A comet revolves around the sun in a highly elliptical orbit having a minimum distance of $7 \times 10^{10}m$ and a maximum distance of $1.4 \times 10^{13}m$. If its speed while nearest to the Sun is $60km s^{-1}$, find its linear speed when situated farthest from the Sun.
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Let mass of comet be M and its angular speed be w when situated at a distance r from the Sun, then its angular momentum $L = I w = Mr^2w$ If v be the linear speed, then $L = Mr^2w = Mrv$ In accordance with conservation law of angular momentum, we can write that $\text{Mr}_1\text{v}_1=\text{mr}_2\text{v}_2$
$\therefore\text{v}_2=\frac{\text{r}_1\text{v}_1}{\text{r}_2}=\frac{7\times10^{10}\text{m}\times60\text{km/s}}{1.4\times10^{13}\text{m}}$ $=0.3\text{km/s}\text{ or }300\text{m/s.}$
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