is added in a solution containing $\mathrm{NO}_3$ ion, it leads to formation of a brown coloured complex. This is known as brown ring test of nitrate.
$\text{NO}_3^-+3\text{Fe}^{2+}+4\text{H}^+\xrightarrow{\ \ \ \ \ \ \ \ \ \ }\ \text{NO}+3\text{Fe}^{3+}+2\text{H}_2\text{O}$
$[\text{Fe}(\text{H}_2\text{O})_6]^{2+}+\text{NO}\xrightarrow{\ \ \ \ \ \ \ \ \ \ }[\text{Fe}(\text{H}_2\text{O})_5(\text{NO})]^{2+}+\text{H}_2\text{O}\\\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ ^{\text{Brown ring}}$
Hence, 2 moles of ammonia will produce $2$ moles of $NO.$
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MCQ 1451 Mark
Urea is prepared by the chemical reaction of:
  • A
    Acetamide and ethyl alcochol.
  • B
    Ammonium sulphate and calcium chloride.
  • Ammonia and Carbon dioxide.
  • D
    Chlorine and water.
Answer
Correct option: C.
Ammonia and Carbon dioxide.
The chemical formula of urea is $\mathrm{H}_2 \mathrm{N}-\mathrm{CO}-\mathrm{NH}_2$
Urea is now prepared commercially in vast amounts from liquid ammonia and liquid carbon dioxide.
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MCQ 1461 Mark
In qualitative analysis when $\ce{H_2S}$ is passed through an aqueous solution of salt acidified with dil$. \text{HCl},$ a black precipitate is obtained. On boiling the precipitate with dil$. \ce{HNO_3},$ it forms a solution of blue colour. Addition of excess of aqueous solution of ammonia to this solution gives $......$
  • A
    Deep blue precipitate of $\mathrm{Cu}(\mathrm{OH})_2$.
  • Deep blue solution of $\left[\mathrm{Cu}\left(\mathrm{NH}_3\right)_4\right]^{2+}$.
  • C
    Deep blue solution of $\mathrm{Cu}\left(\mathrm{NO}_3\right)_2$.
  • D
    Deep blue solution of $\mathrm{Cu}(\mathrm{OH})_2 \cdot \mathrm{Cu}\left(\mathrm{NO}_3\right)_2$.
Answer
Correct option: B.
Deep blue solution of $\left[\mathrm{Cu}\left(\mathrm{NH}_3\right)_4\right]^{2+}$.
Black precipitate of copper sulphide is formed which gives blue colour of copper nitrate on boiling with dilute $\ce{HNO_3}.$ When aqueous solution of ammonia is added to it, deep blue colour of
$\text{Cu}^{2+}+\text{H}_2\text{S}\ \xrightarrow{\ \ \ \ \ \ \ \ \ }\ \text{CuS}+2\text{H}^+,\\\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{Black}$
$\text{CuS}+\text{dil. }\text{HNO}_3\ \xrightarrow{\ \ \ \ \ \ \ \ \ \ }\ \text{Cu}(\text{NO}_3)_2\\\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{Blue}$
$\text{Cu}(\text{NO}_3)_2+4\text{NH}_3\xrightarrow{\ \ \ \ \ \ \ \ \ \ }[\text{Cu}(\text{NH}_3)_4]^{2+}\\\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{Deep blue}$
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MCQ 1471 Mark
Which is the lightest gas?
  • A
    Helium
  • B
    Oxygen
  • Hydrogen
  • D
    Nitrogen
Answer
Correct option: C.
Hydrogen
Atomic weight of hydrogen is least so it is the lightest gas.
Hydrogen dirigibles are able to float in the atmosphere.
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MCQ 1481 Mark
Ammonia is not a product in the:
  • A
    Hydrolysis of nitrolim.
  • B
    Hydrolysis of aluminium nitride.
  • Decomposition of ammonium nitrite.
  • D
    Hydrolysis of urea.
Answer
Correct option: C.
Decomposition of ammonium nitrite.
$\mathrm{NH}_3 \mathrm{NO}_3 \rightarrow \mathrm{N}_2 \mathrm{O}+2 \mathrm{H}_2 \mathrm{O}$
Nitrous oxide is produced after decomposition of ammonium nitrite instead of ammonia.
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MCQ 1491 Mark
Reduction potentials of some ions are given below. Arrange them in decreasing order of oxidising power.
Ion $\text{ClO}_4^-$ $\text{IO}_4^-$ $\text{BrO}_4^-$
Reduction potential $\text{E}^{\ominus}/\text{V}$ $\text{E}^{\ominus}=1.19\text{V}$ $\text{E}^{\ominus}=1.65\text{V}$ $\text{E}^{\ominus}=1.74\text{V}$
  • A
    $\text{ClO}_4^->\text{IO}_4^->\text{BrO}_4^-$
  • B
    $\text{IO}_4^->\text{BrO}_4^->\text{ClO}_4^-$
  • $\text{BrO}_4^->\text{IO}_4^->\text{ClO}_4^-$
  • D
    $\text{BrO}_4^->\text{ClO}_4^->\text{IO}_4^-$
Answer
Correct option: C.
$\text{BrO}_4^->\text{IO}_4^->\text{ClO}_4^-$
Higher the standard reduction potential higher will be the oxidizing power.
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MCQ 1501 Mark
Which of the following orders are correct as per the properties mentioned against each?
$a.$ $\ce{As_2O_3 < SiO_2 < P_2O_3 < SO_2}$ Acid strength.
$b.$ $\ce{AsH_3 < PH_3 < NH_3}$ Enthalpy of vapourisation.
$c.$ $\ce{S < O < Cl < F}$ More negative electron gain enthalpy.
$d.$ $\ce{H_2O > H_2S > H_2Se > H_2Te}$ Thermal stability.
  • A
    $a$ and $b$
  • B
    $b$ and $c$
  • C
    $a$ and $c$
  • $a$ and $d$
Answer
Correct option: D.
$a$ and $d$
  1. $\ce{As_2O_3 < SiO_2 < P_2O_3 < SO_2}$ Order of acid strength.
  2. Correct order of enthalpy of vaporization is $\ce{AsH_3 > PH_3 > NH_3}$
  3. Correct order of more negative electron gain enthalpy $\ce{S < O < FH_2Se > H_2Te}$
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MCQ 1511 Mark
Which of the following options are not in accordance with the property mentioned against them?
$a. \mathrm{F}_2 > \mathrm{Cl}_2 > \mathrm{Br}_2 > \mathrm{I}_2$ Oxidising power.
$b. \mathrm{MI} > \mathrm{MBr} > \mathrm{MCl}  > \mathrm{MF}$ Ionic character of metal halide.
$c. \mathrm{F}_2 > \mathrm{Cl}_2 > \mathrm{Br}_2 > \mathrm{I}_2$ Bond dissociation enthalpy.
$d. \mathrm{HI} < \mathrm{HBr} < \mathrm{HCl} < \mathrm{HF}$ Hydrogen-halogen bond strength.
  • A
    $a$ and $b$
  • B
    $a$ and $c$
  • $b$ and $c$
  • D
    $a$ and $d$
Answer
Correct option: C.
$b$ and $c$
Bond dissociation enthalpy order is $\mathrm{Cl}_2 > \mathrm{Br}_2 > \mathrm{F}_2 > \mathrm{I}_2$ lonic character of metal halides increases as electronegativity of halogen increases $\mathrm{MI} < \mathrm{MBr} < \mathrm{MCl} < \mathrm{MF}$.
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MCQ 1521 Mark
What is the atomic number $(Z)$ of the noble gas that reacts with fluorine?
  • $54$
  • B
    $10$
  • C
    $18$
  • D
    $2$
Answer
Correct option: A.
$54$
Atomic number $54$ is for $Xe.$
It reacts with fluorine and forms compounds, like $\mathrm{XeF}_2, \mathrm{XeF}_4$
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MCQ 1531 Mark
The most abundant element in the atmosphere is:
  • A
    Phosphorus
  • B
    Oxygen
  • Nitrogen
  • D
    Carbon
Answer
Correct option: C.
Nitrogen
The most abundant element in the atmosphere is nitrogen.
Atmosphere contains $78\%$ nitrogen.
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