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M.C.Q (1 Marks)

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215 questions · 1 auto-graded MCQ + 214 self-marked written.

Question 11 Mark
There is a sudden increase in current in zener diode is:
Answer
  1. Due to rupture of bonds
Explanation:
When Zener diode is connected in reverse bias, as applied voltage reaches at Zener breakdown voltage, due to rupture of bonds there is a sudden increase in current in Zener diode.
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Question 21 Mark
The value indicated by Fermi energy level in an intrinsic semiconductor is:
Answer
  1. The average energy of electrons and holes.
Explanation:
In an intrinsic semiconductor, n=p, where, n is number of electrons and p is number of holes in intrinsic semiconductor.
This implies that there is an equal chance of finding an electron at the conduction band edge as there is of finding a hole at the valence band edge. Thus, the average energy level of electrons and holes is half of the energy band gap in intrinsic semiconductors.
Also the Fermi energy level lie exactly in the middle of energy band gap in intrinsic semiconductors. Thus, the value indicated by Fermi energy level in an intrinsic semiconductor is the average energy of electrons and holes.
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Question 31 Mark
The gate that has only one input terminal:
Answer
  1. NOT
Explanation:
Only one logic gate has one input terminal i.e. NOT gate.
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Question 41 Mark
Among the following one can act as the building blocks for the other gates is:
Answer
  1. NAND and NOR
Explanation:
NAND and NOR gates are known as universal gates. Any one of these gates can be used to implement any kind of logic gate. This kind of feasibility is does not exist with other gates i.e. any other gate cannot solely implement all logic gates. For example, AND gate cannot be implemented using an OR gate and vice-versa. The implementation of NAND and NOR gates to generate other logic gates is shown above.
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Question 51 Mark
Which of the following is not the function of a NOT gate?
Answer
  1. Stop a signal.
Explanation:
A NOT gate inverts the input signal which is the same as complementing a signal or changing the logic in a digital circuit. This means that when the input to the NOT gate is logic '0', the output is logic '1'. However, it does not stop a signal.
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Question 61 Mark
Statement-1: NOT gate is also called invertor circuit.Statement-2: NOT gate inverts the input order.
Answer
  1. Statement 1-is true, statement -2 is true and statement -2 is correct explanation of statement-1.
Explanation:
NOT gate is also called invertor circuit since NOT gate inverts the input order. Hence, statement 1-is true statement-2 is true statement-2 is correct explanation of statement-1.
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Question 71 Mark
In a photo-diode, 
Answer
  1. Photocurrent is proportional to incident light intensity.
Explanation:
In a photodiode, photocurrent is directly proportional to intensiy of incident light. More the incident light intensity, more will be the current produced.
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Question 91 Mark
If ‘p’ region of a semi conductor is connected to negative and ‘n’ region to positive pole, it is said to be:
Answer
  1. Reverse biased
Explanation:
In reverse bias, 'p' region of a semi conductor is connected to negative pole and 'n' region to positive pole.
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Question 101 Mark
Truth table for the given circuit (Fig.) is:
Answer

Solution:
Here, C = A.B and D = Ā.B
E = C + D = (A B) + (Ā .B)
Explanation The truth table of this arrangement of gates can be given 
A B Ā C = A.B d = Ā.B E = (C + D)
0 0 1 0 0 0
0 1 1 0 1 1
1 0 0 0 0 0
1 1 0 1 0 0
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Question 111 Mark
If the two ends of a p-n junction are joined by a wire:
Answer
  1. There will not be a steady current in the circuit.
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Question 121 Mark
The breakdown in a reverse biased $p-n$ junction diode is more likely to occur due to:
Answer
Large velocity of the minority charge carriers if the doping concentration is small.
Strong electric field in the depletion region if the doping concentration is large.
Reverse biasing : Positive terminal of the battery is connected to the $N-$ crystal and negative terminal of the battery is connected to $P-$ crystal.
  1. In reverse biasing width of depletion layer increases
  2. In reverse biasing resistance offered $R_\text{Reverse} = 10^5\Omega .$
  3. Reverse bias supports the potential barrier and no current flows across the junction due to the diffusion of the majority carriers.
  1. $($A very small reverse current may exist in the circuit due to the drifting of minority carriers across the junction$)$
  2. Break down voltage : Reverse voltage at which break down of semiconductor occurs.
  3. For Ge it is $25V$ and for $ Si$ it is $35V$.

So, we conclude that in reverse biasing, ionization takes place because the minority charge carriers will be accelerated due to reverse biasing and striking with atoms which in turn cause secondary electrons and thus more number of charge carriers.
When doping concentration is large, there will be a large number of ions in the depletion region, which will give rise to a strong electric field.
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Question 131 Mark
Let nh and ne be the number of holes and conduction electrons in an extrinsic semiconductor:
Answer
  1. nh ≠ ne.
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Question 141 Mark
For germanium diode, the junction voltage is about _____.
Answer
  1. 0.3
Explanation:
The junction voltage Vo​ for a germanium diode is 0.3 V at room temperature. This potential opposes the diffusion of electrons from n-side and holes from p-side. It is 0.7 eV for Si at room temperature.
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Question 151 Mark
The process by which ac is converted into dc is known as:
Answer
  1. Rectification
Explanation:
The process by which ac is converted into dc is known as "Rectification".
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Question 161 Mark
The thickness of the depletion region is of the order of ___________ of a micrometre.
Answer
  1. None of these
Explanation:
Depletion region is a region near the p-n junction where flow of charge carriers (free electrons and holes) is reduced over a given period and finally results in zero charge carriers.The width of depletion region which is generally 1μm, depends on the amount of impurities added to the semiconductor. Impurities are the atoms (pentavalent and trivalent atoms) added to the semiconductor to improve its conductivity.
hence answer is 1μm and correct option is D - none of these.
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Question 171 Mark
Two identical capacitors A and B are charged to the same potential V and are connected in two circuits at t = 0 as shown in figure. The charges on the capahltors at a time t = CR are, respectively:
Answer
  1. $\frac{\text{VC}}{\text{e}}, \text{VC}$
Explanation:
In circuit (a), the diode is forward biassed. So, it offers negligible resistance to the flow of current and can thus be replaced by a short circuit. Now, the capacitor charge will leak through the resistance and decay exponentially with time.
Capacitor charge $=\frac{\text{VC}}{\text{e}}$
In circuit (b), the diode is reverse biassed. So, it offers infinite resistance to the current flow and can thus be replaced by an open circuit. As the circuit is open now, no current can flow across the resistance. So, the charge in the capacitor cannot leak through the resistor.
Capacitor charge = VC
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Question 181 Mark
Figure shows the transfer characteristics of a base biased $CE$ transistor. Which of the following statements are true?
Answer
According to above graph transfer characteristics of a base biased common emitter transistor, we note that.
When $V_i= 0.4 V,$ output voltage remain same,there is no collection current.
So, transistor circuit is not in active state.
when $V_i = 1V \ ($This is in between $0.6V$ to $2V),$ the transistor circuit is in active state and when input is increasing output is decreasing because when $CE$ is used as an amplifier input and output voltages are $180^\circ$ out of phase. Then it is used as an amplifier.
when $V_i = 0.5V,$ there is no collector current. The transistor is in cut off state.
The transistor circuit can be used as a switch to be turned off.
when $V_i = 2.5V,$ the collector current becomes maximum and transistor is in a saturation state and can used as switch turned on state.
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Question 191 Mark
For the given combination of gates, if the logic states of inputs A, B, C are as follows A = B = C = 0 and A = B = 1,C = 0 then the logic states of output D are:
Answer
  1. 0,0
Explanation:
OR gate add the input signals given to it and AND gate multiply the input signals given to it.
Input (0,0) given to OR gate will yield result 0.
Now input for AND gate are (0,0) hence output will be 0.
For the second case, input (1,1) given to OR gate will yield result 1.
Now input for AND gate are (1,0) hence output will be 0.
Therefore combination of gates will yield result 0 and 0.
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Question 201 Mark
When an electric field is applied across a semiconductor:
Answer
  1. Electrons move from lower energy level to higher energy level in the conduction band.
  1. Holes in the valence band move from higher energy level to lower energy level.
Solution:
As we apply electric field is applied across a semiconductor, the electrons in the conduction band acquire energy and get accelerated. They travel from lower energy level to higher energy level. While the holes in valence band travel from higher energy level to lower energy level, where they will be having more energy.
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Question 211 Mark
Carbon, silicon and germanium have four valence electrons each. At room temperature the appropriate statement is:
Answer
  1. The number of free electrons for conduction is significant only in Si and Ge but small in C.
Explanation:
In Si and Ge at room temperature(300K); the energy band gap is low as the result of which electrons in the covalent bonds gain kinetic energy, they break the bond and move to conduction band.
A hole is also created in the valence band. So the number of free electrons for conduction is significant in Si and Ge.
The energy band gap in case of carbon is high as the result of which there are not significant number of electrons in the conduction band even at room temperature.
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Question 231 Mark
A semiconductor is doped with a donor impurity:
Answer
  1. The electron concentration increases.
Explanation:
When a semiconductor is doped with a donor type such as arsenic or phosphorous, which has five valence electrons, the donor atom replaces the Si or Ge atom. As a result, four out of the five electrons of the donor atom form a covalent bond by sharing an electron with four atoms of silicon. However, the fifth electron is free to move. Also, due to the breaking up of covalent bonds at room temperature, equal number of electrons and holes are produced. Thus, the total number of holes in the n-type semiconductor is less compared to the number of free electrons.
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Question 241 Mark
The output of a 2-input OR gate is zero only when its:
Answer
  1. Both inputs are 0.
Explanation:
The truth table for 2-input OR gate is as shown in the figure. Thus, the output is zero only when both inputs are zero.
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Question 251 Mark
There is no hole current in conductors, because they have:
Answer
  1. Overlapping of valence and conduction bands.
Explanation:
In conductors, electrons are loosely bound to the nucleus hence, can detach easily at room temperature. Also, a large number of free electrons thus, available are conduction electrons. When the covalent bond breaks, electrons are freed from the atom.
The departure of an electron from valence band creates the vacancy in bond, this vacancy is known as hole. This hole is captured by another free electron.
Also, the energy level of free electrons corresponds to the conduction level, hence valance level and conduction level are overlapped. So there are no holes in conduction level to carry hole current.
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Question 261 Mark
An intrinsic semiconductor is:
Answer
  1. Undoped
Explanation:
Doping is a process of adding impurities in a semiconductor. Doped semiconductors are known as extrinsic semiconductors and others are known as intrinsic ones.
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Question 271 Mark
Which of the following contains a covalent bond?
Answer
  1. Germanium
Explanation:
A covalent bond is a chemical bond that involves the sharing of electron pairs between atoms. The stable balance of attractive and repulsive forces between atoms when they share electrons is known as covalent bonding.
As the valency of germanium is 4, it can share 4 electrons of neighboring atom to complete the octet.
Hence, Ge has covalent bond. NaCl is an example of an ionic bond and helium and copper both have valency 2 and 1 respectively.
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Question 281 Mark
In an intrinsic semiconductor, if $Ne​$ is the number of electrons in the conduction band and $Np$​ is the number of holes in the valence band then.
Answer
In an intrinsic semiconductor, the number of electrons in the conduction band is equal to the number of holes in the valence band, so $N_{e​} = N_{p̣}$
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Question 291 Mark
In an insulator, the forbidden energy gap between the valence band and conduction band is of the order of:
Answer
  1. 5eV
Explanation:
Forbidden energy gap, also known as band gap refers to the energy difference (eV) between the top of valence band and the bottom of the conduction band in materials. Current flowing through the materials is due to the electron transfer from the valence band to the conduction band.
Insulators do not conduct electricity because a large amount of energy is needed for the electrons to cross the forbidden energy gap. Moreover the forbidden energy gap is the widest (>5eV) in case of insulators.
Example: Forbidden energy gap in diamond is nearly 5.5eV.
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Question 301 Mark
In n-type of semiconductor, majority carries are:
Answer
  1. Electron
Explanation:
In n-type semiconductor, large number of free electrons is present. Hence, free electrons are the majority charge carriers in the n-type semiconductor. The free electrons (majority charge carriers) carry most of the electric charge or electric current in the n-type semiconductor.
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Question 311 Mark
If the series resistance decreases in an unloaded zener regulator, the zener current:
Answer
  1. Increases
Explanation:
current increases as the resistance decreases, as zener current is inversely proportional to the series resistance.
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Question 321 Mark
The pn junction can be formed by which of the following methods?
Answer
  1. All of these
Explanation:
Grown Junction Diode:
Diodes of this type are formed during the crystal pulling process. P and N-type impurities can be alternately added to the molten semiconductor material in the crucible, which results in a P-N junction when crystal is pulled. After slicing, the larger area device can then be cut into a large number of smaller-area semiconductor diodes. Though such diodes, because of larger area, are capable of handling large currents but larger area also introduces more capacitive effects, which are undesirable. Such diodes are used for low frequencies.
Alloy Type or Fused Junction Diode:
Such a diode is formed by first placing a P- type impurity (a tiny pellet of aluminium or some other P- type impurity) into the surface of an N-type crystal and heating the two until liquefaction occurs where the two materials meet. An alloy will result that on cooling will give a P-N junction at the boundary of the alloy substrate. Similarly, an N-type impurity may be placed into the surface of a P- type crystal and the two are heated until liquefaction occurs. Alloy type diodes have a high current rating and large PIV (peak inverse voltage) rating. The junction capacitance is also large, due to the large junction area.
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Question 331 Mark
In the depletion region of a pn junction, there is a shortage of:
Answer
  1. Holes and electrons
Explanation:
Depletion region of a p-n junction is formed due to the shortage of holes and electrons.
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Question 341 Mark
In a $npn$ transistor circuit, the collector current is $10\ mA$. If $95$ per cent of the electrons emitted reach the collector, which of the following statements are true?
Answer
Given $Ic = 10\ mA$
According to the question, $\text{I}_\text{c}=\frac{95}{100}\text{I}_\text{e}$
$\Rightarrow\ \text{I}_\text{e}=\frac{10\times100}{95}=10.53\ \text{mA}$
We know that$, I_b = I_e = I_c = 10.53 - 10 = 0.53\ mA.$
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Question 351 Mark
The number 0 (zero) is required for:
Answer
  1. Computer
Explanation:
The number 0 is most important in digital communication where only two states 0,1 control the input and output and computer is based on digital signals.
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Question 361 Mark
In an intrinsic semiconductor, conductivity is:
Answer
  1. Low at room temperature
Explanation:
In intrinsic semiconductors, n = p. Hence, at room temperature, no free electrons are available for conduction. If the temperature is increased, the covalent bonds will break and electrons will be freed, each electron will leave behind a hole and capture a new hole the process will continued and charge flows through intrinsic semiconductor.
Thus, its conductivity increases with temperature. Hence, in intrinsic semiconductor conductivity is low at room temperature.
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Question 381 Mark
The transducer used in television transmission works on the principle of:
Answer
  1. Photoelectric effect
Explanation:
A transducer is an electronic device that converts light energy to electrical energy in television. When light falls on photosensitive element electric current is generated that is measured directly or after amplification. Similarly, photoelectric effect is the ejection of electrons from a metal or semiconductor surface when illuminated by light or any radiation of suitable wavelength.
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Question 391 Mark
A Zener diode:
Answer
  1. Heavily doped junction diode.
Explanation:
The reverse breakdown voltage depends on doping of the diode. Hence, in the Zener diode the heavy doping of its p-n junction is done. The depletion region formed in the diode is very thin (<1 m) and the reverse bias voltage of about 5 V which is less than ordinary diode.
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Question 401 Mark
Conventional flow of current will always be from:
Answer
  1. p type → n type
Explanation:
The holes in the covalent bonds of p-type semiconductor. They appear to move towards n-type semiconductor. Because the electrons in the covalent bonds of n-type semiconductor (not free electrons) jump towards p-type semiconductor due to plenty of holes available in the covalent bonds at p-side. 
Hence, conventional current flow from p-type to n-type.
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Question 411 Mark
In an LED device, the intensity of emitted light:
Answer
  1. Increases continuously with the forward current of the diode, reaches a maximum and then decreases.
Explanation:
The intensity of emitted light increase with the foreword current more the light intensity.
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Question 421 Mark
The current flow in a Zener diode is mainly due to
Answer
  1. Collision generated charge carriers
Explanation:
When the reverse bias breakdown voltage is exceeded, a conventional diode is subject to high current due to avalanche breakdown.
Avalanche breakdown occurs in reverse bias when the applied voltage is high enough, the free electron may move fast enough to knock other electrons free, creating more free-electron-hole pairs (i.e., more charge carriers), increasing the current.
Thus, the current flow in a Zener diode is mainly due to collision generated charge carriers.
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Question 431 Mark
On increasing the temperature of a semi-conductor material:
Answer
  1. Density of charge-carriers increases, but their mobilities decreases.
Explanation:
On increasing the temperature of a semi-conductor material, the density of charge increases which apparently increases the hinderance and thus decreases their mobility.
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Question 441 Mark
Consider an npn transitor with its base-emitter junction forward biased and collector base junction reverse biased. Which of the following statements are true?
Answer
  1. Electrons crossover from emitter to collector.
  1. Electrons move from emitter to base.
Solution:
Key concept: Transistor:
A junction transistor is formed by sandwiching a thin layer of P-type semiconductor between two N-type semiconductors or by sandwiching a thin layer of N-type semiconductor between two p-type semiconductors.

E - Emitter (emits majority charge carriers)
C - Collects majority charge carries
B - base (provide proper interaction between E and C)

In normal operation base-emitter is forward biased, i.e., the positive pole of emitter base battery is connected to base and its negative pole is connected to the emitter. And collector base junction is reverse biased, i.e., the positive pole of the collector base battery is connected to collector and negative pole to base. Thus, electron moves from emitter to base and crossover from emitter to collector.
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Question 451 Mark
Zener breakdown takes place if:
Answer
  1. Doped impurity is high
Explanation:
Zener breakdown occurs due to heavily doped diodes.In this process electrons crosses the barrier from the valence band of the p-type to the conduction band of the lightly filled n-type material.
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Question 461 Mark
In a semiconductor diode, the depletion region is removed when:
Answer
  1. The diode is in its forward conducting state.
Explanation:
In a semiconductor diode, when diode in its forward conducting state current starts in diode and depletion region starts to deformed. After sometime depletion region is removed.
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Question 471 Mark
A transistor has three impurity regions. All the three regions have different doping levels. In order of increasing doping level, the regions are:
Answer
  1. Base, collector and emitter.
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Question 481 Mark
Which of the following is/are optoelectronic devices?
Answer
  1. All of the above
Explanation:
P-n junctions are an integral part of several optoelectronic devices. These include photodiodes, solar cells light emitting diodes (LEDs) and semiconductor lasers.
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Question 491 Mark
The output of the given circuit in Fig.
Answer
  1. Would be like a half wave rectifier with negative cycles in output.
Solution:
Key Concept:
  1. During positive half cycle,
Diode → Forward biased
Output signal → obtained
  1. During negative half cycle,
Diode → reverse biased
Output signal → not obtained
  1. Output voltage is obtained across the load resistance RL. It is not constant but pulsating (mixture of ac and dc) in nature.
  2. Average output in one cycle
  3. r.m.s. output: $\text{I}_\text{rms}=\frac{\text{I}_0}{2},\text{V}_\text{rms}=\frac{\text{V}_0}{2}$
When the diode is forward biased during positive half cycle of input AC voltage, the resistance of p-n junction is low. The current in the circuit is maximum. In this situation, a maximum potential difference will appear across resistance connected in a series of circuit. This result into zero output voltage across p-n junction.
And when the diode is reverse biased during negative half cycle of AC voltage, the p-n junction is reverse biased. The resistance of p-n junction becomes high which will be more than resistance in series. That is why, there will be voltage across p-n junction with negative cycle in output, hence option (c) is correct.
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Question 511 Mark
The lead marked with the arrow is the _______.
Answer
  1. emitter
Explanation:
 It is a p-n-p, transistor. The Lead marked with the arrow is the emitter. It tells the direction of the flow of the holes i.e, the flow of conventional current. 
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Question 521 Mark
The following truth table is for: ABY 110 101 011 001
Answer
  1. NAND gate
Explanation:
The output is 0 only when the two inputs are 1.
The output is 1 when any of the input is zero. 
This is the characteristic of a NAND gate.
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Question 531 Mark
The energy gap between the valence band and the condition band for a material is 6eV. The material is?
Answer
  1. An insulator
Explanation:
Insulators have large energy gap between valence and conduction band (about 6eV), while semiconductors have a smaller one and conductors, the smallest energy gap.
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Question 541 Mark
In an intrinsic semiconductor, the number of electrons in the conduction band is ________ the number of holes in the valence band.
Answer
  1. Equal to
Explanation:
In an intrinsic semiconductor, the number density of electrons is equal to the number density of holes i.e ne = nh.
Since there is no doping, no extra hole or electron is produced.
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Question 551 Mark
By increasing the temperature, the specific resistance of a conductor and a semiconductor:
Answer
  1. Increases, decreases.
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Question 561 Mark
The main cause of avalanche breakdown is:
Answer
  1. Ionisation by collision.
Explanation:
Avalanche breakdown is caused by impact ionization of electron-hole pairs. A very little current flows under reverse bias conditions and depletion region increases. The electric field in the depletion region of a diode can be very high. Electron/holes that enter the depletion region undergo a tremendous acceleration.
As these accelerated carriers collide with the atoms, they can knock electrons from their bonds, creating additional electron/hole pairs and thus additional current. As these secondary carriers are swept into the depletion region, they too are accelerated and the process repeats itself.
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Question 571 Mark
The truth table given in figure represents:
A B Y
0 0 0
0 1 1
1 0 1
1 1 1
Answer
  1. OR - Gate
Explanation:
OR gate has the property that output is one when any one of the inputs is one and zero only when all inputs are zero. From the truth table, it can be seen that the above two properties are satisfied.
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Question 581 Mark
When an input signal 1 is applied to a NOT gate, its output is:
Answer
  1. 0
Explanation:
NOT gate yields the reverse of the input signal in output, thus when an input signal 1 is applied to a NOT gate, its output is 0.
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Question 591 Mark
When a P - N junction is unbiased, the junction current at equilibrium is:
Answer
  1. Zero as no charges cross the junctions.
Explanation:
When a diode is connected in a Zero Bias condition, no external potential energy is applied to the PN junction. However if the diodes terminals are shorted together, a few holes (majority carriers) in the P-type material with enough energy to overcome the potential barrier will move across the junction against this barrier potential. This is known as the Forward Current.
Likewise, holes generated in the N-type material (minority carriers), find this situation favourable and move across the junction in the opposite direction. This is known as the Reverse Current and is referenced as IR. This transfer of electrons and holes back and forth across the PN junction is known as diffusion.
Then an Equilibrium or balance will be established when the majority carriers are equal and both moving in opposite directions so that the net result is zero current flowing in the circuit. When this occurs the junction is said to be in a state of Dynamic Equilibrium.
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Question 601 Mark
The conductivity of a semiconductor increases with increase in temperature because:
Answer
  1. Number density of current carriers increases, relaxation time decreases but effect of decrease in relaxation time is much less than increase in number density.
Solution:
With increase in temperature, the number density of current carries increases, relaxation time decreases but effect of decrease in relaxation is much less than increase in number density. So, the conductivity of a semiconductor increases with increase in temperature.
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Question 611 Mark
In Boolean algebra, A + B = Y implies that:
Answer
  1. Y exists when A exists or B exists or both A and B exist.
Explanation:
In Boolean algebra, A + B = Y implies that Y exists when A exists or B exists or both A and B exist.
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Question 631 Mark
At breakdown voltage, the rate of creation of hole-electron pairs is _____ leading to the _______ in current. 
Answer
  1. increased, increase
Explanation:
When the reverse voltage across a diode is very large, the valance electrons become free due to applied high electric field and get enough acceleration to make other electrons free, thus create a lot of electron-hole pairs in a short time. As the number of charge carriers increases, current also increases.
Therefore, at breakdown voltage, the rate of creation of hole-electron pairs is increased leading to the increase in current.
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Question 641 Mark
In semiconductors, at a room temperature:
Answer
  1. The valence band is partially empty and the conduction band is partially filled.
Explanation:
In semiconductors at room temperature the electrons get enough energy so that they are able to over come the forbidden gap. Thus at room temperature the valence band is partially empty and conduction band is partially filled.
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Question 671 Mark
The energy gap in glass at room temperature is:
Answer
  1. Both (1) and (3) are true.
Explanation:
Glass is an insulator. The energy gap in a glass is greater than that of semiconductor and a good conductor.
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Question 681 Mark
In the given circuit, if A and B represent two inputs and C represents the output, the circuit represents:
Answer
  1. OR gate
Explanation:
The image given shows a diode OR circuit. R is connected from the output to ground to provide bias current for the diodes. Any positive voltage will represent a logic 1 state and the summing of currents through multiple diodes does not change the logic level.
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Question 691 Mark
In an experiment of photoelectric effect the number of photoelectrons has to be increased without changing their frequency. The suitable step to be taken about the incident radiation for this is:
Answer
  1. Increasing intensity without changing frequency.
Explanation:
Intensity of photons is the number of photons passing through a cross sectional area per unit time. Hence changing the intensity would cause change in number of ejected photoelectrons emitted by them.
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Question 701 Mark
In a semiconductor, which of the following statement is correct?
Answer
  1. p - n junction is electrically neutral.
Explanation:
Generally Si is a semiconductor. In p type semiconductor acceptor level lies near the valence band and each donor atom contribute one electron. p-n junction electrically neutral because total charge is zero.
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Question 711 Mark
Two important processes that occur during the formation of a p-n junction.
Answer
  1. Both drift and diffusion
Explanation:
Three important phenomena occurs during formation of pn junction:
Diffusion, Formation of space charge, Drift.
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Question 721 Mark
The avalanche breakdown in p-n junction is due to:
Answer
  1. Cumulative effect of conduction band electron.
Explanation:
The avalanche breakdown in p-n junction is due to cumulative effect of conduction band electron. In reverse bias, due to applied electric field, electrons acquire enough energy to free more electron bound to the atom. The abundant number of electron-hole pairs are created for conduction, this is cumulative effect.
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Question 741 Mark
In an insulator, the forbidden energy gap between the valence band and conduction band is of the order of:
Answer
  1. 5eV.
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Question 751 Mark
The diffusion current in a p-n junction is:
Answer
  1. From the p-side to the n-side.
Explanation:
When a p‒n junction is formed then because of the difference in the concentration of charge carriers in the two regions, electrons from the n region move to the p region and holes from the p region move to the n region. Since the direction of the current is always opposite to the motion of electron, the direction of the current is from the p side to the n side.
Similarly, when the junction is forward biassed, the positive terminal of the battery is connected to the pside of the p‒n junction and the negative terminal of the battery is connected to the n side of the p‒njunction. As a result, electrons in the n side of the p‒n junction are repelled by the negative terminal of the battery and they move to the p side, where the positive terminal of the battery attracts them. Similarly, holes from the p side of the p‒n junction are repelled by the positive terminal of the battery and they move to the n side, where the negative terminal of the battery attracts them. Thus, they give diffusion current from the p side to the n side across the p‒n junction.
In reverse biassing, there is no flow of majority carriers across the junction; hence, there is not diffusion current. Here, the flow of majority carriers is opposed by the applied voltage.
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Question 771 Mark
Which one of the following statement is false:
Answer
  1. Work is a state finction.
Explanation:
Majority carrier in a n − type semiconductor are holes. This statement is false.
Since, in n−type semiconductor, the pentavalent impurity atoms donate electrons o the host crystal and the semiconductor doped with donars (pentavalent impurity) is called n − type semiconductor.
Therefore majority carrier in a n−type semiconductor are electrons.
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Question 781 Mark
In a p-type semiconductor, the acceptor valence band is:
Answer
  1. Close to the valence band of the host crystal.
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Question 791 Mark
To use a transistor as an amplifier, emitter-base junction is kept in ...X... and base-collector junction is kept in ...Y... Here, X and Y refer to:
Answer
  1. Forward bias, reverse bias.
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Question 801 Mark
When an impurity is doped into semiconductor, the conductivity of the semiconductor:
Answer
  1. Increases
Explanation:
The pure semiconductor has less number of thermally generated charge carriers. But when it is doped with pentavalent or trivalent impurity atoms, the number of charge carriers i.e. electrons and holes increases. So conductivity increases.
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Question 811 Mark
In an intrinsic semiconductor, conductivity is due to:
Answer
  1. Breaking of covalent bonds
Explanation:
In intrinsic semiconductors, n = p. Hence, at room temperature, no free electrons are available for conduction.
If some energy is supplied to the atoms of intrinsic semiconductor, the covalent bonds will break and electrons will be freed, each electron will leave behind a hole and capture a new hole the process will continued and charge flows through intrinsic semiconductor.
Thus, in intrinsic semiconductor conductivity is due to breaking of covalent bonds.
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Question 821 Mark
The impurity atoms with which pure silicon may be doped to make it a p-type semiconductor are those of:
Answer
  1. Boron.
  1. Aluminium.
Explanation:
A p-type semiconductor is formed by doping an intrinsic semiconductor with a trivalent atom (atom having valency 3). As phosphorous and boron have three valence electrons, they can be doped with silicon to make a p-type semiconductor.
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Question 831 Mark
When the conductivity of a semiconductor is only due to breaking of covalent bonds, the semiconductor is called:
Answer
  1. intrinsic
Explanation:
At room temperature, in impure semiconductors some free charge carriers are available for conduction due to impurity atoms. But in pure, i.e., intrinsic semiconductors, n = p.
Hence, at room temperature no free electrons are available for conduction. If the temperature is increased the covalent bonds will break and electrons will be freed, each electron will leave behind a hole and capture a new hole the process will continued and charge flows through intrinsic semiconductor.
Thus, its conductivity is only due to breaking of covalent bonds.
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Question 841 Mark
Materials which allow only larger currents to flow through them are:
Answer
  1. Semi-conductors
Explanation:
Semiconductors in their natural state are poor conductors because a current requires the flow of electrons, and semiconductors have their valence band filled, preventing the entry flow of new electrons.
Thus semi-conductors allows a large current to pass through them.
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Question 851 Mark
The gate for which output is high, if at least one input is low is:
Answer
  1. NAND
Explanation:
The truth table of NAND gate is shown as above, which implies that if at least one of the input is low then the output is high.
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Question 861 Mark
Hole is:
Answer
  1. A vacancy created when an electron leaves a covalent bond.
Solution:
Concept of holes in the semiconductor:
  1. When an electron is removed from a covalent bond, it leaves a vacancy behind. An electron from a neighbouring atom can move into this vacancy, leaving the neighbour with a vacancy. In this way the vacancy formed is called a hole (or cotter), and can travel through the material and serve as an additional current carriers.
  2. A hole is considered as a seat of positive charge, having magnitude of charge equal to that of an electron.
  3. Holes acts as a virtual charge, although there is no physical charge on it.
  4. Effective mass of hole is more than an electron.
  5. Mobility of hole is less than an electron.
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Question 871 Mark
A p-type semiconductor is:
Answer
  1. Uncharged.
Explanation:
A p-type semiconductor is formed by doping a pure semiconductor with a p-type material. As impurity atoms take the position of the germanium atom in a germanium crystal, three electrons of a p-type material form covalent bonds by sharing electrons with three neighbouring germanium atoms. However, the fourth covalent bond is left incomplete, with a want of one electron. This creates a hole. As the atom as a whole is neutral, the p-type material is also neutral.
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Question 881 Mark
The electrical conductivity of pure germanium can be increased by:
Answer
  1. Increasing the temperature.
  2. Doping acceptor impurities.
  3. Doping donor impurities.
  4. Irradiating ultraviolet light on it.
Explanation:
We know that the conductivity of any semiconductor can be increased by increasing the number of charge carriers. All the given methods are effective in increasing the number of free charge carriers. Hence, all options are correct.
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Question 891 Mark
In Fig., assuming the diodes to be ideal:
Answer
A symbol of the diode is represented like this : In this problem first we have to check the polarity of the diodes. $-10$ is the lower voltage in the circuit.
Now $p-$side of $p-n$ juction $D_1$ is connected to lower voltage and $n-$side of $D_1$ to higher voltage.
Thus $D_1$ is reverse biased.
Now, let us analyse $2^{nd}$ diode of the given circuit.
The $p-$side of $p-n$ junction $D_1$ is at higher potential and $n-$side of $D_2$ is at lower potential.
Therefore $D_2$ is forward biased.

Hence, current flows through the jucntion from $B$ to $A$.
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Question 901 Mark
In insulator:
Answer
  1. Conduction band is empty and valence band is filled with electrons.
Explanation:
Insulators are the materials which do not conduct electricity. All the electrons are filled in valance band whereas the conduction band is empty. Moreover, the energy band gap in insulators is very large, thus electrons cannot jump from valence band to conduction band.
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Question 911 Mark
The free electron density is more in .....:
Answer
  1. Conductors
Explanation:
Free electron density is more in conductors that is why they are useful in conducting electricity.
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Question 921 Mark
In intrinsic semiconductors:
Answer
  1. n = p
Explanation:
Intrinsic semiconductors are pure ones. Hence there is no question of impurity. Valence band is the range of energy of electrons which are in the valence shell of the atoms of a substance. Conduction band is the range of energy of electrons which are free and available for conduction.
At room temperature, some electrons of intrinsic semiconductors get excited and reach the conduction band. During this process, the electrons leave empty spaces in the valence shell. These empty spaces are known as holes in a semiconductor. Number of free electrons (n) is equal to the number of holes (p).
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Question 931 Mark
Given above are four logic gate symbols. Those for OR, NOR and NAND are respectively:
Answer
  1. a, c, d
Explanation:
a- represent OR gate 
b- represent the AND gate 
c- represent, the combination of OR and NOT gate, NOR gate.
d- represent, the combination of AND and NOT gate, NAND gate.
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Question 941 Mark
The leakage current across a pn junction is due to _________:
Answer
  1. Minority carriers
Explanation:
When a diode is reverse biased, its depletion region increases in width. Thus depletion region would correspond to an insulator. However still some current actually flows through the depletion region. This is due to the pushing of minority carriers across the depletion region causing very small reverse 'leakage current'.
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Question 951 Mark
Statement -1: NAND and NOR gates are called digital building blocks.
Statement-2: The repeated use of NAND (or NOR) gates can produce all the basis or complicated gates.
Answer
  1. Statement 1-is true, Statement -2 is true and Statement -2 is correct explanation of Statement-1.
Explanation:
NAND or NOR gates are called universal gates or digital building blocks. Also, the repeated use of NAND (or NOR) gates can produce all the basis or any complicated gates can be formed using NAND (or NOR) gates. Hence, statement 1-is true statement -2 is true statement -2 is correct explanation of statement-1.
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Question 961 Mark
Generally semiconductor can be used safely between the temperatures:
Answer
  1. 0 and 75
Explanation:
Semiconductor can be used safely between temperature 0 and 75.
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Question 971 Mark
If the two ends of a p-n junction are joined by a wire:
Answer
  1. There will not be a steady current in the circuit.
Explanation:
In a p‒n junction, current flows only if it is connected to the battery. If two ends of a p‒n junction are joined by a wire, then there will be diffusion and drift currents in the circuit and they will cancel each other. Hence, no current will flow in the circuit.
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Question 981 Mark
A semiconductor device is connected in a series circuit with a battery and resistance. A current is found to pass through the circuit. If the polarity of the battery is reversed, the current drops almost to zero. The device may be:
Answer
  1. A p-n junction
Explanation:
An ideal diode acts like an open switch when rivers biased and like a closed switch when forward biased.
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Question 991 Mark
In a metal, the separation between conduction band and valence band is of the order:
Answer
  1. 0 eV
Explanation:
Energy band gap is the energy difference between conduction band and valence band, i. e., energy required to an electron to overcome the energy levels between conduction band and valence band. In conductors, electrons are loosely bound to the nucleus hence, can detach easily at room temperature also.
A large number of free electrons thus, available are conduction electrons. The energy level of these electrons corresponds to the conduction level, hence valance level and conduction level are overlapped. Due to this, there is no gap between conduction band and valence band hence, for metals their separation is of the order of 0 eV.
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Question 1001 Mark
In the depletion region of a diode:
Answer
On account of difference in concentration of charge carrier in the two sections of $P-N$ junction, the electrons from $N-$rcgion diffuse through the junction into $P-$region and the hole from $P-$region diffuse into $N-$region.

Due to diffusion, neutrality of both $N-$and $P-$type semiconductor is disturbed, a layer of negative charged ions appear near the junction in the $P-$crystal and a layer of positive ions appears near the junction in $N-$crystal.
This layer is called depletion layer.
The thickness of depletion layer is $1$ micron $= 10^{-6}m.$
Width of depletion layer $\infty 1/$Dopping
Depletion is directly proportional to temperature.
Important point: The $P-N$ junction diode is equivalent to capacitor in which the depletion layer acts as a dielectric.
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Question 1011 Mark
The output of OR gate is 1:
Answer
  1. If either one or both inputs are 1
Explanation:
At least one input required to activate or − gate
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Question 1021 Mark
The n-side of the depletion layer of a p-n junction.
Answer
  1. Is positively charged
Explanation:
The diffusion of electrons from n side to p side makes the n side of the depletion layer of pn junction positively charged since it becomes deficient in electrons and each side was neutral in the beginning.
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Question 1031 Mark
If the bandgap between valence band and conduction band in a material is 0eV, then the material is:
Answer
  1. Good conductor
Explanation:
In good conductors, the valance band and the conduction band overlap each other resulting in a zero band gap energy. Whereas, bandgap in insulator is nearly 5 eV and that in semiconductors is nearly 1.1eV.
Hence the given material is a good conductor.
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Question 1041 Mark
In insulators________. (C.B is conduction band and V.B is valence band)
Answer
  1. C.B. is empty and V.B. is filled with electrons.
Explanation:
As shown in the image, insulators have a very large forbidden gap. Their conduction band is empty, thus they cannot conduct electricity under normal room temperature and pressure conditions. The valence band is full.
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Question 1051 Mark
In which of the following statements, the obtained impure semiconductor is of p-type?
Answer
  1. Germanium is doped with gallium.
Explanation:
A p-type semiconductor is produced by doping a 14 group element with a 13 group element as 14 group element has 4 valence electron whereas that of group 13 has 3 valence electron. We know that Germanium is a 14 group element and gallium is a 13 group element, thus doping germanium with gallium forms a p-type semiconductor.
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Question 1061 Mark
The conduction band and valency band of a good conductor are:
Answer
  1. Overlapped.
Explanation:
In conductors, electrons are loosely bound to the nucleus hence, can detach easily at room temperature also. A large number of free electrons thus, available are conduction electrons.
The energy level of these electrons corresponds to the conduction level, hence valance level and conduction level are overlapped.
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Question 1071 Mark
Semiconductors are generally made up of which substance?
Answer
  1. Silicon
Explanation:
Semiconductors are made of Si, generally. Because Si is the second most abundant element in earth's crust after oxygen and is less expensive than other semiconductors used in intrinsic semiconductors. 
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Question 1081 Mark
NAND and NOR gates are called universal gates primarily because they:
Answer
  1. Can be combined to produce OR, AND and NOT gates.
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Question 1091 Mark
In an insulator, the energy gap between conduction band and valence band is about:
Answer
  1. 6 eV
Explanation:
Atoms are neutral in the insulator, thus there are no valence electrons in the outer orbit. The electrons are tightly bound with the nucleus hence, at room temperature thermal energy is not enough to push the electrons into conduction band and hence, no electrons are available for conduction.
The energy required for electron to escape out from orbit and to over come the energy gap is thus of the order of 6 eV.
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Question 1101 Mark
Which of the following are correct for insulators?
Answer
  1. The conduction band is empty and the valence band is filled with electrons.
Explanation:
In insulators, the electrons are very tightly bound to the nucleus. At a room temperature, thermal energy is not enough to push electrons into conduction band. The energy band gap is very high. Thus the conduction band is empty and the valence band is filled with electrons.
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Question 1111 Mark
The concepts of holes is introduced based on:
Answer
  1. The notion that it is a whole lot easier to keep track of the missing particles in an "almost-full" band.
Explanation:
The concept of holes was introduced so as to occupy the empty spaces left by the missing electron. For example, in a valence band, when an electron jumps from valence to conduction band, an empty space is created in valence band which is occupied by a hole.
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Question 1121 Mark
In a semiconductor, the forbidden energy gap between the valence band and the conduction band is of the order is:
Answer
  1. 1eV.
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Question 1131 Mark
Forbidden gap in a pure conductor is:
Answer
  1. 0 eV
Explanation:
Forbidden band gap is the group of energy levels that cannot be occupied by the electrons, these energies lies in between conduction band and valence band. In pure conductors, electrons are loosely bound to the nucleus hence, can detach easily at room temperature also.
A large number of free electrons thus, available are conduction electrons. The energy level of these electrons corresponds to the conduction level, hence valence level and conduction level are overlapped.
Due to this, there is no forbidden band gap present in between conduction band and valence band hence, for metals the forbidden band gap is 0 eV.
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Question 1151 Mark
Which of the following statement(s) is/are true about holes?
Answer
  1. They flow from positive terminal to negative terminal.
Explanation:
Electrons flow from negative to positive terminal of battery. whenever the electric current flows from positive terminal of battery to negative terminal of battery is called conventional current. the conventional current has same direction of flow of holes but opposite to direction of flow of from electron.
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Question 1161 Mark
The transistor are usually made of:
Answer
  1. Metal oxides with high temperature coefficient of resistivity.
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Question 1171 Mark
To reduce the ripples in a rectifier circuit with capacitor filter:
Answer
$R_L$ should be increased.
Input frequency should be increased.
​​​​​Capacitors with high capacitance should be used.
Ripple factor may be defined as the ratio of $\text{r.m.s}$. value of the ripple voltage to the absolute value of the $DC$ component of the output voltage, usually expressed as a percentage.
However ripple voltage is also commonly expressed as the peak $-$ to $-$ peak value.
Ripple factor $(r)$ of a full wave rectifier using capacitor filter is given by
$\text{r}=\frac{0.236\text{R}}{\omega\text{L}}$
where $,L$ is inductance of the coil and $\omega$ is the angular frequency.
or Ripple factor can also be given by
$\text{r}=\frac{1}{4\sqrt{3}\text{v}\text{R}_\text{L}\text{C}_\text{V}}$
i.e., $\text{r}\propto\frac{1}{\text{R}_\text{L}}\Rightarrow\ \text{r}\propto\frac{1}{\text{C}},\text{r}\propto\frac{1}{\text{V}}$
Ripple factor is inversely proportional to $R_L, C$ and $v$.
Thus to reduce $r, R_L$ should be increased, input frequency $v$ should be increased and capacitance $C$ should be increased.
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Question 1181 Mark
The bond, that exists in a semiconductor is:
Answer
  1. Covalent bond
Explanation:
Semi-conductors are made of 14th Group elements which form covalent bonding.
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Question 1191 Mark
The impurity atoms with which pure silicon may be doped to make it a p-type semiconductor are those of:
Answer
  1. Boron.
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Question 1201 Mark
A p-n junction diode cannot be used:
Answer
  1. For increasing the amplitude of an AC signal
Explanation:
To increase the amplitude of an AC signal, transistors are used. p-n junction diodes can be used as rectifiers and in photo-diode and LED.
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Question 1211 Mark
To get an output Y=1 from the circuit above, the input must be:
Answer
  1. A-1 B-0 C-1
Explanation:
Logic gate OR is used for addition of the input signals and Logic gate AND is used for multiplication of the input signals. Hence, here inputs A = 1, B = 0 and C = 1 will yield the output Y = 1.
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Question 1221 Mark
A hole diffuses from the p-side to the n-side in a p-n junction. This means that.
Answer
  1. A bond is broken on the n-side and the electron freed from the bond jumps to a broken bond on the p-side to complete it.
Explanation:
A hole diffuses from the p side to the n side in a p−n junction; that is, an electron moves from the n side to the p side. This implies that a bond is broken on the n side. As the electron travels towards the p side, which is rich in holes, it combines with a hole. A hole is created because of the deficiency of one electron. So, when an electron combines with a hole, it completes that bond.
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Question 1231 Mark
In the Boolean algebra, the following one is wrong:
Answer
  1. 0 + 0 = 1
Explanation:
In the Boolean algebra, binary addition is given as:
1 + 0 = 1
0 + 1= 1
1 + 1 = 1
Hence, 0 + 0 =1 is wrong.
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Question 1241 Mark
In the Boolean algebra, the following one is wrong:
Answer
  1. 1.1 = 0
Explanation:
In the Boolean algebra,
1.0 = 0
0.1 = 0
1.1 = 1
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Question 1251 Mark
The cause of the potential barrier in a p-n diode is:
Answer
  1. Concentration of positive and negative charges near the junction.
Explanation:
During the formation of a junction diode, holes from p- region diffuse into n-region and electrons from n-region diffuse into p-region.
In both cases, when an electrons meets a hole, they cancel the effect at each other and as a result, a thin layer at the junction becomes free from any of charges carriers. This is called depletion layer.
There is a potential gradient in the depletion layer, negative on the p-side, and positive on the n-side.
The potential difference thus developed across the junction is called potential barrier.
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Question 1261 Mark
The load voltage is approximately constant when a zener diode is:
Answer
  1. Operating in the breakdown region
Explanation:
The zener voltage will be a constant only when it is operating in the breakdown region.
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Question 1271 Mark
The energy band gap is maximum in:
Answer
  1. Insulators
Explanation:
In insulators, the electrons are tightly bound with the nucleus hence, at room temperature thermal energy is not enough to push the electrons into conduction band and hence, no electrons are available for conduction.
The energy required for electron to escape out from orbit and to over come the energy gap is thus of the order of 6 eV, while for semiconductors and conductors it is (of the order of) 1 eV and 0 respectively.
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Question 1281 Mark
The breakdown in a reverse biased p-n junction diode is more likely to occur due to.
Answer
  1. Large velocity of the minority charge if the doping concentration is small.
Explanation:
When it comes to he breakdown in a reverse biased PN junction diode, it will probably happen only because of the accumulation of the higher charge at the biased region and large velocity of the minority charge if the doping concentration is small. This is the main cause the breakdown.
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Question 1291 Mark
Identify the logic gate in figure.
Answer
  1. NOR
Explanation:
The symbol of circle shown in figure with OR gate indicates the NOT gate hence, given gate is NOR gate.
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Question 1301 Mark
In p-type semiconductors, holes are:
Answer
  1. Majority carriers
Explanation:
P-type semiconductors are those which have a p-type impurity. A p-type impurity is a material in which the atoms have only 3 Valence Electrons. When they are added to a pure semiconductor, each atom gets bonded with 3 of atoms of the semiconductor. Between the 4th atom of the semiconductor and the atom of the impurity, there is an empty space due to lack of an electron. This empty space is known as a hole. Because of a large existence of P-type material in a p-type semiconductor, it has more holes as compared to free electrons. Hence holes are majority carriers.
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Question 1311 Mark
The distinction between conductors, insulators and semiconductors is largely concerned with:
Answer
  1. Relative widths of their energy gaps
Explanation:
According to band theory, distinction between conductors, insulators and semiconductors is based on relative width of energy gaps between valence band and conduction band.
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Question 1331 Mark
Electric current is due to drift of electrons in:
Answer
  1. Metallic conductors
Explanation:
When an electric field is applied across the metallic conductors the randomly moving electrons are subjected to electrical forces along the direction of the field. Due to this field, the electrons do not give up their randomness of motion, but they will be shifting towards higher potential. That means the electrons will drift towards higher potential along with their random motions.
In semiconductors, in addition to electrons, the travelling vacancies in the valence-band electron population (called 'holes'), act as mobile positive charges and are treated as charge carriers. Electrons and holes are the charge carriers in semiconductors.
Hence, electric current is due to drift of electrons in metallic conductors.
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Question 1341 Mark
The energy gap in a conductor at room temperature is ________ .
Answer
  1. Less than that in a insulator.
Explanation:
The energy band gap is the energy difference between 2 bands i.e. valence band and the conduction band. In case of conductors, energy band gap is very small almost overlapping whereas, in case of insulators, the band gap is ∼6 eV. So. band gap of conductors is less than insulators.
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Question 1351 Mark
Two identical p-ri junctions may be connected in series with a battery in three ways (figure). The potential difference across the two p-n. junctions are equal in:
Answer
  1. Circuit 2 and circuit 3.
Explanation:
In circuit 1, one diode is forward biassed and the other diode is reverse biassed. The forward-biassed diode offers zero resistance (ideally) to the current flow, so it can be replaced by a short circuit. The voltage drop across the first diode will be zero. The second diode is reverse biassed, so it can be replaced by an open circuit; hence, the voltage drop across this diode will be maximum.
In circuit 2, both the diodes are forward biassed, so they can be replaced by short circuits; hence, the voltage drop across both of them will be minimum and equal.
In circuit 3, both the diodes are reverse biassed, so both can be replaced by open circuits; hence, the voltage drop across both of them will be maximum and equal.
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Question 1361 Mark
In a p-n junction with open ends:
Answer
  1. Holes and conduction electrons systematically go from the p-side to the n-side and from the n side to the p-side respectively.
  2. There is no net charge transfer between the two sides.
  3. There is a constant electric field near the junction.
Explanation:
Because of the difference in the concentration of charge carriers in the p−n junction, holes from the p side move to the n side and electrons from the n side move to the p side. This motion of charge carriers gives rise to diffusion current.
Because of this, a negative space charge region is formed in the p region and a positive space region is formed in the n region. This sets up an electric field across the junction. Thus, there is a constant electric field near the junction.
This electric field further opposes the diffusion of majority charge carriers across the junction. As a result, an electron from the p region starts moving to the n region and a hole from the n region starts moving to the p region. This sets up drift current. Thus, there is a systematic flow of charge carriers across the junction. Also, there is no net charge transfer between the two sides.
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Question 1371 Mark
When an impurity is doped into an intrinsic semiconductor, the conductivity of the semiconductor:
Answer
  1. Increases..
Explanation:
When an impurity (either a p-type atom or an n-type atom) is doped into an intrinsic semiconductor, it increases the number of charge carriers in the intrinsic semiconductor. As conductivity is directly related to the number of charge carriers, the conductivity of a semiconductor increases with doping.
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Question 1381 Mark
For a common base amplifier, the values of resistance gain and voltage gain are 3000 and 2800 respectively. The current gain will be:
Answer
  1. 0.93
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Question 1391 Mark
Number of electrons in the valence shell of a semiconductor is:
Answer
  1. 4
Explanation:
The valency of semiconductor (Ge or Si) is four, hence it has 4 valence electrons in the outermost orbit of the Ge or Si-atom
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Question 1401 Mark
Holes are created when:
Answer
  1. A co-valent bond is broken due to thermal energy, the removal of one electron leaves a vacancy.
Explanation:
Holes are created when a co-valent bond is broken due to thermal energy. The removal of one electron leaves a vacancy known as a hole.
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Question 1411 Mark
In an n-type semiconductor, donor valence band is:
Answer
  1. Close to the conduction band of the host crystal.
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Question 1421 Mark
Which among the following is an example of a semiconductor?
Answer
  1. Cuprous oxide
Explanation:
Iron, Copper, Aluminium are metals and are therefore conductors whereas Cuprous oxide is a semiconductor.
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Question 1431 Mark
Optoelectronic devices work on:
Answer
  1. Both A and B
Explanation:
Optoelectronic devices and components are those electronic devices that operate on both light and electrical currents. This can include electrically driven light sources such as laser diodes and light-emitting diodes, components for converting light to an electrical current such as solar and photovoltaic cells and devices that can electronically control the propagation of light.
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Question 1441 Mark
The main cause of Zener breakdown is:
Answer
  1. High doping.
Explanation:
Zener breakdown occurs in heavily doped p-n junctions. The heavy doping makes the depletion layer extremely thin. So that, carriers cannot accelerate enough to cause ionization. Thus, current will increase in reverse bias only due to reverse breakdown voltage.
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Question 1451 Mark
The diffusion current in a p-n junction is:
Answer
  1. From the p-side to the n-side
Explanation:
Holes from p-type diffuse into the n-type and electrons from n-type diffuse into the p-type due to concentration gradient to form a depletion region which results in the rise of diffusion current flowing from p to n side.
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Question 1461 Mark
Zener-diode is used in:
Answer
  1. Volatge regulation
Explanation:
 A voltage regulator circuit can be designed using a zener diode to maintain a constant DC output voltage across the load in spite of variations in the input voltage or changes in the load current.
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Question 1471 Mark
When a hole is produced in P-type semiconductor, there is:
Answer
  1. Missing electron in valence band
Explanation:
A hole is not itself a physical quantity but a missing electron in valence band. An electron from adjacent site jumps to fill this hole and thus creates a hole at its former site. So it seems as if the hole itself has moved.
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Question 1491 Mark
In positive logic, the logic state 1 corresponds to:
Answer
  1. Higher voltage level
Explanation:
In digital logic, higher voltage is defined as logic state '1' and lower voltage is defined as logic state '0'. The higher voltage need not necessarily be positive. For example, it is possible that state '0' is defined as −10 V and state '1' is defined as −5 V.
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Question 1501 Mark
A semi conductor device with both active and passive electronic elements diffused into a silicon water to form a functional circuit is called.
Answer
  1. Integrated circuit
Explanation:
Integrated circuits or I.C's are those semi-conductor device with both active and passive electronic elements diffused into a silicon water to form a functional circuit.
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Question 1511 Mark
A semiconductor device is connected in a series circuit with a battery and a resistance. A current is found to pass through the circuit. If the polarity of the battery is reversed, the current drops to almost zero. The device may be a/ an?
Answer
  1. P-n junction diode.
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Question 1521 Mark
Which of the following devices can be used as a square law device for modulation.
Answer
  1. p-n junction diode near threshold voltage.
Explanation:
p−n junction diode near threshold voltage is used as a square law device for modulation.
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Question 1531 Mark
In a semiconductor:
Answer
  1. There are no free electrons at 0K.
  1. The number of free electrons increases with temperature.
  2. The number of free electrons is less than that in a conductor.
Explanation:
In semiconductors, the valence band is full at 0K, but the conduction band is empty. So, no free electron is available for conduction at 0K.
As the temperature increases, covalent bonds that provide free charge carriers for conduction in a semiconductor break.
As the conduction band in metals is already partially filled at 0K, many free electrons below the Fermi level acquire energy from an external source or temperature, jump to the conduction band and start behaving like free electrons. Hence, metals contain more free electrons than semiconductors.
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Question 1541 Mark
Which of the following is an example of a direct band gap intrinsic semiconductor?
Answer
  1. Gallium Arsenide
Explanation:
Direct Band gap: Defined when maximum energy in the valence band and minimum energy in the conduction band occurs at the same values of the crystal momentum i.e, a direct transition of electrons from valence to conduction band takes place.
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Question 1561 Mark
LEDs have the following advantages over conventional incandescent low power lamps: 
Answer
  1. All of the above
Explanation:
LEDs have longer life as compared to incandescent lamps. LED require low operational voltage and less power as compared to incandescent lamps. LEDs also have fast on-off switching capabilities.
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Question 1571 Mark
Which of the following cannot be used in electronic devices?
Answer
  1. Quasicrystals.
Explanation:
Aluminum gallium arsenide, indium gallium arsenide, and gallium arsenide are used in Laser diodes, LEDs, whereas Quasicrystals have poor heat conductivity which makes them good insulators, so not used in electronic devices.
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Question 1581 Mark
he forbidden gap for pure silicon at room temperature is .......................... eV.
Answer
  1. 1.1
Explanation:
The forbidden gap or band gap for pure Si is 1.1 eV.
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Question 1591 Mark
LED is a p-n junction diode which is:
Answer
  1. Forward biased.
Explanation:
An LED is a light emitting diode. The LED emits light when it is forward biased and it emits no light when it is reverse biased. The intensity of light is proportional to the square of the current flowing through the device.
When a junction diode is forward biased, energy is released at the junction due to recombination of electrons and holes. In the junction diode made of gallium arsenide or indium phosphide, the energy is released in visible region. Thus, light is emitted form the diode and hence the name 'light emitting diode'.
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Question 1611 Mark
In Boolean algebra A.B=Y implies the:
Answer
  1. Y exists when both A and B exist but not when only A or B exists
Explanation:
In Boolean algebra A.B = Y implies that Y exists when both A and B exist but not when only A or B exists.
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Question 1621 Mark
Zener diode acts as a/an:
Answer
  1. Regulator
Explanation:
Zener diode is used to supply constant voltage in voltage regulator circuit.
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Question 1631 Mark
In the circuit shown in Fig., if the diode forward voltage drop is $0.3V,$ the voltage difference between $A$ and $B$ is:
Answer
If $V$ is the potential difference between $A$ and $B,$ then according to the questions and using Kirchhoff’s law,
we have $V - 0.3 = [(5+ 5)10^3] \times (0.2 \times 1(10^{-3}))$
$\Rightarrow V - 0.3 = [(5 + 5)10^3] \times (0.2 \times 10^{-3})$
$\Rightarrow V - 0.3 = 10 \times 10^3 \times 0.2 \times 10^{-3} = 2$
$\Rightarrow V = 2 + 0.3 = 2.3V$
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Question 1641 Mark
The drift current in a p-ri junction is:
Answer
  1. From the n-side to the p-side.
Explanation:
After the diffusion of majority charge carriers across a p‒n junction, an electric field is set up because of the accumulation of immobile ions at the junction. These further oppose the motion of majority charge carriers across the junction. As a result, electrons from the p region start moving to the n region and holes from the n region start moving to the p region. This constitutes the drift current. As the direction of the current is opposite to the direction of the motion of the electrons, the direction of the drift current is from the n side to the p side.
In forward biasing, there is no movement of electrons from the p region to the n region and of holes from the n region to the p region. Hence, there is not drift current.
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Question 1651 Mark
Diffusion current in a p-n junction is greater than the drift current in magnitude:
Answer
  1. If the junction is forward-biased.
Explanation:
In the forward biassing of a p−n junction, the positive terminal of the battery is connected to the p side of the p−n junction and the negative terminal of the battery is connected to the n side of the p−n junction. As a result, electrons in the n side of the p−n junction are repelled by the negative terminal of the battery and move to the p side, where the positive terminal of the battery attracts the electrons. Similarly, holes from the p side of the p−n junction are repelled by the positive terminal of the battery and move to the nside, where the negative terminal of the battery attracts the holes. Thus, they give diffusion current across the p−n junction.
In case of reverse biassing, no conduction takes place across the junction because of the diffusion of majority carriers. Hence, there is no diffusion current.
If the junction is unbiased, then diffusion current is initially maximum. But at equilibrium, diffusion current becomes equal to drift current.
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Question 1671 Mark
If a small amount of antimony is added to germanium crystal:
Answer
  1. There will be more free electrons than holes in the semiconductor.
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Question 1681 Mark
In semiconductors, at room temperature:
Answer
  1. The valence band is completely filled and the conduction band is partially filled.
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Question 1691 Mark
In a p-n junction:
Answer
  1. New holes and conduction electrons are produced continuously throughout the material.
  1. Holes and conduction electrons recombine continuously throughout the material except in the depletion region.
Explanation:
In a p‒n junction diode, diffusion current flows because of the diffusion of holes from the p side to the n side and of electrons from the n side to the p side. The current flowing in the diode due to the diffusion of charge carriers across the junction is called the diffusion current. The current flowing in the diode due to the movement of minority carriers across the junction due to their thermal energy is called the drift current. In an unbiased diode, the net current flowing across the junction is zero due to the cancellation of the drift current by the diffusion current. For the flow of diffusion and drift currents, holes and electrons are produced continuously throughout the material. When a hole crosses the junction, it combines with an electron on the n side. As the depletion region is devoid of free charge carriers, this recombination never takes place inside the depletion region.
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Question 1701 Mark
AND gate:
Answer
  1. It is equivalent to series switching circuit.
Explanation:
AND gate is only active when both the inputs are high same as series switching circuit which is active only when both switches are closed.
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Question 1711 Mark
A semiconductor is a material with a small but non-zero band gap that behaves as an insulator at absolute zero but allows thermal excitation of electrons into its ____________ at temperatures that are below its melting point.
Answer
  1. Conduction band
Explanation:
The band gap in case of semiconductors is of order 3−4 eV. At absolute zero, the valence band is filled and conduction band is empty, so it behaves as an insulator. As the temperature is raised, electrons in the valence band gain sufficient energy to overcome the band gap and jump to the conduction band.
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Question 1721 Mark
LCD stands for:
Answer
  1. Liquid Crystal Display
    Explanation:
    LCD stands for "Liquid Crystal Display".
LCD is a special thin flat panel that can let light go through it, or can block the light. (Unlike an LED it does not produce its own light).
The panel is made up of several blocks, and each block can be in any shape. Each block is filled with liquid crystals that can be made clear or solid, by changing the electric current to that block.
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Question 1731 Mark
Diode can work as:
Answer
  1. Rectifier
Explanation:
Diode can work as rectifier, While converting AC voltage to DC voltage, we use 4 diodes in the form of wheat stone bridge,It effectively works as rectifier.
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Question 1741 Mark
For one electron vacancy,
Answer
  1. 1 hole is created
Explanation:
For one electron vacancy, an empty space or void is created. In order to fill that empty space, a charge carrier with a charge equal in magnitude but opposite polarity should occupy that space in order to maintain electrical neutrality. Such a charge particle is called a hole.
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Question 1751 Mark
In Fig $,Vo$ is the potential barrier across a $p-n$ junction, when no battery is connected across the junction :
Answer
$3$ corresponds to forward bias of junction and $1$ corresponds to reverse bias of junction.
Key concept :
$P-N$ Junction Diode:When a $P-$ type semiconductor is suitably joined to an $N-$ type semiconductor, then resulting arrangement is called $P-N$ junction or $P-N$ junction diode.
  1. Depletion region : On account of difference in concentration of charge carrier in the two sections of $P-N$ junction, the electrons from $N-$ region diffuse through the junction into $P-$ region and the hole from P region diffuse into $N-$ region.
Due to diffusion, neutrality of both $N$ and $P-$ type semiconductor is disturbed, a layer of negative charged ions appear near the junction in the $P-$ crystal and a layer of positive ions, appears near the junction in $N-$ crystal. This layer is called depletion layer.
  • The thickness of depletion layer is $1$ miscron $= 10^{-6}m.$
  • Width of depletion $\text{layer}\propto\frac{1}{\text{Dopping}}$.
  • Depletion is directly proportional to temperature.
  • The $P-N$ junction diode is equivalent to capacitor in which the depletion layer acts as a dielectric.
  1. Potential barrier : The potential difference created across the $P-N$ junction due to the diffusion of electron and holes is called potential barrier.
For $Ge, V_B = 0.3V$ and for silicon $V_B = 0.7V$
On the average the potential barrier in $P-N$ juction is $\sim0.5V$ and the width of depletion region $\approx 10^{-6}m$.
So the barrier electric field $\text{E}=\frac{\text{V}}{\text{d}}=\frac{0.5}{10^{-6}}=5\times10^{5}\text{V/m}$
Height of potential barrier is decreases when $p-n$ junction is forward biased, it opposes the potential barrier junction, when $p-n$ junction is reverse biased, it supports the potential barrier junction, resulting increase in potential barrier across the junction. 
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Question 1761 Mark
When semiconductor is doped half with trivalent and half with pentavalent impurities, junction formed is known as:
Answer
  1. pn junction
Explanation:
As pentavalent impurities contribute or donate electrons to the semiconductor, these are called donor impurities and similarly as these impurities contribute negative charge carriers in the semiconductor this we refer as n - type impurities. The semiconductor doped with n - type impurities is called n-type semiconductor.
Since trivalent impurities contribute excess holes to semiconductor crystal, and these holes can accept electrons, these impurities are referred as acceptor impurities. As the holes virtually carry positive charge, the said impurities are referred as positive - type or p - type impurities and the semiconductor with p type impurities is called p-type semiconductor.
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Question 1771 Mark
A strip of copper and another of germanium are cooled from room temperature to 80K. The resistance of:
Answer
  1. Copper strip decreases and that of germanium increases.
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Question 1781 Mark
Energy gaps between the highest band and the lowest empty bands in elements A, B, C and D are 0,70,530 and 90 kJmol−1. Then,
Answer
  1. All are correct conclusion about elements A, B, C and D
Explanation:
Energy gaps between the highest band and the lowest empty bands is lowest in metals, moderate in semi conductors and very high in insulators. This suggests us that:
Element A must be a metal, element C must be an insulator and element B and D can be semiconductors.
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Question 1791 Mark
Let $n_p$ and $n_e$ be the number of holes and conduction electrons in an intrinsic semiconductor.
Answer
As the intrinsic semiconductor is free from all impurities, the number of electrons is equal to the number of holes.
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Question 1801 Mark
The energy gap in case of which of the following is less than 3eV?
Answer
  1. Germanium
Explanation:
Energy gap of most of the semiconductors is nearly 1.1eV which is less than 3eV.
As we know germanium is a semiconductor and its energy gap is 0.67eV. Thus germanium is the right answer.
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Question 1811 Mark
The vacancy created due to the absence of an electron in the valence band of a semiconductor is called a _________ .
Answer
  1. Hole
Explanation:
Whenever an electron jumps from a valence band to conduction band, an equal and opposite charge is left behind in the place of an electron. This is called a hole.
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Question 1821 Mark
A hole is:
Answer
  1. An unfilled covalent bond.
Explanation:
When the covalent bond breaks, electrons are freed from atom. The departure of electron from valence band creates vacancy in bond, this vacancy is known as hole. Hence, a hole is an unfilled covalent bond.
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Question 1831 Mark
What happens during regulation action of a Zener diode?
Answer
  1. The current through the series Resistance $(R_s)$ changes.
  2. The resistance offered by the Zener changes.
  3. Symbolically zener diode represents like this:
    In the forward bias, the zener diode acts as an ordinary diode. It can be used as a voltage regulator.

A zener diode when reverse biases offers constant voltage drop across in terminals as unregulated voltage is applied across circuit to regulate. Then during regulation action of a Zener diode, the current through the series resistance $R_s$ changes and resistance offered by the Zener changes. The current through the Zener changes but the voltage across the Zener remains constant.
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Question 1851 Mark
The energy band gap (distance between the conduction band and valence band) in conductor is.
Answer
  1. $0$
Explanation:
In conductors, the valence band and conduction band overlap each other or have the extremely small energy gap between them approximately equal to zero.
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Question 1871 Mark
The mobility of free electrons is greater than that of free holes because:
Answer
  1. They require low energy to continue their motion.
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Question 1881 Mark
For detecting the light_______________.
Answer
  1. The photodiode has to be reversed biased.
Explanation:
Photo diode is used to detect light.
In reverse biased condition, the width of depletion region increases as the the applied reverse bias voltage increases across the diode. So, by applying a larger voltage, more of the incident photons are converted to electric current thereby increasing the efficiency.
In forward biased condition, the width of depletion region decreases so only a small portion of the incident photons get converted to electric current and hence the efficiency is less.
Hence photo diode in reverse biased condition detects light.
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Question 1891 Mark
A semiconducting device is connected in a series circuit with a battery and a resistance. A current is found to pass through the circuit. If the polarity of the battery is reversed, the current drops to almost zero. the device may be:
Answer
  1. A p-n junction.
Explanation:
As a p−n junction allows the flow of current in forward bias and stops the current in reverse bias (almost negligible reverse leakage current flows in the reverse-biassed p−njunction), the device should be a p−n junction. Other options are examples of semiconductors that allow moderate current to flow and that do not have any effect of changing the polarity of the battery.
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Question 1901 Mark
NOR gate is the series combination of:
Answer
  1. OR gate followed by NOT gate.
Explanation:
Truth table of NOR is complement of OR. That's why NOR is combination of OR gate followed by NOT gate.
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Question 1921 Mark
What is the order of magnitude of the resistance of a dry human body?
Answer
It is known that the resistance of a dry human body is $10k\Omega = 10^4\Omega .$
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Question 1931 Mark
The battery connections required to forward bias a pn junction are ____________:
Answer
  1. +ve terminal to p and -ve terminal to n
Explanation:
To forward bias the p-n junction, the p side is made more positive, so that it is "downhill" for electron motion across the junction. An electron can move across the junction and fill a vacancy or "hole" near the junction. It can then move from vacancy to vacancy leftward toward the positive terminal, which could be described as the hole moving right. The conduction direction for electrons in the diagram is right to left, and the upward direction represents increasing electron energy.
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Question 1941 Mark
A 220 V A.C. supply is connected between points A and B (Fig.). What will be the potential difference V across the capacitor?
Answer
  1. $220\sqrt{2}\text{V}.$
Solution:
Key concept: Half wave rectifier: When the P-N junction diode rectifies half of the ac wave, it is called half wave rectifier.

  1. During positive half cycle,
Diode → Forward biased
Output signal → obtained
  1. During negative half cycle,
Diode → reverse biased
Output signal → not obtained
  1. Output voltage is obtained across the load resistance RL. It is not constant but pulsating (mixture of ac and dc) in nature.
  2. Average output in one cycle
$\text{I}_\text{dc}=\frac{\text{I}_0}{\pi}\text{ and }\text{V}_\text{dc}=\frac{\text{V}_0}{\pi};\text{I}_0=\frac{\text{V}_0}{\text{r}_\text{f}+\text{R}_\text{I}}$
(rf = forward biased resistance)
  1. r.m.s. output: $\text{I}_\text{rms}=\frac{\text{I}_0}{2},\text{V}_\text{rms}=\frac{\text{V}_0}{2}$
As p-n junction diode will consuct during positive half cycle only, during negative half cycle diode is reverse biased. During this diode will not give any output. So, potential difference across capacitor C = peak voltage of the given AC voltage
$=\text{V}_0=\text{V}_\text{rms}\sqrt{2}=220\sqrt{2}\text{V}$
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Question 1951 Mark
Zener diode works on:
Answer
  1. Reverse bias
Explanation:
We know that zener diode works on the reverse bias. When the reverse bias is equal to the break-down voltage, the voltage across the zener remains almost constant and the current increases rapidly.
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Question 1961 Mark
Which logic gate produces LOW output when any of the inputs is HIGH?
Answer
  1. NOR
Explanation:
The truth table for NOR gate is shown above which suggests that NOR gate is the logic gate which produces low output when any of the inputs is high.
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Question 1971 Mark
Which of the following logic gates is an universal gate?
Answer
  1. NOR
Explanation:
NAND gate is considered universal gate. As other gates can be formed from this gate.
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Question 1991 Mark
p-n junction diode acts as:
Answer
  1. non-ohmic resistance
Explanation:
We know that in the case of metallic conductors, the potential difference varies in direct proportion to the current flowing. The I−V graph of a ohmic conductor is a straight line. But, a p-n junction diode is not in according with Ohm's law. The current voltage characteristic curve of a p-n junction diode shows both forward bias as well as reverse bias characteristics as shown as in the graph.
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Question 2001 Mark
In the valance band, the current is due to:
Answer
  1. The presence of holes
Explanation:
In the valence band, current is only due to holes. In the conduction band, current is due to electrons.
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Question 2011 Mark
Zener diode is used for:
Answer
  1. Stabilisation
Explanation:
A zener diode is always operated in its reverse biased condition. A voltage regulator circuit can be designed using a zener diode to maintain a constant DC output voltage across the load in spite of variations in the input voltage or changes in the load current. The zener voltage regulator consists of a current limiting resistor RS​ connected in series with the input voltage VS​ with the zener diode connected in parallel with the load RL in this reverse biased condition.Hence we can say that ,zener diode is used for stabilization.
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Question 2031 Mark
The creation of voltage or electric current in a material upon exposure to light is termed as:
Answer
  1. Photo-voltaic effect
Explanation:
The generation of current or voltage in a material, when exposed to light is called photovoltaic effect.
The device which operates on this effect is called photo-voltaic device or solar cell. It is a p-n junction diode which converts solar energy into electrical energy.
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Question 2041 Mark
In physics, chemistry, and electronic engineering, _______________ is the lack of an electron at a position where one could exist in an atom or atomic lattice.
Answer
  1. An electron hole
Explanation:
A hole is an absence of an electron in a particular place in an atom. Although it is not a physical particle, a hole can be passed from atom to atom in a semiconductor material.
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Question 2051 Mark
Which of these is the best description of a Zener diode?
Answer
  1. It is a constant voltage device.
Explanation:
Zener diode is a p-n junction diode working in the breakdown region. It is used as a voltage regulator/stabilizer to provide a constant voltage from a source whose voltage may fluctuate over a wide range.
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Question 2061 Mark
In a semiconductor diode, the barrier potential offers opposition to:
Answer
  1. Majority carriers in both regions.
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Question 2071 Mark
Digital circuit can be made by repetitive use of this gate:
Answer
  1. NAND
Explanation:
NAND and NOR gates are the basic building blocks of the digital circuit which means that all other gates can be synthesized using NAND (or NOR) gate only.
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Question 2081 Mark
The expression of Y in the above circuit is:
Answer
  1. A+B+C+D
Explanation:
Here, to build the logic three OR gates are used hence, all the input signals will be added to each other. 
Hence, the boolean expression is: A+B+C+D = Y
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Question 2091 Mark
An electric field is applied to a semiconductor. Let the number of charge carriers be $n$ and the average drift speed be $v.$ If the temperature is increased,
Answer
As we increase the temperature, additional electron$‒$hole pairs are created in a semiconductor. As a result, the number of charge carriers increases.
Now, drift velocity $(v_d)$ is given by
$\text{vd}=\frac{-\text{eE}_\text{T}}{\text{m}}$
As the temperature increases, the relaxation time of charge carriers $(T)$ decreases. As a result, $v_d$ decreases.
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Question 2101 Mark
A pure semiconductor at absolute zero has:
Answer
At absolute zero temperature, in a pure semiconductor, all electrons occupy the valence band and no electrons are present in the conduction band. The forbidden gap energy $E_g$​ is large.
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Question 2111 Mark
The zone in a semiconductor diode where no free charge carriers exists is known as the:
Answer
  1. Depletion region
Explanation:
In depletion region negative charge carrier electrons are attached with their positive charge carrier holes. hence there is no free charge carriers exists.
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Question 2141 Mark
The current gain of a transistor in common base mode is 0.995. The current gain of the same transistor in common emitter mode is?
Answer
  1. 199
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MCQ 2151 Mark
The accepter impurity in following is -
  • A
    Arsenic
  • B
    Phosphorus
  • Indium
  • D
    Antimony
Answer
Correct option: C.
Indium
C
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