A 6.5m long ladder rests against a vertical wall reaching a height of 6.0m. A 60kg man stands half way up the ladder.
- Find the torque of the force exerted by the man on the ladder about the upper end of the ladder.
- Assuming the weight of the ladder to be negligible as compared to the man and assuming the wall to be smooth, find the force exerted by the ground on the ladder.
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m = 60kg, ladder length = 6.5m, height of the wall = 6mTherefore torque due to the weight of the body
- $\tau=\frac{600\times6.5}{2\sin\theta}=\text{i}$
$\Rightarrow\tau=735\text{N-m}$
- $\text{R}_2=\text{mg}=60\times9.8$
$\Rightarrow6.5\text{R}_1\cos\theta=60\text{g}\sin\theta\times\frac{6.5}{2}$
$\Rightarrow\text{R}_1=60\text{g}\tan\theta=60\text{g}\times\Big(\frac{2.5}{12}\Big)\ \Big[$Because $\tan\theta=\frac{2.5}{6}\Big]$
$\Rightarrow\text{R}_1=\Big(\frac{25}{2}\Big)\text{g}=122.5\text{N}$
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