A resistance of $40$ ohms and one of $60$ ohms are arranged in series across $220$ volt supply. Find the heat in joules produced by this combination of resistances in half a minute.
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Given: $R 1=40$ ohms, $R 2=60$ ohms (in series), $V=220 V, t =30 sec$ we know that
Total resistance, $R=40+60=100$ ohms
By ohm's law
$V=IR$
$I=\frac{V}{R}$
$I=\frac{220}{100}=2.2 amp$
Putting the value of $I , R$ and t in eq. $H = I ^2 R T$
$H=2.2^2 \times 100 \times 30$
$H=14520 J$
Total resistance, $R=40+60=100$ ohms
By ohm's law
$V=IR$
$I=\frac{V}{R}$
$I=\frac{220}{100}=2.2 amp$
Putting the value of $I , R$ and t in eq. $H = I ^2 R T$
$H=2.2^2 \times 100 \times 30$
$H=14520 J$
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